Chapter 10: Problem 49
In Exercises \(49-58\), use the given information about \(\theta\) to find the exact values of \- \(\sin (2 \theta)\) \- \(\cos (2 \theta)\) \- \(\tan (2 \theta)\) \(\sin \left(\frac{\theta}{2}\right)\) - \(\cos \left(\frac{\theta}{2}\right)\) - \(\tan \left(\frac{\theta}{2}\right)\) $$ \sin (\theta)=-\frac{7}{25} \text { where } \frac{3 \pi}{2}<\theta<2 \pi $$
Short Answer
Step by step solution
Determine the Quadrant
Calculate \(\cos(\theta)\)
Calculate \(\sin(2\theta)\)
Calculate \(\cos(2\theta)\)
Calculate \(\tan(2\theta)\)
Calculate \(\sin(\frac{\theta}{2})\)
Calculate \(\cos(\frac{\theta}{2})\)
Calculate \(\tan(\frac{\theta}{2})\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Double Angle Formulas
- \(\sin(2\theta) = 2\sin(\theta)\cos(\theta)\)
- \(\cos(2\theta) = \cos^2(\theta) - \sin^2(\theta)\)
- \(\tan(2\theta) = \frac{2\tan(\theta)}{1 - \tan^2(\theta)}\)
Half-Angle Identities
- \(\sin\left(\frac{\theta}{2}\right) = \pm\sqrt{\frac{1 - \cos(\theta)}{2}}\)
- \(\cos\left(\frac{\theta}{2}\right) = \pm\sqrt{\frac{1 + \cos(\theta)}{2}}\)
- \(\tan\left(\frac{\theta}{2}\right) = \frac{\sin(\theta)}{1 + \cos(\theta)}\)
Pythagorean Identity
Trigonometric Functions
- \(\sin(\theta)\) measures the opposite side over the hypotenuse in a right triangle.
- \(\cos(\theta)\) represents the adjacent side over the hypotenuse.
- \(\tan(\theta)\) is the ratio of \(\sin(\theta)\) to \(\cos(\theta)\).
Angle Quadrants
- First Quadrant: All functions are positive.
- Second Quadrant: Sine positive, cosine and tangent negative.
- Third Quadrant: Tangent positive, sine and cosine negative.
- Fourth Quadrant: Cosine positive, sine and tangent negative.