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In Exercises \(82-128\), verify the identity. Assume that all quantities are defined. $$ \frac{1}{1+\cos (\theta)}=\csc ^{2}(\theta)-\csc (\theta) \cot (\theta) $$

Short Answer

Expert verified
The identity is verified, both sides equal \( \frac{1-\cos(\theta)}{\sin^{2}(\theta)} \).

Step by step solution

01

Start With The Left Side

We start by simplifying the left side of the equation, which is \( \frac{1}{1+\cos(\theta)} \).
02

Transform Into Sine and Cosine

Recall that \( \csc(\theta) = \frac{1}{\sin(\theta)} \) and \( \cot(\theta) = \frac{\cos(\theta)}{\sin(\theta)} \). We need to demonstrate the right side as well.
03

Right Side in Terms of Sine and Cosine

The right side \( \csc^{2}(\theta) - \csc(\theta) \cot(\theta) \) can be rewritten using sine and cosine:- \( \csc^{2}(\theta) = \frac{1}{\sin^{2}(\theta)} \)- \( \csc(\theta) \cot(\theta) = \frac{\cos(\theta)}{\sin^{2}(\theta)} \)
04

Combine and Simplify Right Side

Combine the terms on the right side:\[\csc^{2}(\theta) - \csc(\theta) \cot(\theta) = \frac{1}{\sin^{2}(\theta)} - \frac{\cos(\theta)}{\sin^{2}(\theta)} = \frac{1-\cos(\theta)}{\sin^{2}(\theta)}\]
05

Convert Left Side

Re-writing \( \frac{1}{1+\cos(\theta)} \) using the identity \( \sin^{2}(\theta) = 1 - \cos^{2}(\theta) \), we need to show equivalence to \( \frac{1-\cos(\theta)}{\sin^{2}(\theta)} \). Multiply top and bottom by \( 1-\cos(\theta) \) to create:\[\frac{1}{1+\cos(\theta)} = \frac{1-\cos(\theta)}{(1+\cos(\theta))(1-\cos(\theta))} = \frac{1-\cos(\theta)}{\sin^{2}(\theta)}\]
06

Equivalence Confirmation

As both sides have been simplified to \( \frac{1-\cos(\theta)}{\sin^{2}(\theta)} \), the identity is verified.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Functions
Trigonometric functions are fundamental in the study of angles and their relationships with sides of triangles. The six basic trigonometric functions are sine, cosine, tangent, cosecant, secant, and cotangent. Each of these functions provides a unique way to relate an angle to the sides of a right triangle.
For instance, the sine function, denoted as \( \sin(\theta) \), computes the ratio of the length of the side opposite the angle \( \theta \) to the hypotenuse. Cosine, written as \( \cos(\theta) \), finds the ratio of the adjacent side to the hypotenuse.
  • Cosecant \( \csc(\theta) \) is the reciprocal of sine: \( \csc(\theta) = \frac{1}{\sin(\theta)} \).
  • Cotangent \( \cot(\theta) \) is the reciprocal of tangent: \( \cot(\theta) = \frac{1}{\tan(\theta)} = \frac{\cos(\theta)}{\sin(\theta)} \).
Understanding these reciprocal and quotient relationships is key when manipulating and proving trigonometric identities. The identities often require transforming expressions into different forms using these basic trigonometric relationships.
Sine and Cosine Transformations
Transforming trigonometric expressions involving sine and cosine is crucial in verifying identities. In this context, transformation refers to rewriting functions in terms of other functions to simplify or solve equations. For instance, expressing \( \csc(\theta) \) and \( \cot(\theta) \) in terms of sine and cosine facilitates easier computation.
When verifying identities, understanding these transformations lets us see the equivalency between different forms. This exercise exemplifies this by converting \( \csc^{2}(\theta) - \csc(\theta) \cot(\theta) \) into terms that use sine and cosine alone.
  • The expression \( \csc^{2}(\theta) = \frac{1}{\sin^{2}(\theta)} \) shows its relationship to sine.
  • Similarly, \( \csc(\theta) \cdot \cot(\theta) = \frac{\cos(\theta)}{\sin^{2}(\theta)} \) connects it back to sine and cosine.
These transformations are fundamental in deriving equivalences and proving more intricate identities.
Simplifying Expressions
Simplifying expressions in trigonometry often involves transforming complex expressions into more manageable ones using identities and algebraic manipulation. The goal is to rewrite expressions so they are easier to understand or solve. In the given exercise, simplification is a key step.
Here, the expression \( \frac{1}{1 + \cos(\theta)} \) was transformed by multiplying the numerator and denominator by \( 1 - \cos(\theta) \) to achieve \( \frac{1 - \cos(\theta)}{(1 + \cos(\theta))(1 - \cos(\theta))} \). This manipulation relies on the identity \( \sin^{2}(\theta) = 1 - \cos^{2}(\theta) \).
  • Using identities helps break down expressions into familiar or simpler forms.
  • This often involves multiplying or dividing by a strategic term to reveal a recognizable form.
Ultimately, mastering these simplification techniques enhances one's ability to work flexibly with trigonometric expressions and solve complex problems.

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Most popular questions from this chapter

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Assume that the range of arcsecant is \(\left[0, \frac{\pi}{2}\right) \cup\left[\pi, \frac{3 \pi}{2}\right)\) and that the range of arccosecant is \(\left(0, \frac{\pi}{2}\right] \cup\left(\pi, \frac{3 \pi}{2}\right]\) when finding the exact value. \(\operatorname{arcsec}\left(\sec \left(\frac{11 \pi}{12}\right)\right)\)

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