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For the following exercises, find the magnitude and direction of the vector, \(0 \leq \theta<2 \pi\). Given \(u=\langle- 1,6\rangle\) and \( v=\langle 6,-1\rangle,\) calculate \(u \cdot v\).

Short Answer

Expert verified
The dot product of vectors \(u\) and \(v\) is \(-12\).

Step by step solution

01

Understand the Dot Product Formula

The dot product (or scalar product) of two vectors \(\mathbf{a} = \langle a_1, a_2 \rangle\) and \(\mathbf{b} = \langle b_1, b_2 \rangle\) is given by the formula: \(a_1 \cdot b_1 + a_2 \cdot b_2\). We will use this formula to calculate the dot product of vectors \(u\) and \(v\).
02

Identify Components of Given Vectors

Vector \(u\) is \(\langle -1, 6 \rangle\) and vector \(v\) is \(\langle 6, -1 \rangle\). Hence, the components are \(u_1 = -1\), \(u_2 = 6\), \(v_1 = 6\), and \(v_2 = -1\).
03

Substitute the Components into the Dot Product Formula

Use the components identified in the previous step to substitute into the dot product formula: \((-1) \cdot 6 + 6 \cdot (-1)\).
04

Perform the Calculation

Calculate the dot product: \(-1 \times 6 = -6\) and \(6 \times -1 = -6\). Thus, the dot product is \(-6 + (-6) = -12\).
05

Interpret the Result

The dot product of the vectors \(u\) and \(v\) is \(-12\). This scalar quantity indicates the cosine of the angle between the vectors when considered with their magnitudes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dot Product
The dot product, also known as the scalar product, is a fundamental operation in vector calculus. It combines two vectors and results in a scalar quantity. Given two vectors \( \mathbf{a} = \langle a_1, a_2 \rangle \) and \( \mathbf{b} = \langle b_1, b_2 \rangle \), the dot product is calculated using:
  • \( a_1 \cdot b_1 + a_2 \cdot b_2 \)
In simpler terms, you multiply the corresponding components of each vector and then sum them up.
For example, with vectors \( u = \langle -1, 6 \rangle \) and \( v = \langle 6, -1 \rangle \), the calculation is:
  • \( (-1) \cdot 6 + 6 \cdot (-1) = -6 - 6 = -12 \)
The negative dot product suggests the vectors are not pointing in the same direction. It can also imply either a 90-degree angle when it’s zero, an acute angle when positive, or an obtuse angle when negative.
Magnitude
The magnitude of a vector can be thought of as its length or size in space. It's a measure of how long the vector is regardless of its direction. For a vector \( \mathbf{a} = \langle a_1, a_2 \rangle \), the magnitude is given by:
  • \( |\mathbf{a}| = \sqrt{a_1^2 + a_2^2} \)
Let's consider vectors \( u = \langle -1, 6 \rangle \) and \( v = \langle 6, -1 \rangle \). For each vector:
  • Magnitude of \( u = \sqrt{(-1)^2 + 6^2} = \sqrt{1 + 36} = \sqrt{37} \)
  • Magnitude of \( v = \sqrt{6^2 + (-1)^2} = \sqrt{36 + 1} = \sqrt{37} \)
The magnitude helps determine how far the vector extends from the origin in a 2D plane.
Vector Direction
Vectors possess both magnitude and direction. The direction of a vector gives information about where it points in space. It is commonly represented using an angle \( \theta \). To find the direction of a vector \( \mathbf{a} = \langle a_1, a_2 \rangle \), you can use trigonometric functions:
  • \( \theta = \tan^{-1}\left(\frac{a_2}{a_1}\right) \)
For vector \( u = \langle -1, 6 \rangle \), the direction would be determined by:
  • \( \theta = \tan^{-1}\left(\frac{6}{-1}\right) \)
This calculation would yield an angle indicating that the vector points primarily in the positive y-direction with a negative x-component.To properly interpret this angle, it's crucial to know that the calculator may give a reference angle that needs adjustment based on the vector's quadrant.
Scalar Product
The scalar product refers to another name for the dot product. It is called scalar because, unlike a cross product which results in a vector, the outcome of a dot product is a single number – a scalar. This product provides insight into the angle between two vectors as well as their parallelity.
  • A dot product of zero indicates perpendicular vectors.
  • A positive dot product implies the vectors tend to point in the same direction.
  • A negative dot product, like \(-12\) from vectors \( u \) and \( v \), suggests the vectors point in somewhat opposite directions, forming an obtuse angle.
The scalar product is a powerful tool in various applications:
  • Calculating work done when force is applied at an angle
  • Finding projections in vector analysis
Understanding how to navigate these concepts can greatly enhance solving real-world physics and engineering problems.

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