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For the following exercises, solve exactly on \([0,2 \pi)\) $$ 2 \cos (3 \theta)=-\sqrt{2} $$

Short Answer

Expert verified
The solutions are \( \theta = \frac{\pi}{4}, \frac{7\pi}{4}, \frac{5\pi}{12}, \frac{11\pi}{12}, \frac{17\pi}{12}, \frac{23\pi}{12} \).

Step by step solution

01

Isolate the Cosine Function

To solve the equation, start by isolating the cosine function. Divide both sides of the equation by 2: \[ \cos(3\theta) = -\frac{\sqrt{2}}{2} \]
02

Identify Reference Angles

Find the angles \( \theta \) for which \( \cos(\theta) = -\frac{\sqrt{2}}{2} \). On the unit circle, the reference angles are \( \theta = \frac{3\pi}{4} \) and \( \theta = \frac{5\pi}{4} \).
03

Solve for Original Variable

Since the angle in the original problem is \( 3\theta \), set \( 3\theta = \frac{3\pi}{4} + 2k\pi \) and \( 3\theta = \frac{5\pi}{4} + 2k\pi \), where \( k \) is an integer to account for periodicity. Solve these for \( \theta \):\[ \theta = \frac{3\pi}{12} + \frac{2k\pi}{3} \]\[ \theta = \frac{5\pi}{12} + \frac{2k\pi}{3} \]
04

Find Solutions Within Given Interval

Find all solutions for \( \theta \) within the interval \([0, 2\pi)\). Substitute integer values for \( k \).For \( 3\theta = \frac{3\pi}{4} + 2k\pi \):- k = 0: \( \theta = \frac{\pi}{4} \)- k = 1: \( \theta = \frac{7\pi}{4} \)For \( 3\theta = \frac{5\pi}{4} + 2k\pi \):- k = 0: \( \theta = \frac{5\pi}{12} \)- k = 1: \( \theta = \frac{11\pi}{12} \) - k = 2: \( \theta = \frac{17\pi}{12} \)- k = 3: \( \theta = \frac{23\pi}{12} \)Collect all valid solutions within the interval \([0, 2\pi)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Circle
The unit circle is a fundamental concept in trigonometry and is instrumental in solving trigonometric equations. It is a circle with a radius of 1, centered at the origin of a coordinate plane. This means that any point on the unit circle satisfies the equation \(x^2 + y^2 = 1\). In trigonometry, the unit circle is used to define the trigonometric functions sine and cosine.

The unit circle helps visualize angles and their corresponding coordinates, allowing us to understand the periodic nature of trigonometric functions. For instance, when solving the equation \(\cos(3\theta) = -\frac{\sqrt{2}}{2}\), we use the unit circle to identify the angles where the cosine value matches \(-\frac{\sqrt{2}}{2}\). On the unit circle, this corresponds to two specific angles, \(\frac{3\pi}{4}\) and \(\frac{5\pi}{4}\), due to their positions in Quadrant II and III respectively, where cosine values are negative.
Cosine Function
The cosine function, often denoted as \(\cos(\theta)\), is a fundamental trigonometric function that relates the angle \(\theta\) to the x-coordinate of a point on the unit circle. The cosine of an angle is positive in Quadrants I and IV, and negative in Quadrants II and III. This understanding is critical when solving trigonometric equations.

For example, to solve \(2\cos(3\theta) = -\sqrt{2}\), the cosine function plays a crucial role. By isolating the cosine function, we obtain \(\cos(3\theta) = -\frac{\sqrt{2}}{2}\). This tells us we need to find the angles where the cosine value equals \(-\frac{\sqrt{2}}{2}\), which can be referenced using the unit circle. These reference angles, corresponding to the negative cosine value, guide us in determining the solutions for \(\theta\).

  • Cosine is even, meaning \( \cos(-\theta) = \cos(\theta) \).
  • Cosine's periodicity is \(2\pi\), which means \( \cos(\theta + 2k\pi) = \cos(\theta) \) for any integer \(k\).
Periodicity
Periodicity is the property of trigonometric functions to repeat their values at regular intervals. For the cosine function, this interval is \(2\pi\). This characteristic is particularly useful in finding multiple solutions to trigonometric equations within a specific interval.

When solving the equation \(\cos(3\theta) = -\frac{\sqrt{2}}{2}\), it's essential to recognize that the angle \(3\theta\) implies we need to consider the periodicity of cosine on a different scale. By solving \(3\theta = \frac{3\pi}{4} + 2k\pi\) and \(3\theta = \frac{5\pi}{4} + 2k\pi\), where \(k\) is an integer, we take advantage of periodicity. This allows us to find all the possible angles solutions that satisfy the initial equation.

  • Periodicity helps in predicting the cosine function's behavior at every complete cycle.
  • Recognizing the periodic nature helps solve equations in given intervals.
Reference Angles
Reference angles are fundamental in understanding trigonometric functions. They are the acute angles that a given angle makes with the x-axis. Understanding reference angles is crucial when working with trigonometric functions on the unit circle, especially when dealing with negative values.

For the cosine function, reference angles help identify trigonometric values in different quadrants. When solving \(\cos(3\theta) = -\frac{\sqrt{2}}{2}\), we look for reference angles on the unit circle where cosine equals \(-\frac{\sqrt{2}}{2}\).

  • These reference angles are typically in standard positions such as \(\frac{3\pi}{4}\) and \(\frac{5\pi}{4}\).
  • They help convert problems with negative outputs to more manageable forms.
  • In the context of this exercise, using reference angles allows us to find solutions within the required interval.

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