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For the following exercise, use the properties of logarithms to expand each logarithm as much as possible. Rewrite each expression as asum, difference, or product of logs. $$ \log \left(\frac{x^{15} y^{13}}{z^{19}}\right) $$

Short Answer

Expert verified
The expanded expression is \( 15\log(x) + 13\log(y) - 19\log(z) \).

Step by step solution

01

Apply the Quotient Rule

The first step is to use the quotient rule of logarithms, which states \( \log\left(\frac{a}{b}\right) = \log(a) - \log(b) \). Apply this to the expression: \[ \log\left(\frac{x^{15} y^{13}}{z^{19}}\right) = \log(x^{15} y^{13}) - \log(z^{19}) \]
02

Apply the Product Rule

Next, apply the product rule to \( \log(x^{15} y^{13}) \), which states \( \log(ab) = \log(a) + \log(b) \). This results in: \[ \log(x^{15} y^{13}) = \log(x^{15}) + \log(y^{13}) \] Now, substitute back into the expression from Step 1: \[ \log(x^{15}) + \log(y^{13}) - \log(z^{19}) \]
03

Apply the Power Rule

Apply the power rule of logarithms for each term, which states that \( \log(a^b) = b\log(a) \). Use this on each component:- For \( \log(x^{15}) \), apply power rule: \( 15\log(x) \).- For \( \log(y^{13}) \), apply power rule: \( 13\log(y) \).- For \( \log(z^{19}) \), apply power rule: \( 19\log(z) \).Substitute these into the previous expression:\[ 15\log(x) + 13\log(y) - 19\log(z) \]
04

Conclude the Expanded Expression

The final expanded expression using the properties of logarithms is: \[ 15\log(x) + 13\log(y) - 19\log(z) \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule
The quotient rule for logarithms is one of the fundamental properties that allow us to simplify logarithmic expressions by transforming division into subtraction. It states that if you have a logarithm of the quotient of two numbers, you can separate this into the difference of two logarithms. Mathematically, this is expressed as:
  • \( \log\left(\frac{a}{b}\right) = \log(a) - \log(b) \)
Imagine you have a complex logarithmic expression like \( \log\left(\frac{x^{15} y^{13}}{z^{19}}\right) \). Instead of dealing with it all at once, applying the quotient rule allows you to break it into two simpler parts:
  • \( \log(x^{15} y^{13}) \)
  • \( \log(z^{19}) \)
Now you have a subtraction of two logarithms. This transformation makes it much easier to further manipulate and expand the expression using other rules. This rule is particularly useful when dealing with complex fractions in logarithmic form.After applying the quotient rule, don't forget to consider the numerator as one entity if it involves multiple terms or variables, as in this case, \( x^{15} y^{13} \). This strategy sets the stage for using additional rules, such as the product rule.
Product Rule
The product rule of logarithms is another powerful tool used to break down complex expressions into more manageable pieces. It comes into play when you encounter a logarithm of a product of two or more numbers. The rule states that:
  • \( \log(ab) = \log(a) + \log(b) \)
Using this rule, you can take an expression like \( \log(x^{15} y^{13}) \) and expand it into a sum:
  • \( \log(x^{15}) + \log(y^{13}) \)
This simplification separates the complex terms, allowing each part to be further expanded or manipulated individually. This step-by-step breakdown helps in understanding the structure of the expression and paves the way for applying even more rules like the power rule.
By converting a product inside a logarithm to a sum of logarithms, you make the expression easier to handle and further dissect. This is particularly advantageous in calculus and algebra when solving equations or integrating functions.
Power Rule
The power rule of logarithms is essential when you need to deal with exponents within logarithmic expressions. This rule helps in handling powers by bringing them in front of the logarithm. The formula is:
  • \( \log(a^b) = b\log(a) \)
With this simple rule, you can take complex expressions like \( \log(x^{15}) \) or \( \log(y^{13}) \) and simplify them to:
  • \( 15\log(x) \)
  • \( 13\log(y) \)
This form makes calculations and further manipulations much more straightforward. Similarly, for \( \log(z^{19}) \), applying the power rule gives:
  • \( 19\log(z) \)
Once the power rule is applied to each term in an expanded logarithmic expression, the full decomposition is clear, as you see the role each variable's exponent plays in the resulting formula. This visualization is helpful in algebraic computations and calculus, offering insight into the function's behavior and simplifying problem-solving tasks.

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Most popular questions from this chapter

For the following exercises, enter the data from each table into a graphing calculator and graph the resulting scatter plots. Determine whether the data from the table could represent a function that is linear, exponential, or logarithmic. $$\begin{array}{|c|c|c|c|c|c|c|c|}\hline x & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {9} & {10}\\\ \hline f(x) & {2} & {4.079} & {5.296} & {6.159} & {6.828} & {7.375} & {7.838} & { 8.238} & { 8.592} & { 8.908 }\\\ \hline\end{array}$$

For the following exercises, refer to Table 4.29. $$\begin{array}{|c|c|c|c|c|c|c|c|}\hline x & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} \\ \hline f(x) & {7.5} & {6} & {5.2} & {4.3} & {3.9} & {3.1} & {2.9} \\ \hline\end{array}$$ Use the LOGarithm option of the REGression feature to find a logarithmic function of the form \(y=a+b \ln (x)\) that best fits the data in the table.

The intensity levels \(I\) of two earthquakes measured on a seismograph can be compared by the formula \(\log \frac{I}{I_{2}}=M_{1}-M_{2}\) where \(M\) is the magnitude given by the Richter Scale. In August \(2009,\) an earthquake of magnitude a magnitude of 6.1 hit Honshu, Japan. In March 2011, that same region experienced yet another, more devastating earthquake, this time with a magnitude of \(9.0 .[9]\) How many times greater was the intensity of the 2011 earthquake? Round to the nearest whole number.

For the following exercises, evaluate each expression using a calculator. Round to the nearest thousandth. $$ \ln (\sqrt{2}) $$

For the following exercises, use properties of logarithms to evaluate without using a calculator. $$ \log _{3}\left(\frac{1}{9}\right)-3 \log _{3}(3) $$

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