/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 174 For the following exercises, eva... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

For the following exercises, evaluate the natural logarithmic expression without using a calculator. $$ \ln \left(e^{-0.225}\right)-3 $$

Short Answer

Expert verified
The expression evaluates to -3.225.

Step by step solution

01

Simplify the Logarithmic Expression

Recall the property of logarithms that the natural logarithm and the exponential function are inverses. Therefore, if you have the expression \( \ln(e^x) \), it simplifies to \( x \). Apply this property to the term \( \ln(e^{-0.225}) \). It simplifies directly to \( -0.225 \).
02

Perform the Subtraction

Once you've simplified the logarithmic expression, the next step is to substitute it back into the original expression. Therefore, the expression becomes \( -0.225 - 3 \). Perform the subtraction: \( -0.225 - 3 = -3.225 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithm Properties
Understanding logarithm properties is essential when dealing with natural logarithms and simplifying expressions. One of the fundamental properties is that the natural logarithm, denoted as \( \ln \), is the inverse of the exponential function with the base \( e \). This essential property means that for any expression of the form \( \ln(e^x) \), the result simplifies directly to \( x \). This is because the natural log essentially "cancels out" with the exponential, returning the exponent itself. This powerful property allows us to simplify complex logarithmic expressions quickly and efficiently.Another key property is the logarithm rule which states \( \ln(ab) = \ln(a) + \ln(b) \) and \( \ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b) \). These rules are particularly useful when breaking down more complicated expressions involving multiplication or division of terms within a logarithm.
Exponential Functions
Exponential functions form a crucial part of mathematics, especially when dealing with natural logarithms. An exponential function is represented in the form \( e^x \), where \( e \) is approximately 2.71828. This constant \( e \) is one of the most important numbers in mathematics and is often used as the base for natural exponential functions.Exponential functions are unique due to their growth patterns and are inversely related to logarithmic functions. This inverse nature means that they cancel each other out, making one a mirror image of the other. For instance, the expression \( e^{\ln(x)} \) simplifies to \( x \), as the operations of taking a logarithm and exponentiating negate each other.Working with exponential functions involves recognizing how they can be transformed or combined. For instance:
  • If you have \( e^{a+b} \), it's equivalent to \( e^a \cdot e^b \).
  • The expression \( e^{x^2} \) represents an exponential growth based on the square of \( x \).
Simplifying Expressions
Simplifying expressions is all about reducing complex mathematical phrases into their simplest form. This process involves applying rules and properties to condense and clarify expressions. In the context of natural logarithms and exponential functions, simplification often relies on remembering inverses, such as \( \ln(e^x) = x \).For example, in the exercise provided, we used the property that \( \ln(e^{-0.225}) \) simplifies directly to \( -0.225 \). Once that step is completed, simplifying any remaining arithmetic, like subtraction, becomes straightforward. In this exercise, after simplifying the logarithmic part, what remains is basic arithmetic: performing \( -0.225 - 3 \), which equals \( -3.225 \).Simplification is all about making calculations easier. By breaking down a complicated expression into smaller, familiar parts, we can more easily understand and solve mathematical problems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For the following exercises, suppose log \(_{5}(6)=a\) and \(\log _{5}(11)=b\) . Use the change-of-base formula along with properties of logarithms to rewrite each expression in terms of \(a\) and \(b .\) Show the steps for solving. $$ \log _{11}\left(\frac{6}{11}\right) $$

For the following exercises, refer to Table 4.29. $$\begin{array}{|c|c|c|c|c|c|c|c|}\hline x & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} \\ \hline f(x) & {7.5} & {6} & {5.2} & {4.3} & {3.9} & {3.1} & {2.9} \\ \hline\end{array}$$ Use the logarithmic function to find the value of the function when \(x=10\).

For the following exercises, use this scenario: The population \(P\) of an endangered species habitat for wolves is modeled by the function \(P(x)=\frac{558}{1+54.8 e^{-0.462 x}},\) where \(x\) is given in years. Graph the population model to show the population over a span of 10 years.

The intensity levels \(I\) of two earthquakes measured on a seismograph can be compared by the formula \(\log \frac{I}{I_{2}}=M_{1}-M_{2}\) where \(M\) is the magnitude given by the Richter Scale. In August \(2009,\) an earthquake of magnitude a magnitude of 6.1 hit Honshu, Japan. In March 2011, that same region experienced yet another, more devastating earthquake, this time with a magnitude of \(9.0 .[9]\) How many times greater was the intensity of the 2011 earthquake? Round to the nearest whole number.

For the following exercises, refer to Table 4.28. $$\begin{array}{|c|c|c|c|c|c|c|}\hline x & {1} & {2} & {3} & {4} & {5} & {6} \\\ \hline f(x) & {5.1} & {6.3} & {7.3} & {7.7} & {8.1} & {8.6} \\\ \hline\end{array}$$ Graph the logarithmic equation on the scatter diagram.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.