/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 752 Find the unknown value. \(y\) ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the unknown value. \(y\) varies jointly with \(x\) and the cube root of \(z\) . If when \(x=2\) and \(z=27, \quad y=12,\) find \(y\) if \(x=5\) and \(z=8\)

Short Answer

Expert verified
The value of \( y \) is 20.

Step by step solution

01

Understand Joint Variation

When a variable \( y \) varies jointly with \( x \) and the cube root of \( z \), it means there exists a constant \( k \) such that \( y = k \cdot x \cdot \sqrt[3]{z} \).
02

Solve for the Constant k

Using the given values \( x = 2 \), \( z = 27 \), and \( y = 12 \), plug them into the equation: \( 12 = k \cdot 2 \cdot \sqrt[3]{27} \). Since \( \sqrt[3]{27} = 3 \), the equation becomes \( 12 = k \cdot 2 \cdot 3 \). Simplify this to find \( k = 2 \).
03

Write the Equation with k

Substitute \( k = 2 \) back into the joint variation equation to get \( y = 2 \cdot x \cdot \sqrt[3]{z} \).
04

Use New Values to Find y

With the new values \( x = 5 \) and \( z = 8 \), substitute into the equation: \( y = 2 \cdot 5 \cdot \sqrt[3]{8} \). Since \( \sqrt[3]{8} = 2 \), the equation simplifies to \( y = 2 \cdot 5 \cdot 2 \).
05

Calculate y

Carry out the multiplication: \( y = 20 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant of Variation
In problems involving joint variation, the constant of variation plays a crucial role in forming the relationship between variables. It is a constant value that helps link the variables together in a proportional relationship.

When we say that a variable "varies jointly" with other variables, it means that the variable is directly influenced by those variables, multiplied by some constant. Mathematically, this can be represented as:
  • \( y = k \cdot x \cdot \sqrt[3]{z} \)
Here, \( k \) is the constant of variation. It is a fixed number and does not change over the course of the problem.

To find this constant, you use known values from a problem. In the exercise, for example, we used \( x = 2 \), \( z = 27 \), and \( y = 12 \). By solving the equation \( 12 = k \cdot 2 \cdot 3 \), we found \( k = 2 \). This constant is then used in future calculations to determine unknown values of \( y \) for new values of \( x \) and \( z \).
Cube Root
The cube root is essential in understanding the operation done on \( z \) in the given problem. Calculating a cube root means finding a number that, when multiplied by itself three times, gives you the original number, \( z \).

For instance, \( \sqrt[3]{27} = 3 \) because 3 multiplied by itself three times (\( 3 \times 3 \times 3 \)) equals 27. Similarly, for \( \sqrt[3]{8} \), the result is 2 because 2 times itself three times (\( 2 \times 2 \times 2 \)) equals 8.

Understanding the cube root is pivotal since it is used to transform or process \( z \) in the equation \( y = k \cdot x \cdot \sqrt[3]{z} \). The function \( \sqrt[3]{z} \) modifies \( z \) as part of the joint variation, showing that \( y \) is not directly proportional to \( z \) itself, but rather to its cube root.
Jointly Proportional
In mathematics, jointly proportional describes a scenario where a variable depends on multiple other variables in a direct manner, meaning each variable in the relationship is multiplied together with a constant factor.

In the problem, the variable \( y \) varies jointly with \( x \) and the cube root of \( z \), represented as \( y = k \cdot x \cdot \sqrt[3]{z} \). This tells us that \( y \) increases or decreases together with \( x \) and \( \sqrt[3]{z} \).

To find a specific value of \( y \) given new inputs for \( x \) and \( z \), we continue using the fundamental equation derived from joint variation. For the new values, \( x = 5 \) and \( z = 8 \), along with the constant \( k \), we compute \( y \) by substituting them back to get:
  • \( y = 2 \cdot 5 \cdot \sqrt[3]{8} \)
This equation exemplifies how the concept of joint variation is applied to find \( y = 20 \), showing the relationship throughout the process. Joint variation problems provide insight into how multiple factors can simultaneously influence a singular outcome, and understanding it deepens one's knowledge of proportionality and dependence in mathematics.

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