Chapter 3: Problem 580
Find the inverse of the function and graph both the function and its inverse. \(f(x)=x^{2}+4 x, x \geq-2\)
Short Answer
Expert verified
Inverse: \(f^{-1}(x) = \frac{-4 + \sqrt{x + 4}}{2}\); graph both functions.
Step by step solution
01
Write Function as an Equation
Start with the function given: \[ f(x) = x^2 + 4x \] Replace \(f(x)\) with \(y\): \[ y = x^2 + 4x \]
02
Solve for x in Terms of y
Swap \(x\) and \(y\) in the equation to set up for finding the inverse:\[ x = y^2 + 4y \] We need to express \(y\) in terms of \(x\). First, move everything to one side:\[ y^2 + 4y - x = 0 \] This is a quadratic equation in \(y\).
03
Use the Quadratic Formula
Use the quadratic formula to solve for \(y\):\[ y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] In this equation:\(a = 1\), \(b = 4\), and \(c = -x\). So, we have:\[ y = \frac{-4 \pm \sqrt{16 + 4x}}{2} \]
04
Simplify the Expression for y
Since \(x \geq -2\) which makes the expression inside the square root non-negative, we use the positive root (to match the restriction of our original function). Simplifying gives:\[ y = \frac{-4 + \sqrt{x + 4}}{2} \] This is the inverse function \(f^{-1}(x)\).
05
Graph the Function and Its Inverse
Graph the original function \(f(x) = x^2 + 4x\) where \(x \geq -2\). This is a parabola opening upwards starting from the vertex at \((-2, -4)\).Then graph the inverse \(f^{-1}(x) = \frac{-4 + \sqrt{x + 4}}{2}\). This is a square root function shifted right by 4 and down by 2.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Functions
Quadratic functions are a type of polynomial function where the highest degree of the variable is squared, commonly written in the form \( ax^2 + bx + c \). In these functions:
- \(a\) is the coefficient of the squared term.
- \(b\) is the coefficient of the linear term.
- \(c\) is the constant term or y-intercept.
Graphing Functions
Graphing functions visually represents the relationship described by a function, offering an instant understanding of its behavior.To graph a quadratic function like \(f(x) = x^2 + 4x\) for \(x \geq -2\), you start by identifying its vertex, the turning point of the parabola. The formula for the vertex of a parabola \(y = ax^2 + bx + c\) is provided by \((-\frac{b}{2a}, f(-\frac{b}{2a}))\). For our function:
- \(x\)-coordinate of the vertex: \(-\frac{4}{2 \times 1} = -2\)
- \(y\)-coordinate: \(f(-2) = (-2)^2 + 4 \times (-2) = -4\)
Quadratic Formula
The quadratic formula is vital for solving quadratic equations of the form \(ax^2 + bx + c = 0\). It is expressed as:\[ y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula calculates the roots of any quadratic equation, which are the values of \(x\) for which the function equals zero. The term under the square root \((b^2 - 4ac)\) is called the discriminant. This discriminant determines:
- If \(b^2 - 4ac > 0\), the equation has two real and distinct solutions.
- If \(b^2 - 4ac = 0\), there is one real, repeated solution.
- If \(b^2 - 4ac < 0\), the solutions are complex and not real.