Chapter 3: Problem 391
For the following exercises, use the Factor Theorem to find all real zeros for the given polynomial function and one factor. $$ f(x)=2 x^{3}+3 x^{2}+x+6 ; \quad x+2 $$
Short Answer
Expert verified
The only real zero is \( x = -2 \).
Step by step solution
01
Understand the Problem
We are given a polynomial function \( f(x) = 2x^3 + 3x^2 + x + 6 \) and a factor \( x + 2 \). Our task is to find all real zeros of the polynomial using the Factor Theorem.
02
Apply the Factor Theorem
According to the Factor Theorem, \( x + 2 \) is a factor of \( f(x) \), then \( f(-2) = 0 \). We should first verify that \( -2 \) is indeed a root by substituting it into the function.
03
Substitute and Solve
Substitute \( x = -2 \) into the polynomial: \[f(-2) = 2(-2)^3 + 3(-2)^2 + (-2) + 6\]Calculate each term: \[2(-8) + 3(4) - 2 + 6 = -16 + 12 - 2 + 6 = 0 \]This confirms \( x = -2 \) is indeed a zero.
04
Perform Polynomial Division
To find other zeros, divide the polynomial \( f(x) \) by \( x+2 \). Use synthetic division:1. Coefficients: \( 2, 3, 1, 6 \)2. Divider: \( -2 \)Carry out synthetic division:- Bring down the 2.- Multiply by \(-2\) and add to the next coefficient.Remainder: \( 0 \). Resultant polynomial after division is: \( 2x^2 - x + 3 \).
05
Find Remaining Zeros
The division results in a quadratic \( 2x^2 - x + 3 \). Set it equal to zero and solve:\[2x^2 - x + 3 = 0\]Use the quadratic formula where \( a = 2 \), \( b = -1 \), \( c = 3 \):\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]Calculate the discriminant:\[b^2 - 4ac = (-1)^2 - 4(2)(3) = 1 - 24 = -23\]Since the discriminant is negative, the quadratic equation has no real roots.
06
Conclusion
The only real zero of the polynomial \( f(x) = 2x^3 + 3x^2 + x + 6 \) is \( x = -2 \), which we obtained earlier from the factor \( x+2 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Division
Polynomial division is a fundamental algebraic process that helps us break down complex polynomials into simpler parts. This process is similar to long division with numbers, but it involves variables.
When given a polynomial like the one in this exercise, dividing by a factor such as \( x + 2 \) allows us to simplify the original polynomial into smaller, more manageable pieces. In this scenario, we use "synthetic division," a shorthand method that simplifies the process when dividing by linear factors. It's crucial to write down all coefficients of the polynomial in sequence and methodically apply the division.
When given a polynomial like the one in this exercise, dividing by a factor such as \( x + 2 \) allows us to simplify the original polynomial into smaller, more manageable pieces. In this scenario, we use "synthetic division," a shorthand method that simplifies the process when dividing by linear factors. It's crucial to write down all coefficients of the polynomial in sequence and methodically apply the division.
- First, identify the coefficients of the polynomial.
- Use the corresponding value from the factor as the divisor.
- Process each term step-by-step, ensuring careful arithmetic to avoid mistakes.
Real Zeros
Real zeros of a polynomial are the values of \( x \) where the polynomial equals zero. These zeros may also be referred to as roots or solutions.
Finding the real zeros of a polynomial is often the final goal when solving polynomial equations, as these zeros represent the points where the graph of the polynomial crosses the x-axis.
Finding the real zeros of a polynomial is often the final goal when solving polynomial equations, as these zeros represent the points where the graph of the polynomial crosses the x-axis.
- Start by using any known factors and substituting corresponding zeros.
- The Factor Theorem is particularly useful as it guarantees that if \( (x + a) \) is a factor, then \( x = -a \) is a real zero.
Quadratic Formula
The quadratic formula is a robust tool for finding the roots of quadratic equations, typically expressed in the form of \( ax^2 + bx + c = 0 \).
In the current exercise, after performing polynomial division, we were left with a quadratic equation \( 2x^2 - x + 3 = 0 \). To find the zeros of this polynomial, we use the quadratic formula:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]Each component of this formula plays a critical role:
In the current exercise, after performing polynomial division, we were left with a quadratic equation \( 2x^2 - x + 3 = 0 \). To find the zeros of this polynomial, we use the quadratic formula:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]Each component of this formula plays a critical role:
- \( -b \) represents the opposite of the quadratic coefficient.
- \( \pm \sqrt{b^2 - 4ac} \) is key for determining the nature of the roots; the term \( b^2 - 4ac \) is called the discriminant.