Chapter 3: Problem 256
For the following exercises, find the zeros and give the multiplicity of each. $$ f(x)=(2 x+1)^{3}\left(9 x^{2}-6 x+1\right) $$
Short Answer
Expert verified
The zeros are \(x = -\frac{1}{2}\) with multiplicity 3, and \(x = \frac{1}{3}\) with multiplicity 2.
Step by step solution
01
Identify the Zeroes from Each Factor
The function is given as the product of two factors: \[f(x) = (2x+1)^3(9x^2-6x+1) \]For the first factor \[(2x+1)^3\], the zero is found by setting \(2x+1 = 0\). Solving for \(x\) gives the zero as \(x = -\frac{1}{2}\).
02
Determine the Multiplicity of the First Factor
The first factor \((2x+1)^3\) indicates that the zero \(x = -\frac{1}{2}\) occurs with a multiplicity of 3 since the factor is raised to the power of 3.
03
Identify the Zeroes of the Second Factor
For the second factor \[9x^2-6x+1\],use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) where \(a = 9\), \(b = -6\), and \(c = 1\). Calculate the discriminant: \(b^2 - 4ac = (-6)^2 - 4\times9\times1 = 36 - 36 = 0\). Because the discriminant is zero, there is one real double root given by\[x = \frac{-(-6) \pm \sqrt{0}}{2(9)} = \frac{6}{18} = \frac{1}{3}\].
04
Determine the Multiplicity of the Second Factor
The result \(x = \frac{1}{3}\) has a multiplicity of 2 because the quadratic factor \(9x^2 - 6x + 1\) results in a double root when the discriminant is zero as established in the previous step.
05
State the Zeroes and Their Multiplicities
The function \(f(x)\) has zeros at \(x = -\frac{1}{2}\) with multiplicity 3 and \(x = \frac{1}{3}\) with multiplicity 2. Each zero and its corresponding multiplicity are derived from the powers of their respective factors in the function.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Zeros of a Polynomial
The zeros of a polynomial are the values of the variable that make the polynomial equal to zero. In other words, when you plug a zero into the polynomial, the result is zero. For a polynomial expressed as a product of factors, each factor can be set to zero to find its corresponding zero(s). This helps in understanding and visualizing where the polynomial intersects the x-axis on a graph.
In the given exercise, the function is the product of two factors:
The second, quadratic factor \(9x^2 - 6x + 1\), requires the quadratic formula to solve for its zeros, where the discriminant plays an important role.
In the given exercise, the function is the product of two factors:
- \((2x+1)^3\)
- \(9x^2 - 6x + 1\)
The second, quadratic factor \(9x^2 - 6x + 1\), requires the quadratic formula to solve for its zeros, where the discriminant plays an important role.
Multiplicity of Roots
The multiplicity of a root refers to the number of times that root appears in the polynomial as a zero. This concept helps us determine the behavior of the polynomial at the zero. A root with multiplicity greater than one indicates that the graph touches or is tangent to the x-axis at that root, rather than crossing it.
In the given function, each zero has a specified multiplicity:
In the given function, each zero has a specified multiplicity:
- The zero \(x = -\frac{1}{2}\) from the factor \((2x+1)^3\) has a multiplicity of 3, as indicated by the exponent.
- The zero \(x = \frac{1}{3}\) from the quadratic factor has a multiplicity of 2, derived from the quadratic having one unique root root (a double root due to a zero discriminant).
Quadratic Formula
The quadratic formula is a fundamental tool for solving quadratic equations, represented as \(ax^2 + bx + c = 0\). It provides the solutions (or zeros) of the equation: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula is incredibly useful when factoring is difficult or impossible.
For the second factor of our polynomial \(9x^2 - 6x + 1\), we apply the quadratic formula with
For the second factor of our polynomial \(9x^2 - 6x + 1\), we apply the quadratic formula with
- \(a = 9\)
- \(b = -6\)
- \(c = 1\)
Discriminant
The discriminant is a part of the quadratic formula under the square root, given by \(b^2 - 4ac\). It gives essential information about the nature of the roots of a quadratic equation:
- If the discriminant is positive, the quadratic has two distinct real roots.
- If it's zero, there is one real double root (meaning the graph just touches the x-axis once).
- If it's negative, the roots are complex and not real, which means the graph doesn't touch the x-axis.