Chapter 2: Problem 136
If \(g(x)\) is the transformation of \(f(x)=x\) after a vertical compression by \(\frac{1}{3},\) a shift left by \(1,\) and a shift up by 3 a. Write an equation for \(g(x)\) . b. What is the slope of this line? c. Find the \(y\) -intercept of this line.
Short Answer
Expert verified
a. \(g(x) = \frac{1}{3}x + \frac{10}{3}\); b. Slope: \(\frac{1}{3}\); c. Y-intercept: \(\frac{10}{3}\).
Step by step solution
01
Start with the Parent Function
The parent function is given by \( f(x) = x \), which is a linear function with a slope of 1 and a y-intercept of 0.
02
Apply Vertical Compression
To apply a vertical compression by a factor of \( \frac{1}{3} \), multiply the entire function by \( \frac{1}{3} \). This gives us the function: \( h(x) = \frac{1}{3}x \).
03
Shift Left by 1 Unit
Next, apply a horizontal shift left by 1 unit to the compressed function \( h(x) = \frac{1}{3}x \). This operation leads to the function: \( h(x) = \frac{1}{3}(x + 1) \).
04
Shift Up by 3 Units
Finally, perform a vertical shift up by 3 units on \( h(x) = \frac{1}{3}(x + 1) \). Adding 3 to the function yields: \( g(x) = \frac{1}{3}(x + 1) + 3 \). Simplifying further, \( g(x) = \frac{1}{3}x + \frac{1}{3} + 3 \) or \( g(x) = \frac{1}{3}x + \frac{10}{3} \).
05
Identify the Slope of the Transformed Line
In the equation \( g(x) = \frac{1}{3}x + \frac{10}{3} \), the coefficient of \( x \) represents the slope, which is \( \frac{1}{3} \).
06
Determine the Y-intercept
The y-intercept of the function \( g(x) = \frac{1}{3}x + \frac{10}{3} \) can be found directly from the equation as the constant term, which is \( \frac{10}{3} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linear Functions
Linear functions are the simplest type of functions that create a straight line when graphed. The general form for a linear function is given by the equation \( f(x) = mx + b \), where:
- \( m \) is the slope of the line, representing the rate of change.
- \( b \) is the y-intercept, the point where the line crosses the y-axis.
Vertical Compression
Vertical compression is a transformation that "squashes" the graph of a function towards the x-axis. It is achieved by multiplying the entire function by a factor between 0 and 1.Suppose you have a function \( f(x) = x \) and apply a vertical compression by \( \frac{1}{3} \). This results in the new function \( h(x) = \frac{1}{3}x \). Here, each output of the function is one third of what it originally was, making the graph look flatter.Whenever you see a vertical compression, think of it as decreasing the steepness of the line or curve while keeping the x-values unaffected. The slope, as a result, reduces by the compression factor, highlighting the function's rate of change less dramatically.
Horizontal Shift
A horizontal shift moves the graph of a function left or right along the x-axis. It is achieved by adding or subtracting a constant to the input variable \( x \).In our example, after compressing the function, we apply a horizontal shift by shifting it left by 1 unit. To do this, replace \( x \) by \( x + 1 \) in the function \( h(x) = \frac{1}{3}x \). This transformation leads to the equation \( h(x) = \frac{1}{3}(x + 1) \), effectively moving each point on the graph 1 unit to the left.Whether shifting left or right, remember:
- Add to \( x \) for a left shift.
- Subtract from \( x \) for a right shift.
Vertical Shift
Vertical shifts adjust the graph of a function up or down along the y-axis. This process involves adding or subtracting a constant to the entire function.In our case, we are looking at moving the function up by 3 units after applying the horizontal shift and compression. Starting from the function \( h(x) = \frac{1}{3}(x + 1) \), add 3 to each output value: \( g(x) = \frac{1}{3}(x + 1) + 3 \).Simplifying the equation, we find \( g(x) = \frac{1}{3}x + \frac{10}{3} \).This final step involves adjusting all points upward, preserving the shape of the graph while changing the y-intercept. A vertical shift is one of the simplest transformations and is often used to align graphs with desired base levels.