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For the following exercises, sketch a line with the given features. A \(y\) -intercept of \((0,3)\) and slope \(\frac{2}{5}\)

Short Answer

Expert verified
Plot the y-intercept at \((0, 3)\), use the slope \(\frac{2}{5}\) to find another point at \((5, 5)\), and draw the line through these points.

Step by step solution

01

Understanding the Slope and y-intercept

The slope-intercept form of a line is given by the equation \( y = mx + b \), where \( m \) represents the slope, and \( b \) represents the y-intercept. In this exercise, the slope \( m \) is given as \( \frac{2}{5} \), and the y-intercept \( b \) is \( 3 \). This means the line passes through the point \((0, 3)\).
02

Plotting the y-intercept

Begin by plotting the y-intercept on the coordinate plane. The y-intercept is the point \((0, 3)\) where the line crosses the y-axis. This is the starting point for drawing your line.
03

Using the Slope to Find Another Point

The slope \( \frac{2}{5} \) indicates that for every 5 units you move to the right along the x-axis, you move 2 units up along the y-axis. From the y-intercept \((0, 3)\), move 5 units to the right to \((5, 3)\), and then 2 units up to \((5, 5)\). Plot this point, \((5, 5)\), on the graph.
04

Drawing the Line

With the two points \((0, 3)\) and \((5, 5)\) plotted, draw a straight line through these points. This line represents all the solutions to the equation \( y = \frac{2}{5}x + 3 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Y-Intercept
In any linear equation of the form \( y = mx + b \), the \( y \)-intercept is simply the point where the line crosses the \( y \)-axis. This point is crucial because it gives us a starting location from which we can begin to sketch a line on the coordinate plane. The \( y \)-intercept is always found at \((0, b)\), where \( b \) is the constant in the slope-intercept equation.

For example, in the equation \( y = \frac{2}{5}x + 3 \), the \( y \)-intercept is \((0, 3)\). This means the line passes through the \( y \)-axis at the point \((0, 3)\). Once plotted, this point acts as the anchor, or the starting point of the line. So even before introducing the slope, this step helps establish one of the line's definite points.
Grasping the Concept of Slope
The slope of a line is a measure of its steepness and direction. Represented by \( m \) in the slope-intercept form equation, \( y = mx + b \), it describes how much \( y \) increases or decreases as \( x \) increases. Often expressed as "rise over run," the slope \( \frac{rise}{run} \) describes:
  • The amount of units \( y \) changes (rises) vertically.
  • The number of units \( x \) changes (runs) horizontally.

For the equation \( y = \frac{2}{5}x + 3 \), the slope \( \frac{2}{5} \) specifies that for every 5 units of horizontal movement along the \( x \)-axis, the line moves up 2 units along the \( y \)-axis. This ratio provides a clear direction and angle at which to extend the line starting from the \( y \)-intercept.
Navigating the Coordinate Plane
The coordinate plane is an essential tool for graphing lines and interpreting equations. It is a two-dimensional plane formed by two perpendicular lines known as the \( x \)-axis and \( y \)-axis. Here's how it functions:
  • The \( x \)-axis runs horizontally and represents the independent variable values.
  • The \( y \)-axis runs vertically and represents the dependent variable values.

Every point on the coordinate plane is defined by an \((x, y)\) coordinate, where \( x \) is the horizontal location and \( y \) is the vertical location. When sketching lines, understanding this grid system is vital.

In our context, we plot the \( y \)-intercept at \((0, 3)\) directly on the \( y \)-axis. From there, to utilize the slope \( \frac{2}{5} \):
  • Move 5 units right along the \( x \)-axis to indicate the "run".
  • Then, move 2 units up along the \( y \)-axis, representing the "rise".
  • Plot a new point at \((5, 5)\).

Connect the points, and a line forms that adheres to the direction given by the slope. Thus, the coordinate plane turns an algebraic equation into a visual representation, making it easier to grasp and interpret.

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