Chapter 10: Problem 78
For the following exercises, determine whether the following equations represent hyperbolas. If so, write in standard form. $$-9 x^{2}+18 x+y^{2}+4 y-14=0$$
Short Answer
Expert verified
Yes, the equation represents a hyperbola and its standard form is \(-\frac{(x-1)^2}{1} + \frac{(y+2)^2}{9} = 1\).
Step by step solution
01
Identify the General Equation
The equation given is \(-9 x^{2}+18 x+y^{2}+4 y-14=0\). This resembles a conic section equation. To identify if it represents a hyperbola, we need to rewrite it in its standard form.
02
Rearrange Terms
Group the terms by variable: \(-9x^2 + 18x + y^2 + 4y = 14\).
03
Complete the Square for x
Take the terms involving x: \(-9x^2 + 18x\). Factor out the coefficient of the \(x^2\) term: \(-9(x^2 - 2x)\). Complete the square by adding and subtracting \(1\) inside the parenthesis: \(-9(x^2 - 2x + 1 - 1) = -9((x-1)^2 - 1) = -9(x-1)^2 + 9\).
04
Complete the Square for y
Take the terms involving y: \(y^2 + 4y\). Complete the square by adding and subtracting \(4\) inside the expression: \((y^2 + 4y + 4 - 4) = (y + 2)^2 - 4\).
05
Rewrite the Equation
Substitute back the completed squares into the rearranged equation: \((-9(x-1)^2 + 9) + ((y+2)^2 - 4) = 14\). Simplify: \(-9(x-1)^2 + (y+2)^2 = 9\).
06
Divide by the Constant to Standardize
To express in standard form, divide the entire equation by 9: \(-\frac{(x-1)^2}{1} + \frac{(y+2)^2}{9} = 1\).
07
Determine the Type of Conic
The standard form of the equation \(-\frac{(x-1)^2}{1} + \frac{(y+2)^2}{9} = 1\) indicates a hyperbola, as it fits the form \(-\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1\), where one squared term is subtracted.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Conic Sections
Conic sections are figures obtained by slicing a cone with a plane. These shapes are essential in the study of geometry and are used frequently in precalculus. They consist of four main types: circles, ellipses, parabolas, and hyperbolas.
- Circles are formed when the plane cuts perpendicular to the axis of the cone.
- Ellipses occur with a slight tilt, not parallel to any edge.
- Parabolas result from a parallel slice to the cone's side.
- Hyperbolas appear when the plane slices through the opposite sides of the cone.
Standard Form of Hyperbolas
The standard form of a hyperbola's equation helps identify its properties, such as orientation, center, and asymptotes. The usual forms are:
- Horizontal hyperbola: \(\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\)
- Vertical hyperbola: \(\frac{(y-k)^2}{b^2} - \frac{(x-h)^2}{a^2} = 1\)
- \((h, k)\) is the center of the hyperbola.
- \(a\) and \(b\) are constants determining the distances to the vertices and the slope of the asymptotes.
Completing the Square
Completing the square is a method used to simplify quadratic equations, making them easier to handle. It transforms quadratic expressions into perfect square forms, a technique also valuable for converting conic sections into standard forms.
To complete the square for an equation like \(-9x^2 + 18x\):
To complete the square for an equation like \(-9x^2 + 18x\):
- Factor out the coefficient of \(x^2\), in this case, -9.
- Reorganize as: \(-9(x^2 - 2x)\).
- Find \((b/2)^2\), with \(b\) being the coefficient of \(x\) (here, -2). Add and subtract this value inside the parenthesis.
- This yields: \(-9((x-1)^2 - 1) = -9(x-1)^2 + 9\)."
Precalculus
Precalculus serves as a bridge between algebra and calculus, preparing students for more advanced mathematical concepts. It brings together various math principles, including functions, complex numbers, and conic sections. A strong grasp of precalculus is essential for success in calculus because it sets the stage for limits, derivatives, and integrals.
Conic sections are a major component of precalculus, encompassing the study of the curves (such as hyperbolas) that arise from intersecting a plane with a cone. Mastery of these curves and their equations allows students to model and interpret real-world phenomena using mathematical equations.
Additionally, precalculus emphasizes analytical thinking and problem-solving skills, applying algebraic techniques to understand and predict the behavior of functions and their graphs.
Conic sections are a major component of precalculus, encompassing the study of the curves (such as hyperbolas) that arise from intersecting a plane with a cone. Mastery of these curves and their equations allows students to model and interpret real-world phenomena using mathematical equations.
Additionally, precalculus emphasizes analytical thinking and problem-solving skills, applying algebraic techniques to understand and predict the behavior of functions and their graphs.