Chapter 10: Problem 319
Find the polar equation of the conic with focus at the origin and the given eccentricity and directrix. Directrix: \(y=4 ; e=\frac{3}{2}\)
Short Answer
Expert verified
The polar equation is \( r = \frac{6}{1 - \frac{3}{2} \sin \theta} \).
Step by step solution
01
Identify the Type of Conic
Since the eccentricity \(e = \frac{3}{2}\) is greater than 1, the conic is a hyperbola. The focus of the hyperbola is at the origin because we are working in polar coordinates.
02
Express the Directrix in Polar Coordinates
The given directrix is \(y = 4\). In polar coordinates, the equation of a horizontal line is \(r \sin \theta = d\), where \(d\) is the distance from the pole. Thus, the directrix can be written as \(r \sin \theta = 4\).
03
Use the Formula for Polar Equations of Conics
For a conic section with eccentricity \(e\) and directrix \(r = d\), the polar equation is given by \(r = \frac{ed}{1 - e\sin \theta}\).
04
Substitute Values into Polar Conic Equation
Substitute \(e = \frac{3}{2}\), \(d = 4\) into the polar conic equation: \[ r = \frac{\left(\frac{3}{2}\right) \cdot 4}{1 - \frac{3}{2} \cdot \sin \theta} \].
05
Simplify the Equation
Simplify the equation: \[ r = \frac{6}{1 - \frac{3}{2} \sin \theta} \], which further simplifies to \[ r = \frac{6}{1 - \frac{3}{2} \sin \theta} \]. This is the required polar equation of the conic.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Eccentricity
Eccentricity is a crucial concept when analyzing conic sections, especially in polar coordinates. It is a measure of how much a conic section deviates from being circular. The eccentricity, often denoted by the letter \( e \), determines the shape of the conic:
- For a circle, \( e = 0 \).
- For an ellipse, \( 0 < e < 1 \).
- For a parabola, \( e = 1 \).
- For a hyperbola, \( e > 1 \).
Directrix in Polar Coordinates
The directrix is a fixed line used in the definition of conic sections. In polar coordinates, this line is expressed differently than in Cartesian coordinates. If the directrix is a horizontal line in Cartesian coordinates, such as \( y = d \), it can be transformed into polar coordinates using the equation \( r \sin \theta = d \). Here, \( r \) represents the distance from the pole (origin) to any point on the conic, and \( \theta \) is the angle formed with the positive \( x \)-axis.
In our exercise, the directrix is given as \( y = 4 \). Its polar form would therefore be \( r \sin \theta = 4 \). Understanding this transformation is key to setting up the polar equation of a conic section. It highlights the role of the directrix in determining the path traced by points that maintain a specific ratio of distances to this line and the focus.
In our exercise, the directrix is given as \( y = 4 \). Its polar form would therefore be \( r \sin \theta = 4 \). Understanding this transformation is key to setting up the polar equation of a conic section. It highlights the role of the directrix in determining the path traced by points that maintain a specific ratio of distances to this line and the focus.
Hyperbola in Polar Coordinates
A hyperbola is a type of conic section and appears when the eccentricity, \( e \), is greater than 1. In polar coordinates, the hyperbola's focus is at the origin, and the standard form of its equation incorporates both the eccentricity and the directrix.
For a given eccentricity \( e \) and directrix \( r = d \), the polar equation is represented as:\[ r = \frac{ed}{1 - e\sin \theta} \] This equation encompasses the properties of a hyperbola with its specific orientation relative to the directrix. For example, substituting \( e = \frac{3}{2} \) and \( d = 4 \) gives us:\[ r = \frac{6}{1 - \frac{3}{2} \sin \theta} \] This results in a hyperbola where the shape and orientation are determined by these values. The equation captures how the distance from the focus changes as the angle \( \theta \) varies.
For a given eccentricity \( e \) and directrix \( r = d \), the polar equation is represented as:\[ r = \frac{ed}{1 - e\sin \theta} \] This equation encompasses the properties of a hyperbola with its specific orientation relative to the directrix. For example, substituting \( e = \frac{3}{2} \) and \( d = 4 \) gives us:\[ r = \frac{6}{1 - \frac{3}{2} \sin \theta} \] This results in a hyperbola where the shape and orientation are determined by these values. The equation captures how the distance from the focus changes as the angle \( \theta \) varies.