Chapter 10: Problem 153
For the following exercises, rewrite the given equation in standard form, and then determine the vertex \((V),\) focus \((F)\), and directrix \((d)\) of the parabola. $$x=36 y^{2}$$
Short Answer
Expert verified
Vertex: (0, 0), Focus: (\(\frac{1}{144}, 0\)), Directrix: \(x = -\frac{1}{144}\).
Step by step solution
01
Write the Equation in Standard Form
The given equation is \( x = 36y^2 \). For parabolas that open horizontally, the standard form is \((y-k)^2 = 4p(x-h)\). Let's rearrange the equation to match this form. Divide both sides by 36 to get \( (y - 0)^2 = \frac{1}{36} x \).
02
Identify the Vertex
We can compare \( (y - 0)^2 = \frac{1}{36} x \) with the standard form \( (y-k)^2 = 4p(x-h) \). From this, it's evident that the vertex \((h, k)\) is \((0, 0)\).
03
Determine the Value of 4p
In the equation \((y-0)^2 = \frac{1}{36}x\), the expression \(4p\) is equal to \(\frac{1}{36}\). Therefore, \(4p = \frac{1}{36}\).
04
Solve for p
Divide both sides of the equation \(4p = \frac{1}{36}\) by 4 to find \(p\). Thus \(p = \frac{1}{144}\).
05
Find the Focus
For a horizontally opening parabola \((y-k)^2 = 4p(x-h)\), the focus is located \(p\) units right of the vertex \((h, k)\). Since \(p = \frac{1}{144}\), the focus \(F\) is at \((0 + \frac{1}{144}, 0) = (\frac{1}{144}, 0)\).
06
Calculate the Directrix
The directrix of a horizontally opening parabola \((y-k)^2 = 4p(x-h)\) is a vertical line \(x = h - p\). Given \(h = 0\) and \(p = \frac{1}{144}\), the directrix is \(x = 0 - \frac{1}{144}\), which simplifies to \(x = -\frac{1}{144}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex
In the context of a parabola, the vertex is one of its most essential points. For a horizontally opening parabola represented in the form \((y-k)^2 = 4p(x-h)\), the vertex is located at the point
- \((h, k)\)
Focus
The focus is another crucial feature of a parabola, playing an important role in its geometric properties. In a parabola opening horizontally like \((y-k)^2=4p(x-h)\), the focus is located \(p\) units from the vertex along the x-axis. This means it sits inside the parabola. The equation gives us \(p = \frac{1}{144}\), allowing us to determine the precise coordinates of the focus:
- \((h + p, k)\)
Directrix
The directrix of a parabola is a theoretical line that works with the focus to define the parabola's shape mathematically. For our horizontally opening parabola, the equation \((y-k)^2 = 4p(x-h)\) tells us that the directrix is a vertical line positioned \(p\) units left of the vertex.
- The equation for the directrix is \(x = h - p\)