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Using the cofunction relationship and the following exact forms: \(\sec 75^{\circ}=\sqrt{6}+\sqrt{2} ; \tan 75^{\circ}=2+\sqrt{3}\) $$\sqrt{6} \csc 15^{\circ}$$

Short Answer

Expert verified
\( 6 + 2\sqrt{3} \).

Step by step solution

01

Identify Cofunction Relationships

Recognize that the question requires the use of cofunction identities. The cosecant function can be expressed using the secant of its complementary angle; that is, \( \csc(15^{\circ}) = \sec(75^{\circ}) \). Cofunction identities state that \( \csc(15^{\circ}) = \sec(90^{\circ} - 15^{\circ}) = \sec(75^{\circ}) \).
02

Substitute the Given Value

Substitute \( \sec 75^{\circ} \) with its given value into the expression \( \sqrt{6} \csc 15^{\circ} \). We have that \( \sec 75^{\circ} = \sqrt{6} + \sqrt{2} \), so \( \csc 15^{\circ} = \sqrt{6} + \sqrt{2} \).
03

Calculate the Product

Substitute \( \csc 15^{\circ} \) into the original expression. The problem now is to evaluate \( \sqrt{6} (\sqrt{6} + \sqrt{2}) \). Use the distributive property to expand: \( \sqrt{6} \times \sqrt{6} + \sqrt{6} \times \sqrt{2} \).
04

Perform Calculations

Calculate each term separately: \( \sqrt{6} \times \sqrt{6} = 6 \) and \( \sqrt{6} \times \sqrt{2} = \sqrt{12} = 2\sqrt{3} \).
05

Combine the Results

Add these results together to find the final answer: \( 6 + 2\sqrt{3} \). This is the simplified form of the original expression.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cosecant Function
The cosecant function, often abbreviated as "csc," is a trigonometric function that is the reciprocal of the sine function. Specifically, for any angle \( \theta \), the cosecant is defined as \( \csc(\theta) = \frac{1}{\sin(\theta)} \). This function is particularly useful in various mathematical applications, especially when dealing with right triangles and periodic functions found in calculus.
In this particular exercise, the relationship between the cosecant and secant functions is highlighted through the cofunction identity. It shows how \( \csc(15^{\circ}) \) can be expressed in terms of \( \sec(75^{\circ}) \), utilizing the complementary angle properties that lead to such simplification. This is because \( 75^{\circ} \) and \( 15^{\circ} \) are complementary, adding up to \( 90^{\circ} \).
Understanding the cosecant function helps in breaking down complex trigonometric problems by transitioning between functions using known identities like cofunctions, which are further explored in right triangular settings and periodic examinations.
Secant Function
The secant function, notated as "sec," is another fundamental trigonometric function. It is the reciprocal of the cosine function. For any angle \( \theta \), the secant is written as \( \sec(\theta) = \frac{1}{\cos(\theta)} \). This function is the counterpart of the cosecant when analyzing complementary angles.
In this exercise, the secant function plays a pivotal role through its relationship with the complementary angle identities. Given that \( \sec(75^{\circ} )\) is provided as \( \sqrt{6} + \sqrt{2} \), it allows us to find another angle's cosecant value directly through cofunction identities. Specifically, \( \csc(15^{\circ}) = \sec(75^{\circ}) \).
The secant function helps extend the understanding of inverse trigonometric properties and assists in resolving complex equations by leveraging its identity as part of the broader set of trigonometric functions.
Complementary Angles
Complementary angles are pairs of angles whose measures add up to \( 90^{\circ} \). These angles play a significant role in trigonometry, especially when it comes to cofunction identities. Such identities state that the trigonometric function of an angle is equal to the cofunction of its complementary angle.
For example, as seen in this problem, \( 15^{\circ} \) and \( 75^{\circ} \) are complementary since \( 15^{\circ} + 75^{\circ} = 90^{\circ} \). This relationship helps us express \( \csc(15^{\circ}) \) as \( \sec(75^{\circ}) \), simplifying the computation using known values.
Understanding complementary angles is crucial because they help simplify complex trigonometric relationships, allowing us to use known values to calculate seemingly difficult trigonometric expressions.
Distributive Property
The distributive property is a key mathematical principle, often expressed as \( a(b + c) = ab + ac \). This property is essential in algebraic operations, as it allows for the expansion of expressions and simplification of computations.
In the given trigonometry problem, after substituting the values using the cofunction identity, the expression \( \sqrt{6} (\sqrt{6} + \sqrt{2}) \) can be expanded using the distributive property. Here's how it works:
  • First, multiply \( \sqrt{6} \times \sqrt{6} \), which results in \( 6 \).
  • Then, calculate \( \sqrt{6} \times \sqrt{2} \), resulting in \( \sqrt{12} \), which simplifies to \( 2\sqrt{3} \).

Combining these results, \( 6 + 2\sqrt{3} \) gives the final answer. Applying the distributive property is a powerful tool in arithmetic and algebra, simplifying complex expressions into manageable parts.

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