/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 The local chapter of Mu Alpha Th... [FREE SOLUTION] | 91Ó°ÊÓ

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The local chapter of Mu Alpha Theta will soon be electing a president, vice- president, and treasurer. In how many ways can the positions be filled if the chapter has 15 members?

Short Answer

Expert verified
There are 2730 ways to fill the positions.

Step by step solution

01

Understanding the Problem

We need to find out the number of ways to fill three different positions: president, vice-president, and treasurer, from a group of 15 members. This is a permutations problem since each position is unique and the order of selection matters.
02

Determining the Formula

To solve this problem, we'll use the permutation formula for selecting and arranging r individuals from a total of n, given by: \[ P(n, r) = \frac{n!}{(n-r)!} \]where \( n \) is the total number of people (15), and \( r \) is the number of positions (3).
03

Applying the Permutation Formula

Substitute \( n = 15 \) and \( r = 3 \) into the permutation formula:\[ P(15, 3) = \frac{15!}{(15-3)!} = \frac{15!}{12!} \].
04

Simplifying the Expression

To simplify \( \frac{15!}{12!} \), cancel out the common \(12!\) in the numerator and the denominator:\[ \frac{15 \times 14 \times 13 \times 12!}{12!} = 15 \times 14 \times 13 \].
05

Calculating the Result

Calculate the multiplication: \[ 15 \times 14 = 210 \]\[ 210 \times 13 = 2730 \]Thus, there are 2730 different ways to fill the positions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is a branch of mathematics focused on counting, arranging, and finding patterns. It's crucial for solving problems where you need to figure out the number of ways to group or arrange items. In this local chapter's election problem, we use combinatorics to determine the number of ways to elect a president, vice-president, and treasurer from 15 members. Since each role is distinct, the order does matter, making it a permutations problem. Combinatorics helps in calculating possibilities, ensuring no potential outcome is overlooked.
Factorial
A factorial, denoted by an exclamation point (e.g., 5!), is a mathematical tool used to represent the product of all positive integers up to a specific number. For example,
  • example
    • 5! = 5 × 4 × 3 × 2 × 1 = 120
Factorials play a key role in permutations and combinations. They simplify complex multiplication problems in these contexts. In the problem, we use factorials to calculate the permutations of 15 members taking 3 positions. By understanding factorials, simplifying \[ \frac{15!}{12!} \] becomes manageable, as common terms are easily canceled out.
Counting Methods
Counting methods are strategies used to determine the number of ways objects can be arranged or grouped. These include permutations, combinations, and variations. When order matters, as in selecting specific roles like president and vice-president, permutations are used. For this election scenario, you would apply the permutation formula:\[P(n, r) = \frac{n!}{(n-r)!}\]where \(n\) is the total number of members, and \(r\) is the number of roles to fill. By substituting the values, \[P(15, 3) = \frac{15!}{(12)!} = 15 \times 14 \times 13\]This counting method skillfully handles the distinct order of selections, resulting in 2730 ways to fill the positions. Understanding these methods allows you to tackle various real-world decision-making scenarios more effectively.

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