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Solve for \(x\) a) \(2 \log _{3} x=\log _{3} 32+\log _{3} 2\) b) \(\frac{3}{2} \log _{7} x=\log _{7} 125\) c) \(\log _{2} x-\log _{2} 3=5\) d) \(\log _{6} x=2-\log _{6} 4\)

Short Answer

Expert verified
a) x = 8b) x = 25c) x = 96d) x = 9

Step by step solution

01

Simplify the expression using logarithm properties

Given the equation: a) \(2 \log _{3} x=\log _{3} 32+\log _{3} 2\)Use the product rule of logarithms: \(\log_b a + \log_b c = \log_b (a \cdot c)\)So the equation becomes: \(2 \log _{3} x=\log _{3}(32 \cdot 2)\)This simplifies to: \(2 \log _{3} x=\log _{3} 64\)
02

Isolate the variable

Divide both sides by 2:\(\log _{3} x = \frac{\log _{3} 64}{2}\)This simplifies to: \(\log _{3} x = \log _{3} 8\)
03

Solve for x

Since the bases and the logs are the same:\(x = 8\)
04

Convert logarithmic expressions using properties

Given the equation: b) \(\frac{3}{2} \log _{7} x = \log _{7} 125\)
05

Isolate the variable

Multiply both sides by \(\frac{2}{3}\):\(\log _{7} x = \frac{2}{3} \log _{7} 125\)
06

Use exponent rules

We know that \(\frac{2}{3} \log _{7} 125\) is the same as \(\log _{7} 125^{\frac{2}{3}}\):\(\log _{7} x = \log _{7} 25\)
07

Solve for x

Since the bases and the logs are the same:\(x = 25\)
08

Convert logarithmic expressions using properties

Given the equation: c) \(\log _{2} x - \log _{2} 3 = 5\)
09

Use quotient rule

Combine using the quotient rule: \(\log _{2} \left( \frac{x}{3} \right) = 5\)
10

Remove the logarithm

Rewrite the equation in exponential form: \(\frac{x}{3} = 2^{5}\)
11

Solve for x

Multiply both sides by 3: \(x = 3 \cdot 32\)So: \(x = 96\)
12

Convert right-hand side using properties

Given the equation: d) \(\log _{6} x = 2 - \log _{6} 4\)
13

Use subtraction property

Combine using the subtraction property: \(\log _{6} x = \log _{6} 6^{2} - \log _{6} 4\)Which simplifies to: \(\log _{6} x = \log _{6} \left( \frac{36}{4} \right)\)
14

Simplify the argument

Simplify \(\frac{36}{4}\) to: \(\log _{6} x = \log _{6} 9\)
15

Solve for x

Since the bases and the logs are the same:\(x = 9\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

logarithm properties
Logarithms help us to solve for unknown exponents and manage multiplication and division within logarithmic expressions. Some essential properties include:
- **Product Rule**: \(\text{log}_b(a \times c) = \text{log}_b(a) + \text{log}_b(c)\). This enables us to compress the sum of two logs into a single logarithm.
- **Quotient Rule**: \(\text{log}_b \left( \frac{a}{c} \right) = \text{log}_b(a) - \text{log}_b(c)\). This is handy for combining differences into a single logarithm.
- **Power Rule**: \(\text{log}_b(a^c) = c \times \text{log}_b(a)\). This brings the exponent out as a coefficient.
Understanding these properties is fundamental. For instance, \(2 \text{log}_3(x) = \text{log}_3(64)\) can be solved with these rules. We rewrite \(2 \text{log}_3(x)\) as \(\text{log}_3(x^2)\), simplifying to \(\text{log}_3(64)\). Then, \(x^2 = 64\) leads us to \(x = 8\).
solving logarithm equations
Solving logarithm equations involves using logarithm properties to isolate the variable. Here is the general process:
1. **Apply Logarithm Properties**: Simplify the given logarithmic expressions using product, quotient, or power rules.
2. **Isolate the Logarithm**: Rearrange the equation to isolate the logarithmic expression on one side.
3. **Convert to Exponential Form**: If needed, rewrite the logarithmic equation in its exponential form to solve for the variable.
Take the equation \(\frac{3}{2} \text{log}_7(x) = \text{log}_7(125)\). We isolate \(\text{log}_7(x)\) by multiplying both sides by \(\frac{2}{3}\). This transforms the equation into \(\text{log}_7(x) = \text{log}_7(25)\). Since the log bases and values are equal, it follows that \(x = 25\).
logarithm rules
Logarithm rules allow us to manipulate logarithmic expressions effectively. They include:
- **Change of Base Rule**: Helps converting logarithms of different bases, useful if calculators have specific log functions.
- **Single Logarithm Rule**: Helps compress multiple logarithms into one, which simplifies equations.
Consider \(\text{log}_2(x) - \text{log}_2(3) = 5\). Using the quotient rule, rewrite it to get \(\text{log}_2\left( \frac{x}{3} \right) = 5\). Then, convert to exponential form \(\frac{x}{3} = 2^5\), which becomes \(\frac{x}{3} = 32\). Solve for \(x\) by multiplying both sides by 3, resulting in \(x = 96\).
exponential form
Rewriting logarithms in exponential form is crucial. It helps in solving complex logarithmic equations. The general transform is \(\text{log}_b(a) = c\) converts to \(b^c = a\).
For example, with \(\text{log}_6(x) = 2 - \text{log}_6(4)\), use subtraction rule to combine terms: \(\text{log}_6(x) = \text{log}_6 \left( \frac{36}{4} \right)\), simplifying to \(\text{log}_6(x) = \text{log}_6(9)\). Since the logs are equal, \(x = 9\). The conversion to exponential form helps to isolate and solve for the variable directly when dealing with more complex logarithmic components.

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