Chapter 8: Problem 24
If \(m=\log _{2} n\) and \(2 m+1=\log _{2} 16 n\), determine the values of \(m\) and \(n\).
Short Answer
Expert verified
The values are \( m = 3 \) and \( n = 8 \).
Step by step solution
01
- Understand the given equations
The problem provides two equations: 1. \( m = \log_{2} n \)2. \( 2m + 1 = \log_{2} 16n \)
02
- Rewrite the second equation using properties of logarithms
Use the property of logarithms that \( \log_{a} (bc) = \log_{a} b + \log_{a} c \): \( 2m + 1 = \log_{2} (16 \cdot n) \)\( 2m + 1 = \log_{2} 16 + \log_{2} n \)
03
- Calculate \( \log_{2} 16 \)
Since \( 16 = 2^4 \), we find: \( \log_{2} 16 = 4 \)
04
- Substitute \( \log_{2} 16 \) and simplify
Substitute \( 4 \) for \( \log_{2} 16 \) back in the equation: \( 2m + 1 = 4 + \log_{2} n \)
05
- Substitute \( \log_{2} n \) with \( m \)
Since \( m = \log_{2} n \), replace \( \log_{2} n \) with \( m \): \( 2m + 1 = 4 + m \)
06
- Solve for \( m \)
Rearrange the equation to isolate \( m \): \( 2m - m = 4 - 1 \)\( m = 3 \)
07
- Solve for \( n \)
Use the value of \( m \) in equation \( m = \log_{2} n \): \( 3 = \log_{2} n \)Convert from logarithmic form to exponential form: \( n = 2^3 \)\( n = 8 \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
logarithm properties
Logarithms are a fundamental part of mathematics, especially useful for dealing with exponential equations. Understanding the properties of logarithms can simplify complex equations. Let’s cover some essential properties:
1. **Product Property**: \[ \log_{a} (bc) = \log_{a} b + \log_{a} c \] This property means that the log of a product is the sum of the logs.
2. **Quotient Property**: \[ \log_{a} \left( \frac{b}{c} \right) = \log_{a} b - \log_{a} c \] This property tells us that the log of a quotient is the difference of the logs.
3. **Power Property**: \[ \log_{a} (b^c) = c \log_{a} b \] This property means if you're logging a number raised to a power, you can multiply the power out in front.
In our exercise, we specifically use the product property to simplify the equation. By rewriting \[ \log_{2} (16n) \] as \[ \log_{2} 16 + \log_{2} n. \] This helps break down the complex log into simpler parts, making it easier to solve.
1. **Product Property**: \[ \log_{a} (bc) = \log_{a} b + \log_{a} c \] This property means that the log of a product is the sum of the logs.
2. **Quotient Property**: \[ \log_{a} \left( \frac{b}{c} \right) = \log_{a} b - \log_{a} c \] This property tells us that the log of a quotient is the difference of the logs.
3. **Power Property**: \[ \log_{a} (b^c) = c \log_{a} b \] This property means if you're logging a number raised to a power, you can multiply the power out in front.
In our exercise, we specifically use the product property to simplify the equation. By rewriting \[ \log_{2} (16n) \] as \[ \log_{2} 16 + \log_{2} n. \] This helps break down the complex log into simpler parts, making it easier to solve.
exponential functions
Exponential functions are mathematical functions in the form \[ y = a^x. \] They are crucial in various fields such as compound interest, population growth, and more. Key points to understand about exponential functions include:
1. **Base and Exponent**: In the function \[ y = a^x \], \[ a \] is the base and \[ x \] is the exponent.
2. **Growth and Decay**: If \[ a > 1 \], the function grows. If \[ 0 < a < 1 \], the function decays.
3. **Inverse Relation**: Logarithms are the inverse of exponential functions. This means that if \[ y = a^x \], then \[ x = \log_{a} y \].
In solving our exercise, we use the inverse relationship between logarithms and exponentials. When we get \[ m = \log_{2} n \], we can easily convert it to exponential form: \[ n = 2^m. \] This conversion is critical for finding the value of \[ n \], once we have solved for \[ m \].
1. **Base and Exponent**: In the function \[ y = a^x \], \[ a \] is the base and \[ x \] is the exponent.
2. **Growth and Decay**: If \[ a > 1 \], the function grows. If \[ 0 < a < 1 \], the function decays.
3. **Inverse Relation**: Logarithms are the inverse of exponential functions. This means that if \[ y = a^x \], then \[ x = \log_{a} y \].
In solving our exercise, we use the inverse relationship between logarithms and exponentials. When we get \[ m = \log_{2} n \], we can easily convert it to exponential form: \[ n = 2^m. \] This conversion is critical for finding the value of \[ n \], once we have solved for \[ m \].
solving equations
Solving equations, especially ones involving logarithms and exponentials, requires a systematic approach. Here are some steps to follow:
1. **Understand the given problem**: Identify the given equations and their forms.
2. **Use logarithm properties**: Apply the relevant properties to simplify the equations, like the product property in our case.
3. **Convert forms as needed**: Switching between logarithmic and exponential forms can make solving easier.
4. **Isolate variables**: Rearrange the equation to isolate the variable you are solving for.
In our step-by-step solution, we:
- start by recognizing the given equations.
- simplify using logarithm properties.
- convert logarithmic expressions to exponential forms to solve for the variable.
By following these structured steps, you can solve complex logarithmic equations efficiently.
1. **Understand the given problem**: Identify the given equations and their forms.
2. **Use logarithm properties**: Apply the relevant properties to simplify the equations, like the product property in our case.
3. **Convert forms as needed**: Switching between logarithmic and exponential forms can make solving easier.
4. **Isolate variables**: Rearrange the equation to isolate the variable you are solving for.
In our step-by-step solution, we:
- start by recognizing the given equations.
- simplify using logarithm properties.
- convert logarithmic expressions to exponential forms to solve for the variable.
By following these structured steps, you can solve complex logarithmic equations efficiently.