/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Match each function with its des... [FREE SOLUTION] | 91Ó°ÊÓ

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Match each function with its description in the table. a) \(y=-2 \cos 2(x+4)-1\) b) \(y=2 \sin 2(x-4)-1\) c) \(y=2 \sin (2 x-4)-1\) d) \(y=3 \sin (3 x-9)-1\) e) \(y=3 \sin (3 x+\pi)-1\) $$\begin{aligned} &\begin{array}{|c|c|c|c|c|}\hline & \text { Amplitude } & \text { Period } & \begin{array}{c}\text { Phase } \\\\\text { Shift }\end{array} & \begin{array}{c}\text { Vertical } \\ \text { Displacement }\end{array} \\\\\hline \mathbf{A} & 3 & \frac{2 \pi}{3} & 3 \text { right } & 1 \text { down } \\\\\hline \mathbf{B} & 2 & \pi & 2 \text { right } & 1 \text { down } \\\\\hline \mathbf{C} & 2 & \pi & 4 \text { right } & 1 \text { down } \\\\\hline \mathbf{D} & 2 & \pi & 4 \text { left } & 1 \text { down } \\\\\hline \mathbf{E} & 3 & \frac{2 \pi}{3} & \frac{\pi}{3} \text { left } & 1 \text { down } \\\\\hline \end{array}\end{aligned}$$

Short Answer

Expert verified
a: D, b: B, c: C, d: A, e: E

Step by step solution

01

Determine the amplitude

The amplitude is the coefficient of the sine or cosine function.a) Amplitude = |−2| = 2b) Amplitude = |2| = 2c) Amplitude = |2| = 2d) Amplitude = |3| = 3e) Amplitude = |3| = 3
02

Determine the period

The period is given by \ \( \frac{2\pi}{|B|} \), where B is the coefficient of x inside the sine or cosine function.a) Period = \( \frac{2\pi}{2} = \pi \)b) Period = \( \frac{2\pi}{2} = \pi \)c) Period = \( \frac{2\pi}{2} = \pi \)d) Period = \( \frac{2\pi}{3} \)e) Period = \( \frac{2\pi}{3} \)
03

Determine the phase shift

The phase shift is given by \( -\frac{C}{B} \), where C is the constant inside the sinusoid function with x and B is the coefficient of x.a) Phase shift = \( -\frac{4}{2} = -2 \), which means 4 leftb) Phase shift = \( \frac{4}{2} = 2 \), which means 2 rightc) Phase shift = \( \frac{4}{2} = 2 \), which means 2 rightd) Phase shift = \( \frac{9}{3} = 3 \), which means 3 righte) Phase shift = \( \frac{-\pi}{3} \), which means \( \frac{\pi}{3} \) left
04

Determine the vertical displacement

The vertical displacement is the constant term added or subtracted from the sine or cosine function.All functions have a vertical displacement of -1, which is 1 down.
05

Match the functions to the descriptions

Now match each function to the descriptions based on the amplitude, period, phase shift, and vertical displacement.a) Amplitude = 2, Period = \( \pi \), Phase shift = 4 left, Vertical Displacement = 1 down, matches Db) Amplitude = 2, Period = \( \pi \), Phase shift = 2 right, Vertical Displacement = 1 down, matches Bc) Amplitude = 2, Period = \( \pi \), Phase shift = 2 right, Vertical Displacement = 1 down, should match B but the match for C (4 right) is E (needs to be verified further)d) Amplitude = 3, Period = \( \frac{2\pi}{3} \), Phase shift = 3 right, Vertical Displacement = 1 down, matches Ae) Amplitude = 3, Period = \( \frac{2\pi}{3} \), Phase shift = \( \frac{\pi}{3} \) left, Vertical Displacement = 1 down, matches ETherefore, b can only match C

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Amplitude
The amplitude of a trigonometric function measures the height of its peaks and the depths of its troughs. It is a coefficient in front of the sine or cosine term. For example, if we have the function \( y = 2 \sin(x) \), the amplitude is 2, indicating the wave oscillates between -2 and 2. In general, if your function is in the form \( y = A \sin(Bx + C) + D \) or \( y = A \cos(Bx + C) + D \), then the amplitude is represented as \( |A| \). Always take the absolute value, as amplitude is a measurement of distance and cannot be negative.
Period of Trigonometric Functions
The period of a trigonometric function is the distance along the x-axis before the function starts repeating its pattern. For sine and cosine functions, the period is calculated using the formula \( \frac{2\pi}{|B|} \), where B is the coefficient of x inside the function. For instance, in the function \( y = \cos(2x) \), the period would be \( \frac{2\pi}{2} = \pi \). This means the function completes one full cycle every \( \pi \) units along the x-axis.
Phase Shift
Phase shift refers to the horizontal shift left or right of a trigonometric function. If a function is in the form \( y = A \sin(Bx + C) + D \) or \( y = A \cos(Bx + C) + D \), the phase shift can be found using \( -\frac{C}{B} \). For example, in the function \( y = \sin(x + \pi) \), the phase shift is \( -\frac{\pi}{1} = -\pi \), meaning the function shifts \( \pi \) units to the left. Positive results mean a shift to the right.
Vertical Displacement
Vertical displacement shifts the entire graph of the function up or down along the y-axis. In the general forms \( y = A \sin(Bx + C) + D \) and \( y = A \cos(Bx + C) + D \), the term D represents the vertical displacement. For instance, in the function \( y = \cos(x) - 1 \), the whole graph of \( \cos(x) \) is shifted 1 unit down. The displacement can be positive (up) or negative (down).

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Most popular questions from this chapter

A plane flying at an altitude of \(10 \mathrm{km}\) over level ground will pass directly over a radar station. Let \(d\) be the ground distance from the antenna to a point directly under the plane. Let \(x\) represent the angle formed from the vertical at the radar station to the plane. Write \(d\) as a function of \(x\) and graph the function over the interval \(0 \leq x \leq \frac{\pi}{2}\).

Write the equation of the sine function in the form \(y=a \sin b(x-c)+d\) given its characteristics. a) amplitude \(4,\) period \(\pi,\) phase shift \(\frac{\pi}{2}\) to the right, vertical displacement 6 units down b) amplitude 0.5, period \(4 \pi,\) phase shift \(\frac{\pi}{6}\) to the left, vertical displacement 1 unit up c) amplitude \(\frac{3}{4},\) period \(720^{\circ},\) no phase shift, vertical displacement 5 units down

The University of Calgary's Institute for Space Research is leading a project to launch Cassiope, a hybrid space satellite. Cassiope will follow a path that may be modelled by the function \(h(t)=350 \sin 28 \pi(t-25)+400,\) where \(h\) is the height, in kilometres, of the satellite above Earth and \(t\) is the time, in days. a) Determine the period of the satellite. b) How many minutes will it take the satellite to orbit Earth? c) How many orbits per day will the satellite make?

Determine the period (in degrees) of each function. Then, use the language of transformations to describe how each graph is related to the graph of \(y=\cos x\) a) \(y=\cos 2 x\) b) \(y=\cos (-3 x)\) c) \(y=\cos \frac{1}{4} x\) d) \(y=\cos \frac{2}{3} x\)

a) State the five key points for \(y=\cos x\) that occur in one complete cycle from 0 to \(2 \pi\) b) Use the key points to sketch a graph of \(y=\cos x\) for \(-2 \pi \leq x \leq 2 \pi .\) Indicate the key points on your graph. c) What are the \(x\) -intercepts of the graph? d) What is the \(y\) -intercept of the graph? e) What is the maximum value of the graph? the minimum value?

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