/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 If \(y=f(x)\) has a period of \(... [FREE SOLUTION] | 91Ó°ÊÓ

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If \(y=f(x)\) has a period of \(6,\) determine the period of \(y=f\left(\frac{1}{2} x\right)\)

Short Answer

Expert verified
The period is 12.

Step by step solution

01

Understand the given period

The function given is \( y = f(x) \) with a period of \( 6 \). This means that for any value of \( x \), \( f(x) = f(x + 6) \).
02

Substitute in the new function

We need to determine the period of the new function \( y = f\left(\frac{1}{2} x\right) \). Let's consider when \( f(x) \) has the same period as \( f\left(\frac{1}{2} x\right) \) by substituting \( \frac{1}{2} x \).
03

Set up the equation for the new period

To find the period \( T \) of \( f\left(\frac{1}{2} x\right) \), we need to find \( T \) such that \( f\left(\frac{1}{2} x + \frac{1}{2} T\right) = f\left(\frac{1}{2} x\right) \). This implies the argument of the function must change by 6 units due to the original period: \[ \frac{1}{2} T = 6 \]
04

Solve for the new period

Now solve \( \frac{1}{2} T = 6 \) for \( T \): \[ T = 6 \times 2 = 12 \] Hence, the period of the function \( y = f\left(\frac{1}{2} x\right) \) is \( 12 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

function period
When working with periodic functions, understanding the period is crucial. The period of a function is the interval over which the function's values repeat. For example, if a function has a period of 6, this means that it repeats its values every 6 units. Mathematically, for a function \(f(x)\) with period \(P\), we have \(f(x) = f(x + P)\) for any value of \(x\).

Knowing the period helps us predict the behavior of the function over larger intervals. It's especially important in problems involving function transformations, where the period can change. Recognizing these changes allows us to grasp the new pattern of repetition.
periodic functions
A periodic function is one that repeats its values at regular intervals, known as periods. Examples include trigonometric functions like sine and cosine, which have periods of \(2\pi\). Understanding periodic functions is essential in various fields such as signal processing, physics, and engineering.

To determine the period of a transformed function, we need to understand how the transformation affects the original period. For instance, if we have a function \(f(x)\) with period 6, and we transform it by scaling the input, such as \(f(\frac{1}{2} x)\), the period changes accordingly. The transformation can stretch or shrink the period depending on the scaling factor. In general, if the transformation is of the form \(f(ax)\), then the new period \(P_{\text{new}}\) can be found using the relationship \(P_{\text{new}} = P_{\text{original}} \times |a|\).
function transformations
Function transformations involve shifting, stretching, or compressing the graph of a function. In the exercise, we looked at the transformation \(y = f(\frac{1}{2} x)\). This transformation scales the input \(x\) by \(\frac{1}{2}\), effectively stretching the graph horizontally.

To find the new period of the transformed function, we set up an equation based on the changed input. We know the original period is 6, so we use the equation \(\frac{1}{2} T = 6\) to find the new period \(T\). Solving this equation gives us \(T = 12\). Therefore, the period of \(y = f(\frac{1}{2} x)\) is 12.

Understanding these transformations is vital for graphing functions correctly and predicting their behavior after transformations. It's a key skill across mathematics and its applications in real-world problems.

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Most popular questions from this chapter

The graph of \(y=\cos x\) is transformed as described. Determine the values of the parameters \(a, b, c,\) and \(d\) for the transformed function. Write the equation for the transformed function in the form \(y=a \cos b(x-c)+d\). a) vertical stretch by a factor of 3 about the \(x\) -axis, horizontal stretch by a factor of 2 about the \(y\) -axis, translated 2 units to the left and 3 units up b) vertical stretch by a factor of \(\frac{1}{2}\) about the \(x\) -axis, horizontal stretch by a factor of \(\frac{1}{4}\) about the \(y\) -axis, translated 3 units to the right and 5 units down c) vertical stretch by a factor of \(\frac{3}{2}\) about the \(x\) -axis, horizontal stretch by a factor of 3 about the \(y\) -axis, reflected in the \(x\) -axis, translated \(\frac{\pi}{4}\) units to the right and 1 unit down

State the amplitude of each periodic function. Sketch the graph of each function. a) \(y=2 \sin \theta\) b) \(y=\frac{1}{2} \cos \theta\) c) \(y=-\frac{1}{3} \sin x\) d) \(y=-6 \cos x\)

Does \(y=\) tan \(x\) have an amplitude? Explain.

Determine the period, the sinusoidal axis, and the amplitude for each of the following. a) The first maximum of a sine function occurs at the point \(\left(30^{\circ}, 24\right),\) and the first minimum to the right of the maximum occurs at the point \(\left(80^{\circ}, 6\right).\) b) The first maximum of a cosine function occurs at \((0,4),\) and the first minimum to the right of the maximum occurs at \(\left(\frac{2 \pi}{3},-16\right).\) c) An electron oscillates back and forth 50 times per second, and the maximum and minimum values occur at +10 and \(-10,\) respectively.

Golden, British Columbia, is one of the many locations for heliskiing in Western Canada. When skiing the open powder, the skier leaves behind a trail, with two turns creating one cycle of the sinusoidal curve. On one section of the slope, a skier makes a total of 10 turns over a \(20-s\) interval. a) If the distance for a turn, to the left or to the right, from the midline is \(1.2 \mathrm{m}\) determine the function that models the path of the skier. b) How would the function change if the skier made only eight turns in the same 20-s interval?

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