/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 Solve the system of linear equat... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve the system of linear equations. $$ \begin{array}{r} 2 x+3 y=6 \\ -x-y=-3 \end{array} $$ Solution: Set up the determinants. $$ D=\left|\begin{array}{rr} 2 & 3 \\ -1 & -1 \end{array}\right|, D_{x}=\left|\begin{array}{rr} 2 & 6 \\ -1 & -3 \end{array}\right|, \text { and } D_{y}=\left|\begin{array}{rr} 6 & 3 \\ -3 & -1 \end{array}\right| $$ Evaluate the determinants. $$ \begin{array}{c} D=1, D_{x}=0, \text { and } D_{y}=3 \\ x=\frac{D_{x}}{D}=\frac{0}{1}=0 \text { and } y=\frac{D_{y}}{D}=\frac{3}{1}=3 \end{array} $$ Solve for \(x\) and \(y .\) \(x=0, y=3\) is incorrect. What mistake was made?

Short Answer

Expert verified
The mistake was a misinterpretation; \((x, y) = (0, 3)\) is correct and satisfies the system.

Step by step solution

01

Understanding Determinants

A determinant is calculated for a 2x2 matrix \(\begin{bmatrix}a & b\c & d\end{bmatrix}\) as \(ad - bc\). We need to apply this method to our matrices to find the correct determinants.
02

Verify Determinant Calculation for D

For the determinant \(D = \left|\begin{array}{rr} 2 & 3 \ -1 & -1 \end{array}\right|\), calculate it using the formula \(ad - bc = (2)(-1) - (3)(-1) = -2 + 3 = 1\), which is correct.
03

Verify Determinant Calculation for Dx

For the determinant \(D_{x} = \left|\begin{array}{rr} 2 & 6 \ -1 & -3 \end{array}\right|\), calculate it using \(ad - bc = (2)(-3) - (6)(-1) = -6 + 6 = 0\). This is correct.
04

Verify Determinant Calculation for Dy

For the determinant \(D_{y} = \left|\begin{array}{rr} 6 & 3 \ -3 & -1 \end{array}\right|\), calculate it using \(ad - bc = (6)(-1) - (3)(-3) = -6 + 9 = 3\), which is correct.
05

Review the Solution Interpretation

Reevaluate using Cramer's rule: \(x = \frac{D_{x}}{D} = \frac{0}{1} = 0\) and \(y = \frac{D_{y}}{D} = \frac{3}{1} = 3\). These calculations appear correct, meaning the likely mistake is in the interpretation of these results, rather than the numerical computation.
06

Evaluate Consistency with Equations

Verify by substituting \(x = 0\) and \(y = 3\) into the original equations: \(2(0) + 3(3) = 6\) is true, and \(-0 - 3 = -3\) is also true. The solution indeed satisfies the equations.
07

Conclusion on Mistake

The original provided answer claimed \(x = 0\) and \(y = 3\) was incorrect, but calculations and verifications show it is correct. The apparent mistake was misunderstanding the consistency of the results with the system of equations.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Determinants
Determinants are mathematical values that are calculated from a matrix, and they play a crucial role in solving systems of linear equations using Cramer's Rule. When dealing with a 2x2 matrix, it is structured as follows: \[\begin{bmatrix} a & b \ c & d \end{bmatrix}\]. To find the determinant of this 2x2 matrix, you apply the formula \( ad - bc \). This formula helps us evaluate and understand the behavior of the matrix.
  • The determinant is a single number associated with a square matrix.
  • It's a key concept in various areas of algebra, including solving equations and understanding properties of matrices.
In our exercise, we calculated several determinants for matrices to find the solutions to the equations. Each determinant corresponds to a specific part of the formula evaluations in Cramer's Rule.
System of Linear Equations
A system of linear equations is a collection of two or more linear equations with the same set of variables. In our exercise, the system consists of:\[\begin{array}{r} 2x + 3y = 6 \ -x - y = -3\end{array}\]
  • The goal is to find values for variables that satisfy all equations simultaneously.
  • There can be one solution, many solutions, or no solution at all.
Cramer's Rule is particularly useful for systems of linear equations, especially when you have exactly as many equations as unknowns. By using determinants, Cramer's Rule offers a straightforward way to find the solution, assuming certain conditions about the determinant itself.
2x2 Matrix
A 2x2 matrix is the simplest form of a square matrix, containing two rows and two columns. It looks like:\[\begin{bmatrix} a & b \ c & d \end{bmatrix}\]
  • Every element in the matrix (\(a, b, c, d\)) is crucial in calculations involving determinants and linear equations.
  • The 2x2 matrix is foundational for more complex matrices and is a stepping stone for higher dimensional algebra.
When applying Cramer's Rule, each equation in our system is represented as a 2x2 matrix, allowing us to calculate determinants and solve for the unknown variables. Understanding the formation and application of the 2x2 matrix is essential for tackling more complex systems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Astronomers have determined the number of stars in a small region of the universe to be 2,880,968 classified as red dwarfs, yellow, and blue stars. For every blue star there are 120 red dwarfs; for every red dwarf there are 3000 yellow stars. Determine the number of stars by type in that region of the universe.

Maximize the objective function \(z=x+2 y\) subject to the conditions, where \(a > b > 0\). $$\begin{aligned}x+y & \geq a \\\\-x+y & \leq a \\\x+y & \leq a+b \\\\-x+y & \geq a-b\end{aligned}$$

Apply a graphing utility to evaluate the determinants. $$\left|\begin{array}{rrrr} -3 & 21 & 19 & 3 \\ 4 & 1 & 16 & 2 \\ 17 & 31 & 2 & 5 \\ 13 & -4 & 10 & 2 \end{array}\right|$$

If \(A_{m \times n} B_{n \times p}\) is defined, explain why \(\left(A_{m \times n} B_{n \times p}\right)^{2}\) is not defined for \(m \neq p\)

Use the following tables. The following table gives fuel and electric requirements per mile associated with gasoline and electric automobiles: $$\begin{array}{|l|c|c|}\hline & \begin{array}{c} \text { Numeer of } \\\\\text { GatLons/Mile }\end{array} & \begin{array}{c}\text { Numeer of } \\\\\text { kW-hr/Mile }\end{array} \\\\\hline \text { SUV full size } & 0.06 & 0 \\ \hline \text { Hybrid car } & 0.02 & 0.1 \\\\\hline \text { Electric car } & 0 & 0.3 \\\\\hline\end{array}$$ The following table gives an average cost for gasoline and electricity: $$\begin{array}{|l|c|}\hline \text { Cost per gallon of gasoline } & \$ 3.80 \\\\\hline \text { Cost per kW-hr of electricity } & \$ 0.05 \\\\\hline\end{array}$$ Environment. Assume you drive 12,000 miles per year. What are the yearly costs associated with driving the three types of cars in Exercise \(81 ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.