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In Exercises \(21-50,\) graph each system of inequalities or indicate that the system has no solution. $$\begin{aligned} &y \geq x-1\\\ &y \leq-x+3\\\ &y < x+2 \end{aligned}$$

Short Answer

Expert verified
The solution is the triangular region where \( y \geq x - 1 \), \( y \leq -x + 3 \), and \( y < x + 2 \).

Step by step solution

01

Graph the First Inequality

Graph the inequality \( y \geq x - 1 \). Start by graphing the line \( y = x - 1 \), which has a y-intercept at -1 and a slope of 1. The line is solid because the inequality sign is \( \geq \). Shade above the line since it includes all points where \( y \) is greater than or equal to \( x - 1 \).
02

Graph the Second Inequality

Graph the inequality \( y \leq -x + 3 \). Begin by graphing the line \( y = -x + 3 \), which has a y-intercept at 3 and a slope of -1. Since the inequality sign is \( \leq \), use a solid line. Shade below the line to include all points where \( y \) is less than or equal to \( -x + 3 \).
03

Graph the Third Inequality

Graph the inequality \( y < x + 2 \). Plot the line \( y = x + 2 \), which intersects the y-axis at 2 with a slope of 1. Since the inequality is strict (\(<\)), use a dashed line to represent it. Shade below this line to include all points where \( y \) is strictly less than \( x + 2 \).
04

Find the Feasible Region

Identify the overlapping shaded region that satisfies all three inequalities. The feasible region is where the shaded areas from all inequalities overlap. Note that the line \( y = x + 2 \) is dashed, meaning points on this line are not included in the solution.
05

Interpret the Graph

The shaded area that lies above the line \( y = x - 1 \), below the line \( y = -x + 3 \), and strictly below the line \( y = x + 2 \) is the solution. Since each line forms a boundary, the solution is a triangular region where all these conditions hold true. Check that any point in this triangular area satisfies all inequalities.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Feasible Region
A feasible region is a core concept in systems of inequalities. It refers to the area on a graph where all the conditions of the inequalities are satisfied simultaneously.
When graphing a system of linear inequalities, each inequality will divide the plane into two halves - one where the inequality holds true, and one where it doesn't. The feasible region is the intersection of these true halves.
For example:
  • If you have three inequalities, you will graph each one by determining if they use solid or dashed lines.
  • Next, you'll find the area where all the shaded regions overlap.
  • This overlapping region is what we call the feasible region.
This region may be bound by solid lines if the inequalities are non-strict (≥ or ≤), meaning the points on the lines are included. Or, it may be bounded by dashed lines if the inequalities are strict (< or >), indicating that points on these lines are not part of the feasible region.
In our example exercise, the feasible region is a triangular area where all the three given inequalities hold true. This region is important because it encompasses all possible solutions that satisfy the system of inequalities.
Inequality Graphing
Inequality graphing involves plotting each inequality on a coordinate plane to visualize the solution set.
The process starts by transforming each inequality into an equation (e.g., replacing ≥ with =), allowing you to graph a boundary line.
For example:
  • Equation of the form \( y \geq x - 1 \) becomes the line \( y = x - 1 \).
  • Once plotted, determine if the line should be solid or dashed. Solid lines are used if the inequality is non-strict (≥ or ≤), indicating that points on the line are included in the solution. Dashed lines represent strict inequalities (< or >), where points on the line are excluded.
After graphing the line, you determine on which side of the line the inequality holds true and shade that region. For instance, if the inequality is \( y \geq x - 1 \), you would shade above the line since that represents all points where \( y \) values are greater than or equal to \( x - 1 \).
This method helps in visualizing the potential solutions for each inequality in the system.
Shading Regions
Shading regions is a vital step in graphing systems of inequalities as it displays where each inequality holds true.
Once you plot the boundary line for each inequality, decide which region or side of the line to shade. This region contains all the possible solutions for that inequality.
Steps to shade regions accurately:
  • First, choose a test point that is not on the line to determine which side should be shaded. Common choices are points like (0, 0) unless it lies on the line.
  • If the test point satisfies the inequality, shade the side where it lies. If not, shade the opposite side.
In the example exercise given:
  • For the inequality \( y \geq x - 1 \), shade the region above the line since points there have greater y-values.
  • For \( y \leq -x + 3 \), shade below the line as y-values in this region are smaller.
  • Lastly, for \( y < x + 2 \), a dashed line is used. Here, shade the area below this line, indicating that the actual line is not included in the solution.
Thus, shading helps you easily identify where conditions from all inequalities overlap, leading to the feasible region.

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