/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 Solve each system of linear equa... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each system of linear equations by elimination. $$\begin{aligned} &\frac{1}{3} x+\frac{1}{2} y=1\\\ &\frac{1}{5} x+\frac{7}{2} y=2 \end{aligned}$$

Short Answer

Expert verified
The solution is \( x = \frac{75}{32} \), \( y = \frac{7}{16} \).

Step by step solution

01

Clear Fractions

Multiply the first equation by 6 and the second equation by 10 to eliminate the fractions. This gives:\[ 2x + 3y = 6 \] (from the first equation) and \[ 2x + 35y = 20 \] (from the second equation).
02

Eliminate the x-term

Subtract the first equation from the second equation to eliminate the \(x\)-term. This means you take: \[ (2x + 35y) - (2x + 3y) = 20 - 6 \]which simplifies to: \[ 32y = 14 \].
03

Solve for y

Divide both sides of the equation \(32y = 14\) by 32 to solve for \(y\):\[ y = \frac{14}{32} = \frac{7}{16} \].
04

Substitute to Find x

Substitute \(y = \frac{7}{16}\) back into one of the original equations to solve for \(x\), using the modified first equation:\[ 2x + 3(\frac{7}{16}) = 6 \].This simplifies to:\[ 2x + \frac{21}{16} = 6 \].Subtract \(\frac{21}{16}\) from both sides:\[ 2x = 6 - \frac{21}{16} \],\[ 2x = \frac{75}{16} \].
05

Solve for x

Divide both sides by 2 to solve for \(x\):\[ x = \frac{75}{32} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Systems of Equations
A system of equations refers to a set of two or more equations that share common variables. In a system of linear equations, all the equations are linear. This implies that each equation can be represented as a straight line. The goal is to find the values of the variables that satisfy all equations simultaneously.

If each equation involves two variables like x and y, we're often looking for an intersection of lines. The point where the lines cross corresponds to the solution of the system. When using the elimination method, we focus on eliminating one of the variables to simplify the problem. This can help us get to the solution more directly.
Basics of Linear Equations
A linear equation is an equation of the first degree. This means it has no exponents higher than one. Common forms of linear equations include formulas such as: ax + by = c, where a, b, and c are constants.

Linear equations graph as straight lines and have consistent slope values. The simplicity of these equations allows them to be solved using techniques like substitution or elimination. Recognizing a linear equation is crucial because it tells us how to approach solving it. By focusing on terms with the variable, we can transform the equation systematically to find the unknown variable values.
Techniques for Solving Equations
To solve equations, particularly simultaneous linear equations, different methods can be used, such as substitution and elimination. Elimination is particularly useful when dealing with a system of equations. As seen in the original exercise, the first step often involves making the equations simpler or more comparable.

It involves the elimination of one variable by making the coefficients of that variable the same in both equations and then subtracting one equation from the other. This allows you to solve for the remaining variable.
The elimination method is efficient for solving systems of linear equations, leading directly to a solution when executed correctly. After eliminating one variable, you can substitute back to find the other.
Handling Fractions in Equations
Fractions in equations can often complicate matters as they require careful handling to avoid mistakes. To simplify, multiplying each term of the equation by the least common multiple (LCM) of the denominators is a common strategy. This method removes fractions, transforming the equation into a more standard form without fractions.

In the example provided, we multiplied by 6 and 10 to clear fractions. This not only makes calculations easier but reduces the chance of errors. When fractions are cleared, linear equations become simpler to manipulate, allowing for easier implementation of solving methods like elimination. Thus, understanding how to manage fractions is vital for simplifying complex equations.

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