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Perform the indicated row operations on each augmented matrix. $$\left[\begin{array}{rrrr|r} 1 & 0 & 5 & -10 & 15 \\ 0 & 1 & 2 & -3 & 4 \\ 0 & 2 & -3 & 0 & -1 \\ 0 & 0 & 1 & -1 & -3 \end{array}\right] \quad R_{2}-\frac{1}{2} R_{3} \rightarrow R_{3}$$

Short Answer

Expert verified
The updated Row 3 is \([0, \frac{3}{2}, -4, \frac{3}{2}, -3]\).

Step by step solution

01

Understanding Row Operations

The operation given is a type of row operation for matrices. Row operations involve adding, subtracting, or multiplying a row by a scalar for matrix manipulation. Here, the operation is to subtract half of Row 2 from Row 3 and replace Row 3 with this new result.
02

Identifying Rows Involved

First, clearly identify the rows involved: Row 2 is \([0, 1, 2, -3, 4]\) and Row 3 is \([0, 2, -3, 0, -1]\). The goal is to transform Row 3.
03

Calculating Half of Row 2

Calculate \(\frac{1}{2}\) of Row 2. Divide each element by 2, which gives \(\left[0, \frac{1}{2}, 1, -\frac{3}{2}, 2\right]\).
04

Performing the Subtraction

Subtract the result from Step 3 from Row 3: \[\begin{aligned}&[0, 2, -3, 0, -1] - [0, \frac{1}{2}, 1, -\frac{3}{2}, 2] \&= [0 - 0, 2 - \frac{1}{2}, -3 - 1, 0 + \frac{3}{2}, -1 - 2] \&= [0, \frac{3}{2}, -4, \frac{3}{2}, -3].\end{aligned}\]
05

Updating the Augmented Matrix

Replace Row 3 in the augmented matrix with the newly calculated row from Step 4. The updated matrix is:\[\begin{bmatrix}1 & 0 & 5 & -10 & 15 \0 & 1 & 2 & -3 & 4 \0 & \frac{3}{2} & -4 & \frac{3}{2} & -3 \0 & 0 & 1 & -1 & -3\end{bmatrix}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Augmented Matrix
An augmented matrix is a special type of matrix that includes both the coefficients of a system of linear equations and the constants on the right side of the equations. This combination is separated by a vertical line, allowing for a clear visual distinction between them. Understanding this format is key to solving linear systems using matrix methods.

In augmented matrices, each row generally represents one equation, and each column represents a different variable or constant from the system of equations. The augmented matrix from the exercise is shown as follows:

\[\begin{bmatrix}1 & 0 & 5 & -10 & \big| & 15 \ 0 & 1 & 2 & -3 & \big| & 4 \ 0 & 2 & -3 & 0 & \big| & -1 \ 0 & 0 & 1 & -1 & \big| & -3\end{bmatrix}.\]

This concise representation makes it easier to perform calculations like matrix manipulations and row operations.
Matrix Manipulation
Matrix manipulation refers to the various operations we can perform on matrices to solve systems of equations or transform them into different forms. Such operations include basic arithmetic operations (addition, subtraction, multiplication) and more advanced ones like finding inverses or determinants.

When manipulating matrices, it is crucial to follow mathematical rules specific to matrices. For example, matrix multiplication is not commutative, meaning that the order of multiplication matters. For an augmented matrix, these manipulations can help simplify the matrix into a more workable form, potentially making it easier to solve for unknown variables.
  • Matrix addition and subtraction are straightforward, performing operations element-wise.
  • Scalar multiplication involves multiplying every element of a matrix by a given scalar.
  • Transformation processes like Gaussian elimination or row reduction are often used in solving matrix problems.
These manipulations make the calculation of solutions more systematic and organized.
Elementary Row Operations
Elementary row operations are procedures used to manipulate the rows of a matrix to simplify it and eventually solve corresponding linear equations. There are three types of elementary row operations:

  • Row swapping: Exchanging two rows in the matrix.
  • Scalar multiplication: Multiplying all elements in a row by a non-zero constant.
  • Row replacement: Adding or subtracting a multiple of one row to/from another row.
In the provided exercise, the operation performed was a row replacement. This type of operation is powerful because it maintains the equivalency of the system of equations represented by the matrix but transforms it to make the solution process easier.

These operations are applicable to any matrix and are essential in methods like Gaussian elimination or finding the reduced row echelon form of a matrix.
Row Replacement
Row replacement, as demonstrated in the exercise, is a specific elementary row operation. It involves replacing a row in the matrix with the sum (or difference) of itself and a multiple of another row. This operation is quite flexible and crucial in transforming a matrix towards a simpler form without altering the solution set of the associated system of equations.

In this particular exercise, Row 3 was transformed using a row replacement operation: 1. Calculate half of Row 2.2. Subtract this from Row 3.

This specific process, written mathematically, can be summarized as:\[R_3 = R_3 - \frac{1}{2}R_2\]
The result alters Row 3 but keeps the overall mathematical nature of the matrix unchanged, thus helping in moving closer to the solution.

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Most popular questions from this chapter

For what values of \(x\) does the inverse of \(A\) not exist, given \(A=\left[\begin{array}{ll}x & 6 \\ 3 & 2\end{array}\right] ?\)

Involve vertical motion and the effect of gravity on an object. Because of gravity, an object that is projected upward will eventually reach a maximum height and then fall to the ground. The equation that relates the height \(h\) of a projectile \(t\) seconds after it is projected upward is given by $$h=\frac{1}{2} a t^{2}+v_{0} t+h_{0}$$ where \(a\) is the acceleration due to gravity, \(h_{0}\) is the initial height of the object at time \(t=0,\) and \(v_{0}\) is the initial velocity of the object at time \(t=0 .\) Note that a projectile follows the path of a parabola opening down, so \(a<0\). An object is thrown upward, and the table below depicts the height of the ball \(t\) seconds after the projectile is released. Find the initial height, initial velocity, and acceleration due to gravity. $$\begin{array}{|c|c|} \hline t \text { (seconos) } & \text { Heiant (FEET) } \\ \hline 1 & 54 \\ \hline 2 & 66 \\ \hline 3 & 46 \\ \hline \end{array}$$

Given \(C_{n \times m}\) and \(A_{m \times n}=B_{m \times n},\) explain why \(A C \neq C B\) if \(m \neq n\)

Solve the system of equations using an augmented matrix. $$ \begin{aligned} 3 x-2 y+z &=-1 \\ x+y-z &=3 \\ 2 x-y+3 z &=0 \end{aligned} $$ Solution: \(\begin{aligned} \text { Step } 1: \text { Write the system as an } &\left[\begin{array}{rrr|r}3 & -2 & 1 & -1 \\ 1 & 1 & -1 & 3 \\ 2 & -1 & 3 & 0\end{array}\right] \\ \text { augmented matrix. } & 1 \end{aligned}\) \(\begin{aligned} \text { Step 2: Reduce the matrix using } &\left[\begin{array}{lll|l}1 & 0 & 0 & 1 \\ 0 & 1 & 0 & 2 \\ 0 & 0 & 1 & 0\end{array}\right] \\ \text { Gaussian elimination. } & 0 \end{aligned}\) Step 3: Identify the answer: Row 3 is inconsistent \(1=0\) therefore there is no solution. This is incorrect. What mistake was made?

Determine whether each of the following statements is true or false: The procedure for Gaussian elimination can be used only for a system of linear equations represented by a square matrix.

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