/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 Solve each system of linear equa... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each system of linear equations by elimination. $$\begin{array}{r} 3 x+2 y=6 \\ -3 x+6 y=18 \end{array}$$

Short Answer

Expert verified
The solution is \( x = 0 \) and \( y = 3 \).

Step by step solution

01

Add the Equations

The system of equations is: \( 3x + 2y = 6 \) and \( -3x + 6y = 18 \). To eliminate \(x\), add the first equation to the second equation: \[(3x + 2y) + (-3x + 6y) = 6 + 18 \] The resulting equation is \( 8y = 24 \).
02

Solve for y

With the equation from Step 1, \( 8y = 24 \), solve for \( y \) by dividing both sides by 8: \[y = \frac{24}{8} = 3\] So, \( y = 3 \).
03

Substitute y into One Equation

Substitute \( y = 3 \) back into the first original equation to solve for \( x \): \[3x + 2(3) = 6\] Simplify to get: \[3x + 6 = 6\] Subtract 6 from both sides: \[3x = 0\]
04

Solve for x

From the equation \( 3x = 0 \), solve for \( x \) by dividing both sides by 3: \[x = \frac{0}{3} = 0\] So, \( x = 0 \).
05

Conclusion

The solution to the system is \( x = 0 \) and \( y = 3 \). This means the two lines intersect at the point \( (0, 3) \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elimination Method
The elimination method is a popular way to solve systems of linear equations. This technique involves adding or subtracting equations to eliminate one of the variables, making it easier to solve the system.
In our original exercise, we start with two equations. The goal is to remove one of the variables, either \( x \) or \( y \), from the equations. By manipulating the equations, particularly by aligning them in a way that the coefficients of one of the variables are opposites, we can add or subtract the equations to eliminate that variable.
  • This method is useful when the equations are already set up to cancel out one variable easily.
  • Eliminating a variable simplifies the system into a single equation, making it straightforward to find the value of the remaining variable.
  • Once a variable is eliminated, the resulting equation can be solved using basic algebraic operations.
In short, the elimination method is favored for its straightforward approach to simplifying systems of linear equations into a much easier-to-solve format.
Solving for Variables
Once we have simplified the system of equations using the elimination method, we proceed to solve for the unknown variables. Solving for variables involves isolating the variable on one side of the equation to determine its value.
For example, in our step-by-step solution, after eliminating \( x \), we find ourselves with the equation \( 8y = 24 \). Solving for \( y \) involves performing arithmetic operations to isolate \( y \). Dividing both sides by 8 gives \( y = 3 \).
  • First, simplify the equation as much as possible.
  • Perform operations that will leave the variable on one side, usually achieved by addition, subtraction, multiplication, or division.
  • Remember, whatever operation you apply to one side of the equation, apply it to the other to maintain equality.
After determining the value of one variable, substitute it back into one of the original equations to find the second variable, as we did by substituting \( y = 3 \) to find \( x = 0 \).
This ensures that both solutions are consistent with the original system of equations.
Intersection of Lines
Once both variables \( x \) and \( y \) are determined, interpreting the solution involves understanding where the two lines intersect on the coordinate plane. In the context of linear equations, the solution represents the point of intersection.
In our problem, finding \( x = 0 \) and \( y = 3 \) means the two lines intersect at the point \( (0, 3) \). This point of intersection is significant as it signifies that both equations are satisfied simultaneously at this coordinate pair.
  • The intersection point is where the lines cross and represents the solution to the system of equations.
  • If the lines are not parallel and not the same, there is exactly one intersection point.
  • Understanding the geometric interpretation of these solutions helps in visualizing the problem and verifying the accuracy of the solution.
In summary, the intersection point obtained from solving systems of linear equations illustrates the common solution shared by both equations, providing insight into their geometric relationship.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine whether each of the following statements is true or false: Gauss-Jordan elimination produces a matrix in reduced row-echelon form.

The circle given by the equation \(x^{2}+y^{2}+a x+b y+c=0\) passes through the points (4,4) \((-3,-1),\) and \((1,-3) .\) Find \(a, b,\) and \(c\)

Ginger talks Gary into putting less money in the money market and more money in the stock (see Exercise 95 ). They place \(10,000\) of their savings into investments. They put some in a money market account earning \(3 \%\) interest, some in a mutual fund that has been averaging \(7 \%\) a year, and some in a stock that rose \(10 \%\) last year. If they put \( 3,000\) more in the stock than in the mutual fund and the mutual fund and stock have the same growth in the next year as they did in the previous year, they will earn \(\$ 840\) in a year. How much money did they put in each of the three investments?

Involve vertical motion and the effect of gravity on an object. Because of gravity, an object that is projected upward will eventually reach a maximum height and then fall to the ground. The equation that relates the height \(h\) of a projectile \(t\) seconds after it is projected upward is given by $$h=\frac{1}{2} a t^{2}+v_{0} t+h_{0}$$ where \(a\) is the acceleration due to gravity, \(h_{0}\) is the initial height of the object at time \(t=0,\) and \(v_{0}\) is the initial velocity of the object at time \(t=0 .\) Note that a projectile follows the path of a parabola opening down, so \(a<0\). An object is thrown upward, and the table below depicts the height of the ball \(t\) seconds after the projectile is released. Find the initial height, initial velocity, and acceleration due to gravity. $$\begin{array}{|c|c|} \hline t \text { (seconos) } & \text { HeiGHT (FEET) } \\ \hline 1 & 34 \\ \hline 2 & 36 \\ \hline 3 & 6 \\ \hline \end{array}$$

Apply a graphing utility to evaluate the determinants. $$\left|\begin{array}{rrrr} -3 & 2 & -1 & 3 \\ 4 & 1 & 5 & 2 \\ 17 & 2 & 2 & 8 \\ 13 & -4 & 10 & -11 \end{array}\right|$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.