Chapter 6: Problem 29
Simplify each of the trigonometric expressions. $$\frac{1-\cot (-x)}{1+\cot x}$$
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
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Chapter 6: Problem 29
Simplify each of the trigonometric expressions. $$\frac{1-\cot (-x)}{1+\cot x}$$
These are the key concepts you need to understand to accurately answer the question.
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In calculus, the method of separation of variables is used to solve certain differential equations. Given an equation with two variables, the method consists of writing the equation in such a way that each side of the equation contains only one type of variable. Use the product-to-sum and sum-to-product identities to separate the variables \(x\) and \(y\) in each equation. $$\frac{1}{2}=\sin \left(\frac{x+y}{2}\right) \cos \left(\frac{x-y}{2}\right)$$
Find the smallest positive values of \(x\) that make the statement true. Give the answer in degrees and round to two decimal places. $$\ln x-\cos x=0$$
Explain the mistake that is made. $$\text { Solve } \sqrt{1+\sin x}=\cos x \text { on } 0 \leq x \leq 2 \pi$$ Solution: Square both sides. \(\quad 1+\sin x=\cos ^{2} x\). Use the Pythagorean identity. \(\quad 1+\sin x=\underbrace{\cos ^{2} x}_{1-\sin ^{2} x}\). Simplify. \(\sin ^{2} x+\sin x=0\). Factor. \(\quad \sin x(\sin x+1)=0\). Set each factor equal to zero.\(\sin x=0 \quad\) or \(\quad \sin x+1=0\). Solve for \(\sin x, \quad \sin x=0 \quad\) or \(\quad \sin x=-1\). Solve for \(x\) \(x=0, \pi, \frac{3 \pi}{2}, 2 \pi\). This is incorrect. What mistake was made?
Determine whether each statement is true or false. $$\cot \left(\frac{\pi}{4}-x\right)=\frac{1+\tan x}{1-\tan x}$$
Determine whether each statement is true or false. If a trigonometric equation has all real numbers as its solution, then it is an identity.
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