Chapter 4: Problem 43
Convert from radians to degrees. Round your answers to the nearest hundredth of a degree. 4.
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Chapter 4: Problem 43
Convert from radians to degrees. Round your answers to the nearest hundredth of a degree. 4.
These are the key concepts you need to understand to accurately answer the question.
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Find the smallest positive measure of \(\theta\) (rounded to the nearest degree) if the indicated information is true. \(\sin \theta=-0.3420\) and the terminal side of \(\theta\) lies in quadrant IV.
The measures of two sides and an angle are given. Determine whether a triangle (or two) exist, and if so, solve the triangle(s). $$a=13, b=26, \alpha=120^{\circ}$$
Determine whether each statement is true or false. If the radius of a circle doubles, then the arc length (associated with a fixed central angle) doubles.
A hot-air balloon is sighted at the same time by two friends who are 2 miles apart on the same side of the balloon. The angles of elevation from the two friends are \(10^{\circ}\) and \(15^{\circ} .\) How high is the balloon?
Explain the mistake that is made. If the radius of a set of tires on a car is 15 inches and the tires rotate \(180^{\circ}\) per second, how fast is the car traveling (linear speed) in miles per hour? Solution: Write the formula for linear speed. $$\begin{aligned}&v=r \omega\\\&v=(15 \text { in. })\left(\frac{180^{\circ}}{\sec }\right) \end{aligned}$$ Let \(r=15\) inches and \(\omega=180^{\circ}\) per second. Simplify. \(v=2700 \frac{\mathrm{in}}{\mathrm{sec}}\) Let 1 mile \(=5280\) feet \(=63,360\) inches and 1 hour \(=3600\) seconds. $$v=\left(\frac{2700 \cdot 3600}{63,360}\right) \mathrm{mph}$$ Simplify. \(v \approx 153.4 \mathrm{mph}\) This is incorrect. The correct answer is approximately 2.7 mph. What mistake was made?
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