Chapter 4: Problem 14
Convert from degrees to radians. Leave the answers in terms of \(\pi\). $$60^{\circ}$$
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Chapter 4: Problem 14
Convert from degrees to radians. Leave the answers in terms of \(\pi\). $$60^{\circ}$$
These are the key concepts you need to understand to accurately answer the question.
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Let \(A, B,\) and \(C\) be the lengths of the three sides with \(X, Y,\) and \(Z\) as the corresponding angle measures in a triangle. Write a program using a TI calculator to solve each triangle with the given measures. $$A=\sqrt{12}, B=\sqrt{21}, \text { and } Z=62.8^{\circ}$$
In calculus, the value of \(F(b)-F(a)\) of a function \(F(x)\) at \(x=a\) and \(x=b\) plays an important role in the calculation of definite integrals. Find the exact value of \(F(b)-F(a)\). $$F(x)=\sec x, a=\frac{\pi}{6}, b=\frac{\pi}{3}$$
Evaluate the expression \(\sec 120^{\circ}\) exactly. Solution: \(120^{\circ}\) lies in quadrant 11 The reference angle is \(30^{\circ}\) \(\begin{array}{l}\text { Find the cosine of the } \\ \text { reference angle. }\end{array} \quad \cos 30^{\circ}=\frac{\sqrt{3}}{2}\) \(\begin{array}{l}\text { Cosine is negative in } \\ \text { quadrant II. }\end{array} \quad \cos 120^{\circ}=-\frac{\sqrt{3}}{2}\) \(\begin{array}{l}\text { Secant is the reciprocal } \\ \text { of cosine. }\end{array} \quad \sec 120^{\circ}=-\frac{2}{\sqrt{3}}=-\frac{2 \sqrt{3}}{3}\) This is incorrect. What mistake was made? (GRAPH CANNOT COPY)
Use a calculator to evaluate the following expressions. If you get an error, explain why. $$\sec 270^{\circ}$$
Calculate cot \(54.9^{\circ}\) in the following two ways: a. Find tan \(54.9^{\circ}\) to three decimal places and then divide 1 by that number. Write that number to five decimal places. b. With a calculator in degree mode, enter \(54.9,\) tan, \(1 / \mathrm{x},\) and round the result to five decimal places.
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