Chapter 3: Problem 91
In calculus the following two functions are studied: $$ \sinh x=\frac{e^{x}-e^{-x}}{2} \quad \text { and } \quad \cosh x=\frac{e^{x}+e^{-x}}{2} $$ $$\text { Show that } \cosh ^{2} x-\sinh ^{2} x=1$$
Short Answer
Expert verified
\( \cosh^2 x - \sinh^2 x = 1 \) is true after simplifying both sides using algebra.
Step by step solution
01
Write Down the Identity to Prove
We need to prove the identity \(\cosh^2 x - \sinh^2 x = 1\). This can be verified by using the definitions of the hyperbolic sine and cosine functions.
02
Write the Expressions for \( \cosh x \) and \( \sinh x \)
Start by writing the expressions for \( \cosh x \) and \( \sinh x \):\[\cosh x = \frac{e^x + e^{-x}}{2}\]\[\sinh x = \frac{e^x - e^{-x}}{2}\]
03
Square the Expressions
Find \( \cosh^2 x \) and \( \sinh^2 x \) by squaring their expressions:\[\cosh^2 x = \left(\frac{e^x + e^{-x}}{2}\right)^2 = \frac{(e^x + e^{-x})^2}{4}\]\[\sinh^2 x = \left(\frac{e^x - e^{-x}}{2}\right)^2 = \frac{(e^x - e^{-x})^2}{4}\]
04
Expand the Squared Expressions
Expand both expressions using the formula \((a+b)^2 = a^2 + 2ab + b^2\):\[(e^x + e^{-x})^2 = e^{2x} + 2 \cdot e^x \cdot e^{-x} + e^{-2x} = e^{2x} + 2 + e^{-2x}\]And for \((a-b)^2 = a^2 - 2ab + b^2\):\[(e^x - e^{-x})^2 = e^{2x} - 2 \cdot e^x \cdot e^{-x} + e^{-2x} = e^{2x} - 2 + e^{-2x}\]
05
Subtract the Squared Terms
Subtract \( \sinh^2 x \) from \( \cosh^2 x \):\[\cosh^2 x - \sinh^2 x = \frac{(e^{2x} + 2 + e^{-2x})}{4} - \frac{(e^{2x} - 2 + e^{-2x})}{4}\]Simplify the expression:\[\cosh^2 x - \sinh^2 x = \frac{e^{2x} + 2 + e^{-2x} - e^{2x} + 2 - e^{-2x}}{4}\]The terms \( e^{2x} \) and \( e^{-2x} \) cancel each other out, leaving:\[\cosh^2 x - \sinh^2 x = \frac{4}{4} = 1\]
06
Conclusion: Verify the Identity
After performing the algebraic operations, we verify that \( \cosh^2 x - \sinh^2 x = 1 \), confirming the given identity.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hyperbolic Sine
The hyperbolic sine function, denoted as \( \sinh x \), is an important concept in calculus, similar to its trigonometric counterpart, the sine function. Its definition is based on exponential functions, given by \( \sinh x = \frac{e^x - e^{-x}}{2} \). This formula uses the natural exponential function \( e \), providing an elegant symmetry between the exponential growth and decay. The hyperbolic sine function reflects properties of hyperbolas, analogous to how the sine function relates to circles.
- \( \sinh x \) is an odd function: \( \sinh(-x) = -\sinh x \).
- It's differentiable and smooth, critical for calculus applications.
- The function increases as \( x \) increases, reflecting exponential growth.
Hyperbolic Cosine
Just like the hyperbolic sine, the hyperbolic cosine function has a key role in mathematics. It is expressed as \( \cosh x = \frac{e^x + e^{-x}}{2} \). Interestingly, it is based on the average of exponential growth and decay, which highlights its symmetry and provides useful properties.
- \( \cosh x \) is an even function: \( \cosh(-x) = \cosh x \).
- It is always non-negative, reflecting the positive values of exponential sums.
- As \( x \) approaches infinity, \( \cosh x \) grows exponentially.
Identity Proof
In mathematics, proof of identities is essential to verifying mathematical facts and relationships. The identity \( \cosh^2 x - \sinh^2 x = 1 \) is one such relationship that shows a profound connection between hyperbolic functions. The proof demonstrates that hyperbolic functions, like their trigonometric relatives, have intrinsic relationships that are elegantly expressed using exponential functions.
To prove this:
To prove this:
- Start with the definitions: \( \cosh x = \frac{e^x + e^{-x}}{2} \) and \( \sinh x = \frac{e^x - e^{-x}}{2} \).
- Square both functions separately.
- Expand each using algebraic identities for squaring binomials.
- Subtract the squared terms to show all exponential terms cancel out, simplifying to 1.
Exponential Functions
Exponential functions are a cornerstone of both mathematics and applied sciences. Defined by the base of the natural logarithm \( e \), they exhibit dramatic growth and decay, with unique characteristics that make them indispensable. These functions form the backbone of hyperbolic functions with equations like \( e^x \) representing exponential growth and \( e^{-x} \) indicating decay.
- Exponential functions are always positive, never touching zero.
- They grow increasingly faster as \( x \) increases, or decrease slower as \( x \) decreases for negative exponents.
- They are the only functions with a rate of change directly proportional to the function's current value.