Chapter 2: Problem 62
For each polynomial function given: (a) list each real zero and its multiplicity; (b) determine whether the graph touches or crosses at each \(x\) -intercept; (c) find the \(y\) -intercept and a few points on the graph; (d) determine the end behavior; and (e) sketch the graph. $$f(x)=-5 x^{4}+10 x^{3}-5 x^{2}$$
Short Answer
Step by step solution
Factor the Polynomial
List Zeros and Multiplicities
Determine the Graph Behavior at Each x-Intercept
Find the y-Intercept and Additional Points
Determine End Behavior
Sketch the Graph
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Zeros and Multiplicities
Both zeros here have a multiplicity of 2, indicating that each zero appears twice in the factorization.
- Zero at \(x = 0\) with multiplicity 2
- Zero at \(x = 1\) with multiplicity 2
Graph Behavior
- At \(x = 0\) with even multiplicity (2), the graph touches the x-axis and turns back without crossing it.
- At \(x = 1\) with even multiplicity (2), the graph likewise touches and turns back without crossing.
To understand further graph behavior, we evaluate some points:
- At \(x = -1\), the graph is below the x-axis with a value of -5.
- At \(x = 0.5\), the graph remains slightly below the x-axis, at approximately -0.3125.
- At \(x = 2\), it is far below the x-axis, at -20.
End Behavior
Because the coefficient is negative and the degree is even, the graph of \(f(x)\) will head downwards towards \(-\infty\) as \(x\) moves to \(\pm \infty\).
- As \(x \to \infty\), \(f(x) \to -\infty\).
- As \(x \to -\infty\), \(f(x) \to -\infty\).
Intercepts
The y-intercept occurs where the graph crosses the y-axis, that is, when \(x = 0\). By plugging \(x = 0\) into the function, \(f(0) = -5(0)^2(0 - 1)^2 = 0\), we find that the y-intercept is at the origin (0,0).
- X-Intercepts: \(x = 0\) (multiplicity 2), \(x = 1\) (multiplicity 2)
- Y-Intercept: (0, 0)