Chapter 2: Problem 53
In Exercises \(45-54,\) find the vertex of the parabola associated with each quadratic function. $$f(x)=0.06 x^{2}-2.6 x+3.52$$
Short Answer
Expert verified
The vertex of the parabola is approximately at \((21.67, -24.678)\).
Step by step solution
01
Identify the Quadratic Function
We are given the quadratic function \( f(x) = 0.06 x^2 - 2.6 x + 3.52 \). This is a standard form \( ax^2 + bx + c \) where \( a = 0.06 \), \( b = -2.6 \), and \( c = 3.52 \). Our task is to find the vertex of the parabola.
02
Use the Vertex Formula
The x-coordinate of the vertex of a parabola defined by the quadratic function \( ax^2 + bx + c \) is given by the formula \( x = -\frac{b}{2a} \). Substitute \( a = 0.06 \) and \( b = -2.6 \) into the formula.
03
Calculate the X-Coordinate of the Vertex
Compute the x-coordinate using the formula: \[x = -\frac{-2.6}{2 \times 0.06} = \frac{2.6}{0.12} = 21.67\]
04
Use the X-Coordinate to Find the Y-Coordinate
Substitute \( x = 21.67 \) back into the function to find the y-coordinate of the vertex:\[f(21.67) = 0.06(21.67)^2 - 2.6(21.67) + 3.52\]Calculate each term separately:\[0.06 \times 469.0689 \approx 28.144,\]\[-2.6 \times 21.67 = -56.342,\]\[3.52 = 3.52\]Summing these gives \[f(21.67) = 28.144 - 56.342 + 3.52 \approx -24.678\]
05
State the Vertex
Combine the x-coordinate and y-coordinate to state the vertex of the parabola. Thus, the vertex is approximately at \((21.67, -24.678)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Functions
In mathematics, quadratic functions play a vital role in understanding different relationships and models. A quadratic function is a type of polynomial function which is characterized by its highest exponent of two, written in the form:
\[ f(x) = ax^2 + bx + c \]
where:
\[ f(x) = ax^2 + bx + c \]
where:
- \(a, b, \) and \(c\) are constants with \(a eq 0\)
- \(x\) represents the variable
- If \(a > 0\), the parabola opens upwards, resembling a U-shape.
- If \(a < 0\), it opens downwards, resembling an upside-down U.
Standard Form of a Quadratic Function
The standard form of a quadratic function is crucial for analyzing and solving quadratic equations, and it is expressed as:
\[ ax^2 + bx + c = 0 \]
where:
Recognizing the standard form quickly allows one to apply algebraic techniques effectively, such as factoring and completing the square. For the function \( f(x) = 0.06 x^2 - 2.6 x + 3.52 \), which is already in standard form, we can directly use these features to find important aspects like the vertex using the vertex formula.
\[ ax^2 + bx + c = 0 \]
where:
- \(a\) is the coefficient of the quadratic term \(x^2\)
- \(b\) is the coefficient of the linear term \(x\)
- \(c\) is the constant term
Recognizing the standard form quickly allows one to apply algebraic techniques effectively, such as factoring and completing the square. For the function \( f(x) = 0.06 x^2 - 2.6 x + 3.52 \), which is already in standard form, we can directly use these features to find important aspects like the vertex using the vertex formula.
Vertex Formula
The vertex of a parabola is a critical point that indicates either the maximum or minimum value that the parabola can achieve. When a quadratic function is in standard form \( ax^2 + bx + c \), we can use the vertex formula to easily find the vertex.
The x-coordinate of the vertex is found using:
\[ x = -\frac{b}{2a} \]
This formula allows us to calculate precisely where the parabola's axis of symmetry is located. Once the x-coordinate is known, the y-coordinate can be found by plugging this value back into the original quadratic function.
For example, with \(a = 0.06\) and \(b = -2.6\), we substitute these into our vertex formula to find the x-coordinate: \[ x = -\frac{-2.6}{2 \times 0.06} = 21.67 \]
Then, we substitute \(x = 21.67\) back into the quadratic function to find the y-coordinate, thus determining that the vertex is at \((21.67, -24.678)\). This process not only gives us the vertex but also critical insight into the parabola's properties and behavior on a graph.
The x-coordinate of the vertex is found using:
\[ x = -\frac{b}{2a} \]
This formula allows us to calculate precisely where the parabola's axis of symmetry is located. Once the x-coordinate is known, the y-coordinate can be found by plugging this value back into the original quadratic function.
For example, with \(a = 0.06\) and \(b = -2.6\), we substitute these into our vertex formula to find the x-coordinate: \[ x = -\frac{-2.6}{2 \times 0.06} = 21.67 \]
Then, we substitute \(x = 21.67\) back into the quadratic function to find the y-coordinate, thus determining that the vertex is at \((21.67, -24.678)\). This process not only gives us the vertex but also critical insight into the parabola's properties and behavior on a graph.