Chapter 2: Problem 52
In Exercises \(45-54,\) find the vertex of the parabola associated with each quadratic function. $$f(x)=0.05 x^{2}+2.5 x-1.5$$
Short Answer
Expert verified
The vertex of the parabola is \((-25, -32.75)\).
Step by step solution
01
Identify the Quadratic Function
The given quadratic function is in the standard form: \( f(x) = ax^2 + bx + c \). Here, \( a = 0.05 \), \( b = 2.5 \), and \( c = -1.5 \).
02
Formula for the Vertex of a Parabola
The vertex \((h, k)\) of a parabola given by the quadratic function \( f(x) = ax^2 + bx + c \) can be found using the formula: \( h = -\frac{b}{2a} \) and \( k = f(h) \).
03
Calculate the x-coordinate of the Vertex
Substitute \( a = 0.05 \) and \( b = 2.5 \) into the formula for \( h \): \[ h = -\frac{2.5}{2 \times 0.05} = -\frac{2.5}{0.1} = -25. \] So, the x-coordinate of the vertex is \( h = -25 \).
04
Calculate the y-coordinate of the Vertex
Substitute \( x = -25 \) into the original function to find \( k \): \[ k = f(-25) = 0.05(-25)^2 + 2.5(-25) - 1.5. \] Calculate \( (-25)^2 = 625 \), then \( 0.05 \times 625 = 31.25 \), \( 2.5 \times (-25) = -62.5 \). Thus, \( k = 31.25 - 62.5 - 1.5 = -32.75 \).
05
Identify the Vertex
The vertex of the parabola is at \( (h, k) = (-25, -32.75) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Function
When dealing with quadratic functions, it's important to understand their basic form. A quadratic function is a type of polynomial function that takes the shape of a parabola when graphed. These functions can be written in the general form as \( f(x) = ax^2 + bx + c \). Here, \( a \), \( b \), and \( c \) are constants, and \( x \) represents the variable. Quadratic functions are unique because they create symmetrical curves that open either upwards or downwards. This opening direction is dictated by the coefficient \( a \): if \( a \) is positive, the parabola opens upwards; if negative, it opens downwards. This shape helps in determining specific points of interest on the graph, such as the vertex and the axis of symmetry.
Standard Form
The standard form of a quadratic function is expressed as \( f(x) = ax^2 + bx + c \). This is a crucial format for identifying the coefficients which play a key role in solving quadratic equations and finding the vertex of a parabola. The standard form is organized to highlight the quadratic coefficient \( a \), the linear coefficient \( b \), and the constant term \( c \). Recognizing these coefficients is essential because they help determine the properties of the parabola, such as the orientation and position on the Cartesian plane.
- Orientation: Based on the sign of \( a \), the parabola's direction (upward or downward) is deduced.
- Vertex Calculation: The coefficients are plugged into formulas to calculate the vertex.
Vertex Formula
To find the vertex of a parabola described by a quadratic function in standard form \( ax^2 + bx + c \), we use the vertex formula. The vertex is represented by the coordinates \((h, k)\). The formula for calculating \( h \), the x-coordinate of the vertex, is given by:\[ h = -\frac{b}{2a} \]This formula results from identifying the axis of symmetry of the parabola. Once \( h \) is found, we substitute it back into the original quadratic function to find \( k \), the y-coordinate:\[ k = f(h) \]Understanding this formula is crucial because it allows us to directly calculate the vertex, a significant point that acts as the peak or trough of the parabola depending on its orientation.
- This formula simplifies finding the vertex without needing to complete the square, a process that can sometimes be cumbersome.
- It's a quick computational solution for determining the most important feature of a parabola.
Coordinate Calculation
The process of coordinate calculation involves determining the x and y values for the vertex of a parabola. Let's discuss how these are calculated step-by-step using the given quadratic function. First, to find the x-coordinate \( h \), apply the vertex formula:\[ h = -\frac{b}{2a} \]In our example, substituting the constants \( a = 0.05 \) and \( b = 2.5 \) provides:\[ h = -\frac{2.5}{2 \times 0.05} = -25 \]Next, calculate the y-coordinate \( k \) by substituting \( h \) back into the quadratic function \( f(x) = 0.05x^2 + 2.5x - 1.5 \):\[ k = 0.05(-25)^2 + 2.5(-25) - 1.5 \]Proceed with the calculations:
- \((-25)^2 = 625\)
- \(0.05 \times 625 = 31.25\)
- \(2.5 \times (-25) = -62.5\)