Chapter 2: Problem 52
For each polynomial (a) use Descartes' rule of signs to determine the possible combinations of positive real zeros and negative real zeros; (b) use the rational zero test to determine possible rational zeros; (c) test for rational zeros; and (d) factor as a product of linear and/or irreducible quadratic factors. $$P(x)=4 x^{4}-8 x^{3}+7 x^{2}+30 x+50$$
Short Answer
Step by step solution
Count Sign Changes for Positive Zeros
Substitute for Negative Zeros
Possible Rational Zeros
Test Possible Zeros
Factor Polynomial
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Descartes' Rule of Signs
For example, considering a polynomial such as \(P(x) = 4x^4 - 8x^3 + 7x^2 + 30x + 50\), we analyze the signs of the coefficients: +, -, +, +, +. Here, we notice two sign changes: \(+ \to -\) and \(- \to +\). According to Descartes' Rule, there could be 2 or 0 positive real roots.
To find the potential negative real roots, we substitute \(x\) with \(-x\), resulting in \(P(-x) = 4x^4 + 8x^3 + 7x^2 - 30x + 50\). The signs are +, +, +, -, +, with one sign change \(+ \to -\), indicating the possibility of 1 or 0 negative real roots.
Rational Root Theorem
Consider \(P(x) = 4x^4 - 8x^3 + 7x^2 + 30x + 50\). Here, the constant term is 50, with factors ±1, ±2, ±5, ±10, ±25, ±50, and the leading coefficient is 4, with factors ±1, ±2, ±4. Thus, the possible rational roots are the combinations of these factors as fractions: ±1, ±1/2, ±1/4, ±2, ±5, ±5/2, ±5/4, ±10, ±10/2, ±10/4, ±25, ±25/2, ±25/4, ±50, ±50/2, ±50/4.
Testing this range of values helps in narrowing down the actual rational zeros of the polynomial.
Synthetic Division
When testing, for example, the potential root \(x = -5\) against the polynomial \(P(x) = 4x^4 - 8x^3 + 7x^2 + 30x + 50\), synthetic division is used to determine if \(P(x) = 0\). When \(P(-5) = 0\), synthetic division confirms \(x + 5\) as a factor of the polynomial.
To synthesize the division, use the coefficients \(4, -8, 7, 30, 50\) in synthetic division with \(-5\) as the divisor. If the remainder is zero, \(x + 5\) is indeed a factor, helping further breakdown the polynomial.
Factoring Polynomials
For example, after confirming \(x = -5\) is a root of \(P(x) = 4x^4 - 8x^3 + 7x^2 + 30x + 50\), we use synthetic division to divide \(P(x)\) by \(x + 5\), leading to \(P(x) = (x+5)(4x^3 - 20x^2 + 7x + 10)\).
Further factorization involves checking the resulting polynomial \(4x^3 - 20x^2 + 7x + 10\) for additional factors or finding other roots. This can result either in linear factors or irreducible quadratic factors, streamlining the polynomial into simpler components.