/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 In Exercises \(45-54,\) find the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises \(45-54,\) find the vertex of the parabola associated with each quadratic function. $$f(x)=33 x^{2}-2 x+15$$

Short Answer

Expert verified
The vertex of the parabola is \( \left( \frac{1}{33}, 14.9697 \right) \).

Step by step solution

01

Identify the Coefficients

The quadratic function is given by the equation \( f(x) = 33x^2 - 2x + 15 \). Let's identify the coefficients: \( a = 33 \), \( b = -2 \), and \( c = 15 \). These will be used in the formula for the vertex of a parabola.
02

Use the Vertex Formula for the x-coordinate

The x-coordinate of the vertex for a parabola given by \( f(x) = ax^2 + bx + c \) is calculated using \( x = -\frac{b}{2a} \). Substitute the values of \( a \) and \( b \) into this formula: \[ x = -\frac{-2}{2 \times 33} = \frac{2}{66} = \frac{1}{33} \].
03

Calculate the y-coordinate

Substitute \( x = \frac{1}{33} \) back into the original function \( f(x) \) to find the y-coordinate of the vertex. \[ f\left(\frac{1}{33}\right) = 33 \left(\frac{1}{33}\right)^2 - 2 \left(\frac{1}{33}\right) + 15 \]. Simplify this to get: \[ f\left(\frac{1}{33}\right) = \frac{33}{1089} - \frac{2}{33} + 15 \]. Further simplify to find \( f\left(\frac{1}{33}\right) \).
04

Simplify the Expression

Simplify \( \frac{33}{1089} \) and \( \frac{2}{33} \): \( \frac{33}{1089} = \frac{1}{33} \). So, \[ f\left(\frac{1}{33}\right) = \frac{1}{33} - \frac{2}{33} + 15 = -\frac{1}{33} + 15 \]. The y-coordinate becomes: \[ f\left(\frac{1}{33}\right) = 15 - \frac{1}{33} \].
05

Write the Vertex Coordinates

After simplifying, the coordinates of the vertex are \( \left( \frac{1}{33}, 14.9697 \right) \), where \( 14.9697 \) is the approximate value of \( 15 - \frac{1}{33} \). Therefore, the vertex of the parabola is \( \left( \frac{1}{33}, 14.9697 \right) \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Function
A quadratic function is a type of polynomial function that is represented by the equation \( f(x) = ax^2 + bx + c \). This equation characterizes a unique curve on a graph known as a parabola. Here, \( a \), \( b \), and \( c \) are constants with \( a eq 0 \), which ensures the function is indeed quadratic.
  • The term \( ax^2 \) is the quadratic term and determines the parabola's width and the direction it opens.
  • The term \( bx \) is the linear term influencing the slope of the parabola.
  • Constant \( c \) is the y-intercept of the graph, showing where the parabola crosses the y-axis.
Understanding the structure of a quadratic function allows us to graph the parabola and locate its features like its vertex and axis of symmetry. A quadratic function's graph is always a symmetric curve, either opening upwards or downwards depending on the sign of \( a \). If \( a \) is positive, the parabola opens upwards; if negative, it opens downwards.
Vertex Formula
The vertex of a parabola is its highest or lowest point, depending on the direction in which the parabola opens. For a quadratic function \( f(x) = ax^2 + bx + c \), the vertex provides critical information about the graph. To find the vertex, we rely on the vertex formula:\[ x = -\frac{b}{2a} \]
  • This equation gives the x-coordinate of the vertex.
  • Once we have the x-coordinate, we substitute it back into the function to find the y-coordinate.
For example, in the function \( f(x) = 33x^2 - 2x + 15 \), using the formula, we find:
  • The x-coordinate as \( x = -\frac{-2}{2 \times 33} = \frac{1}{33} \).
  • To find the y-coordinate, substitute \( x = \frac{1}{33} \) into the function to get \( y \approx 14.9697 \).
Thus, the vertex of the parabola is the point \( \left( \frac{1}{33}, 14.9697 \right) \). This point is significant because it represents the minimum value of the function when the parabola opens upwards and the maximum when it opens downwards.
Parabola
A parabola is the U-shaped graphical representation of a quadratic function. It exhibits symmetry, which is one of its defining characteristics. Whether the parabola opens upwards or downwards depends on the coefficient \( a \) in the quadratic function:
  • If \( a > 0 \), the parabola opens upwards and the vertex is the minimum point.
  • If \( a < 0 \), it opens downwards and the vertex is the maximum point.
The vertex acts as the tipping point of the parabola where the direction changes. Another significant aspect of a parabola is its axis of symmetry. This is an imaginary vertical line that passes through the vertex and divides the parabola into two mirror-image halves. For the equation \( f(x) = ax^2 + bx + c \), the axis of symmetry is given by the equation \( x = \frac{-b}{2a} \).Understanding these properties helps in sketching the graph of a parabola and analyzing the behavior of quadratic functions. Whether solving optimization problems or analyzing real-world motion, parabolas play a key role across various applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.