Chapter 10: Problem 57
Evaluate each finite series. $$\sum_{n=0}^{4} 1^{n}$$
Short Answer
Expert verified
The sum of the series is 5.
Step by step solution
01
Understanding the Series
The given series is \( \sum_{n=0}^{4} 1^{n} \). This means we need to find the sum of the sequence of terms generated by raising 1 to the power of \( n \) for each \( n \) from 0 to 4.
02
Expanding the Series
Since \( 1^{n} = 1 \) for any integer \( n \), we expand the series \( \sum_{n=0}^{4} 1^{n} \) as follows: \( 1^{0} + 1^{1} + 1^{2} + 1^{3} + 1^{4} \). Since each \( 1^{n} \) is equal to 1, the expanded form becomes \( 1 + 1 + 1 + 1 + 1 \).
03
Calculating the Sum
Now, we sum the expanded terms: \( 1 + 1 + 1 + 1 + 1 = 5 \). This is the sum of the series.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
power of a number
The concept of the "power of a number" involves raising a number to an exponent. This means multiplying that number by itself a certain number of times. For example:
- If you have a base of 2 and an exponent of 3, it means you multiply 2 by itself 3 times: \(2^3 = 2 \times 2 \times 2 = 8\).
- The base number is the number you repeatedly multiply, while the exponent tells you how many times to multiply it by itself.
sequence of terms
A "sequence of terms" in mathematics is simply an ordered list of numbers. Each number in the list is called a term. These terms are typically generated using a specific rule or formula based on their position in the sequence. For example:
- A simple sequence could be the list of even numbers: 2, 4, 6, 8, ..., where each term can be determined by the formula \(2n\).
- Another sequence might be the list of powers of 2: 1, 2, 4, 8, ..., where each term is \(2^n\).
sum of a series
The "sum of a series" refers to the result obtained when you add together all the terms of a sequence. A finite series, like the one in the exercise, has a specific beginning and end, meaning it consists of a limited number of terms. To compute the sum, simply add each term in the sequence sequentially. Here's how that works:
- Consider the example: \(1 + 2 + 3 + 4 + 5\). The sum here is 15.
- For the exercise series: \(1^{0} + 1^{1} + 1^{2} + 1^{3} + 1^{4}\), since each term equals 1, the sum is \(1 + 1 + 1 + 1 + 1 = 5\).