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Expand each expression using the Binomial theorem. $$(a-7 b)^{3}$$

Short Answer

Expert verified
The expression expands to \(a^3 - 21a^2b + 147ab^2 - 343b^3\).

Step by step solution

01

Identify the Formula

The Binomial theorem states that \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k}b^k\). In this expression, we need to expand \((a - 7b)^3\). Here, \(a\) is \(a\), \(b\) is \(-7b\), and \(n\) is 3.
02

Calculate Binomial Coefficients

For \((a - 7b)^3\), we need the binomial coefficients for \(n = 3\). These are obtained from \(\binom{3}{k}\) as follows:- \(\binom{3}{0} = 1\)- \(\binom{3}{1} = 3\)- \(\binom{3}{2} = 3\)- \(\binom{3}{3} = 1\)We'll use these coefficients in the next step.
03

Expand the Expression

We apply the binomial theorem:\[(a - 7b)^3 = \binom{3}{0} a^{3-0}(-7b)^0 + \binom{3}{1} a^{3-1}(-7b)^1 + \binom{3}{2} a^{3-2}(-7b)^2 + \binom{3}{3} a^{3-3}(-7b)^3\]Simplifying each term:- \(\binom{3}{0} a^3 = 1 \cdot a^3 = a^3\)- \(\binom{3}{1} a^2(-7b) = 3 \cdot a^2 \cdot (-7b) = -21a^2b\)- \(\binom{3}{2} a^1(-7b)^2 = 3 \cdot a \cdot 49b^2 = 147ab^2\)- \(\binom{3}{3} (-7b)^3 = 1 \cdot (-343b^3) = -343b^3\)
04

Assemble the Final Expression

Now, combine the simplified terms to get:\[a^3 - 21a^2b + 147ab^2 - 343b^3\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficients
Binomial coefficients are the numbers that appear in the expansion of a binomial raised to a power, such as \((a+b)^n\). In mathematical terms, they are represented as \(\binom{n}{k}\), where \(n\) is the power to which the binomial is raised and \(k\) is the position of a term in the expansion. These coefficients tell us how many ways we can choose \(k\) elements from a set of \(n\) elements—hence they are also called "combinatorial numbers".
  • The binomial coefficient \(\binom{n}{k}\) can be calculated using the formula: \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\).
  • "!" denotes a factorial, meaning the product of all positive integers up to that number.
In our example problem, we calculated binomial coefficients for \((a - 7b)^3\). Here, \(n\) is 3, so the necessary coefficients are \(\binom{3}{0} = 1\), \(\binom{3}{1} = 3\), \(\binom{3}{2} = 3\), and \(\binom{3}{3} = 1\). These coefficients help distribute the powers of the terms \(a\) and \(-7b\) across each part of the polynomial expression.
Polynomial Expansion
Polynomial expansion using the Binomial Theorem provides us with a systematic way to expand expressions like \((a + b)^n\). The formula \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\) helps distribute the terms in a precise manner.When applying the theorem to expand \((a - 7b)^3\), we replace \(b\) with \(-7b\). The expansion becomes:\[(a - 7b)^3 = \binom{3}{0} a^3 (-7b)^0 + \binom{3}{1} a^2 (-7b)^1 + \binom{3}{2} a^1 (-7b)^2 + \binom{3}{3} a^0 (-7b)^3\]
  • The first term is \(a^3\), the purest form of \(a\) raised to the power of 3.
  • The second term combines \(a^2\) with \(-7b\), resulting in \(-21a^2b\).
  • The third term involves \(a\) and \((-7b)^2\), giving \(147ab^2\).
  • The final term is \((-7b)^3\), which results in \(-343b^3\).
This methodical approach ensures no step is overlooked, guaranteeing the expansion is accurate.
Algebraic Expressions
Understanding algebraic expressions is crucial when working with the Binomial Theorem. An algebraic expression is a combination of numbers, variables, and arithmetic operations. Variables are symbols used to represent unknown values or quantities, like \(a\) and \(b\) in our expression. When dealing with expressions like \((a - 7b)^3\), it's important to treat each variable carefully:
  • Each expression consists of terms such as \(a^3\), which is just the variable \(a\) multiplied by itself three times.
  • In this problem, \(-7b\) is handled as a single entity. So, \((-7b)^2\) becomes \(49b^2\) when calculated, and \((-7b)^3\) results in \(-343b^3\).
By comprehending these interactions, you can simplify and combine terms logically and methodically. Remember, practicing these operations and expanding expressions step-by-step greatly improves your proficiency in algebra.

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