Chapter 1: Problem 73
In Exercises \(53-76\), graph the piccewise-defined functions. State the domain and range in interval notation. Determine the intervals where the function is increasing, decreasing, or constant. $$f(x)=\left\\{\begin{array}{ll} x+3 & x \leq-2 \\ |x| & -2< x< 2 \\ x^{2} & x \geq 2 \end{array}\right.$$
Short Answer
Step by step solution
Analyze Domain
Analyze Range
Intervals of Increase, Decrease, and Constant Specific Segments
Graphing the Function
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Function Domain
Let's break it down for the given piecewise function:
- For the segment \( f(x) = x + 3 \), the domain is \((-\infty, -2]\). This covers all \( x \) values less than or equal to -2.
- For the segment \( f(x) = |x| \), the domain is \((-2, 2)\). This only includes \( x \) values between -2 and 2.
- For the segment \( f(x) = x^2 \), the domain is \([2, \infty)\). This entails all \( x \) values greater than or equal to 2.
Exploring the Function Range
- For \( f(x) = x + 3 \) when \( x \leq -2 \), the smallest output starts at 1 and decreases without bound as \( x \) goes to \(-\infty\). Therefore, the range for this part is \((-\infty, 1]\).
- For \( f(x) = |x| \) within \(-2 < x < 2\), the outputs start from slightly above 0 and rise just below 2. Thus, the range here is \([0, 2)\).
- For \( f(x) = x^2 \) where \( x \geq 2 \), the outputs begin at 4 and increase indefinitely as \( x \) increases. This gives a range of \([4, \infty)\).
Identifying Increasing and Decreasing Intervals
- The function \( f(x) = x + 3 \) decreases for \( x \leq -2 \). The slope is negative, meaning as \( x \) increases, \( f(x) \) decreases.
- In \( f(x) = |x| \), there is a notable V-shaped behavior:
- Between \(-2 \) and 0, the function decreases as \( x \) approaches 0.
- Between 0 and 2, the function increases as \( x \) moves away from 0.
- For \( f(x) = x^2 \), the function is increasing when \( x \geq 2 \) due to its upward concave shape.
Graphing Piecewise Functions
- Start by graphing \( f(x) = x + 3 \) for \( x \leq -2 \), noting a downward slope. This segment starts with a closed circle at \( x = -2 \).
- Next, plot \( f(x) = |x| \) for \(-2 < x < 2\). This forms a V-shape, starting from a point just above 0, increasing as \( x \) moves towards 2.
- Finally, graph \( f(x) = x^2 \) for \( x \geq 2 \). Start at the point (2, 4) and show an upward curve, typical of a parabola.