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Transform the function into the form \(f(x)=c(x-h)^{2}+k,\) where \(c, k,\) and \(h\) are constants, by completing the square. Use graph-shifting techniques to graph the function. $$f(x)=x^{2}+2 x-2$$

Short Answer

Expert verified
The function is \(f(x) = (x+1)^2 - 3\) and the graph is shifted left 1 unit and down 3 units.

Step by step solution

01

Identify the Quadratic Coefficients

First, identify the quadratic expression in the form of \(ax^2 + bx + c\). For the given function \(f(x) = x^2 + 2x - 2\), it is already in this form, with \(a = 1\), \(b = 2\), and \(c = -2\).
02

Complete the Square

To transform the expression \(x^2 + 2x - 2\) into the vertex form, \((x-h)^2 + k\), start by focusing on the \(x^2 + 2x\) part. To "complete the square," take the coefficient of \(x\), which is 2, divide it by 2 to get 1, and then square it to get \(1^2 = 1\). Add and subtract this square inside the function: \(f(x) = (x^2 + 2x + 1) - 1 - 2\).
03

Simplify the Expression

Rewrite the quadratic part as a square and simplify: \(f(x) = (x+1)^2 - 3\). Now the function is in the form \(c(x-h)^2 + k\) where \(c = 1\), \(h = -1\), and \(k = -3\).
04

Graph-shifting Techniques

The expression \(f(x) = (x + 1)^2 - 3\) indicates a parabola with vertex \((-1, -3)\). The graph should be shifted 1 unit to the left and 3 units downward from the standard parabola \(y = x^2\). Since \(c = 1\), the parabola opens upwards without any vertical stretch or compression.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graph Shifting
Graph shifting is a powerful technique to understand how a function changes position on the coordinate plane. In algebra, particularly with quadratics, shifting allows us to visualize transformations. When we look at the function transformation given, \(f(x) = (x + 1)^2 - 3\), we can see the effects of graph shifting.
  • The term \((x + 1)\) indicates a horizontal shift. Since it is \(+1\), the plot of the parabola shifts 1 unit to the left.
  • The \(-3\) at the end of the function causes a vertical shift, moving the whole graph down by 3 units.
  • These shifts help us locate the new vertex at \((-1, -3)\) from the position of a default parabola \(y = x^2\) whose vertex is at the origin \((0, 0)\).
These graph transformations help in quickly sketching the graph and understanding the behavior of the function relative to the standard \(y = x^2\) graph.
Quadratic Equations
Quadratic equations generally take the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants. They are interesting because their graph forms a parabola, a common curve you'll often encounter. In this exercise, our focus is on converting the quadratic equation into a different form, known as the vertex form.Key characteristics of a quadratic equation are:
  • The midpoint of the parabola (vertex) is a crucial point of symmetry.
  • Solutions to the equation (if exist) are called roots or zeros of the quadratic, which are the points where the graph intersects the x-axis.
  • The parabola can open upwards if \(a > 0\) or downwards if \(a < 0\).
Understanding these basics about quadratic equations helps in solving and graphing these equations with ease and efficiency.
Parabola Vertex Form
The vertex form of a quadratic function is a useful format that reveals the vertex's position on the graph. The form is \(f(x) = c(x-h)^2 + k\), where \(h, k\) represent the vertex's coordinates, and \(c\) affects the parabola's width and direction.Here's why it's useful:
  • Visible vertex: You can easily identify the vertex of the parabola, which makes sketching the graph quicker.
  • Simplifies graph transformations: Adjusting \(h\) and \(k\) allows for direct control of horizontal and vertical shifts.
  • Determine direction: The sign of \(c\) helps you know if the parabola opens up (when \(c > 0\)) or down (when \(c < 0\)).
By completing the square, we are transforming a standard quadratic equation into this more intuitive form. For example, converting \(f(x) = x^2 + 2x - 2\) into \((x + 1)^2 - 3\). This immediately tells us the vertex is at \((-1, -3)\), and the parabola opens upwards.

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