/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 70 Explain the mistake that is made... [FREE SOLUTION] | 91Ó°ÊÓ

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Explain the mistake that is made. Use symmetry to help you graph \(x^{2}=y-1\) Solution: Replace \(x\) with \(-x\) \((-x)^{2}=y-1\) Simplify. \(x^{2}=y-1\) \(x^{2}=y-1\) is symmetric with respect to the \(x\) -axis. Determine points that lie on the graph in quadrant I. $$\begin{array}{|c|c|c|}\hline y & x^{2}=y-1 & (x, y) \\\\\hline 1 & 0 & (0,1) \\\ \hline 2 & 1 & (1,2) \\\\\hline 5 & 2 & (2,5) \\\\\hline\end{array}$$ Symmetry with respect to the \(x\) -axis implies that (0,-1) \((1,-2),\) and (2,-5) are also points that lie on the graph. (GRAPH CAN'T COPY) This is incorrect. What mistake was made?

Short Answer

Expert verified
The mistake was assuming symmetry with the \(x\)-axis, when it is actually symmetric with the \(y\)-axis.

Step by step solution

01

Identify the Error in the Use of Symmetry

The solution states that the equation \(x^2 = y - 1\) is symmetric with respect to the \(x\)-axis. However, for a graph to be symmetric with respect to the \(x\)-axis, replacing \(y\) with \(-y\) should yield an equivalent equation. Let's check this: replacing \(y\) with \(-y\) gives \(x^2 = -y - 1\), which is not equivalent to \(x^2 = y - 1\). Thus, the equation is not symmetric with respect to the \(x\)-axis.
02

Identify Correct Symmetry

The equation \(x^2 = y - 1\) can be rewritten as \(y = x^2 + 1\). This form shows it is a parabola opening upwards. Parabolas of this form are symmetric with respect to the \(y\)-axis, not the \(x\)-axis. The graph is symmetric if replacing \(x\) with \(-x\) gives an equivalent equation: \((-x)^2 = x^2\), confirming \(y = x^2 + 1\) is symmetric with respect to the \(y\)-axis.
03

Analyze Given Points

The solution lists points (0,1), (1,2), (2,5). These are correctly calculated from the table where \(y = x^2 + 1\). However, the extension to (0,-1), (1,-2), (2,-5) based on supposed symmetry with the \(x\)-axis is incorrect; such points are not on the graph of \(y = x^2 + 1\).
04

Correct the Misunderstanding

The graph should only include points symmetric about the \(y\)-axis. Therefore, the correct points are those derived from \(y = x^2 + 1\) without considering a faulty \(x\)-axis symmetry. Hence, correct symmetry points include (0,1), (1,2), and (2,5), along with their reflections over the \(y\)-axis (-1,2) and (-2,5), rather than any over the \(x\)-axis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

x-axis symmetry
To determine if a graph is symmetric with respect to the x-axis, a simple test involves replacing every instance of \(y\) in the equation with \(-y\). If the resulting equation is equivalent to the original, the graph is x-axis symmetric. For example, consider an equation of the form \(y^2 = x\). By changing \(y\) to \(-y\), we get \((-y)^2 = x\), simplifying to \(y^2 = x\). Since these equations match, this implies x-axis symmetry.

In the exercise, the equation was mislabeled as having x-axis symmetry. When trying to replace \(y\) with \(-y\) in \(x^2 = y - 1\), we got \(x^2 = -y - 1\), which is not equivalent. Thus, there is no x-axis symmetry. It's crucial to remember that for a graph to exhibit x-axis symmetry, the y-values must mirror across the x-axis, creating a direct reflection.
y-axis symmetry
For a graph to be symmetric with respect to the y-axis, replacing \(x\) with \(-x\) should produce an equivalent equation. Consider the function \(y = x^2 + 1\). By substituting \(-x\) for \(x\), we have \(y = (-x)^2 + 1\), which equals \(y = x^2 + 1\). Therefore, the equations match, demonstrating y-axis symmetry.

This reflects that the parabola described by the equation \(y = x^2 + 1\) is evenly balanced around the y-axis, meaning any point \((x, y)\) on the parabola has a mirror point \((-x, y)\). Understanding y-axis symmetry helps accurately depict and understand parabola shapes, as they consistently reflect over the vertical line \(x = 0\).

In problems, correctly identifying y-axis symmetry ensures no mistakes like attributing reflections across the wrong axis.
graphing parabolas
Graphing parabolas involves several key steps to capture their correct shape and symmetry. A fundamental form of a parabola is expressed as \(y = a(x-h)^2 + k\), where \((h, k)\) represents the vertex, and \(a\) determines the width and direction of the parabola.

For the simple form \(y = x^2 + 1\), the vertex is \( (0,1) \) since \(h=0\) and \(k=1\). The positive coefficient of \(x^2\) (in this case 1) indicates that the parabola opens upwards.

To graph it, start by plotting the vertex. Then, choose x-values (positive and negative) to find corresponding y-values, plotting the points \((x,y)\) and their symmetrical counterparts \((-x,y)\) due to y-axis symmetry. For instance, points like \((1,2)\) and \((-1,2)\) arise from squaring symmetric x-values.

Connect these points with a smooth curve, ensuring the parabola's arms extend upwards, maintaining the shape determined by the equation. Recognizing axis symmetry simplifies these steps, offering a guide on point placement and graph balance.

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