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Calculate the distance between the given points, and find the midpoint of the segment joining them. $$(-3,-1) \text { and }(-7,2)$$

Short Answer

Expert verified
The distance is 5 units and the midpoint is (-5, 0.5).

Step by step solution

01

Distance Formula Setup

To find the distance between two points \(x_1, y_1\) and \(x_2, y_2\), we use the distance formula: \[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]. Substitute \((-3, -1)\) for \(x_1, y_1\) and \((-7, 2)\) for \(x_2, y_2\).
02

Calculate Differences

Compute the differences \((x_2 - x_1)\) and \((y_2 - y_1)\): \((-7 + 3) = -4\) and \((2 + 1) = 3\).
03

Apply the Distance Formula

Plug the differences into the distance formula: \[d = \sqrt{(-4)^2 + (3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5\]. The distance between the points is 5 units.
04

Midpoint Formula Setup

To find the midpoint of the segment joining two points \(x_1, y_1\) and \(x_2, y_2\), use the midpoint formula: \((\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})\).
05

Calculate Midpoint

Substitute the given points into the formula: \((\frac{-3 + (-7)}{2}, \frac{-1 + 2}{2}) = (\frac{-10}{2}, \frac{1}{2}) = (-5, 0.5)\). The midpoint is \((-5, 0.5)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Midpoint Formula
When you need to find a point that lies exactly in the middle of a line segment joining two given points, the midpoint formula comes in handy. Imagine you have two points in the coordinate plane,
  • Point 1: \((x_1, y_1)\)
  • Point 2: \((x_2, y_2)\)
The midpoint is simply the average of the x-coordinates and the y-coordinates of the given points. The formula to find the midpoint is:
  • \(\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)\)
Think of this as the spot that has balanced the x-values and y-values from both given points. For example, using our coordinates \((-3, -1)\) and \((-7, 2)\), the calculations would be:
  • x-coordinate of the midpoint = \((\frac{-3 + (-7)}{2} = -5)\)
  • y-coordinate of the midpoint = \((\frac{-1 + 2}{2} = 0.5)\)
Thus, the midpoint is \((-5, 0.5)\). Finding the midpoint gives you the center of the line segment in question.
Coordinate Geometry
Coordinate Geometry is an exciting field that helps us use algebra to describe geometric figures in a plane. It is a way to connect algebra and geometry—offering methods for describing locations and distances between points with precision.
The fundamental elements of coordinate geometry include:
  • Points: These are presented in pairs such as \( (x, y) \) indicating their position on the plane.
  • Lines and Segments: Defined by two points, and important for applications of distance and midpoint formulas.
  • Planes: Coordinate planes allow us to visualize and compute complex calculations easily.
In the real-world, coordinate geometry is key to tasks like mapping, navigation, and even in computer graphics. For example, knowing how figures relate and how far they are from each other makes it easier to map routes or design video game landscapes. Concepts like the distance and midpoint formulas are part of this broader picture, helping you to solve problems involving points in a plane.
Distance Between Points
Understanding how to find the distance between two points is essential in coordinate geometry. This concept involves determining how far apart two points lie on a plane, which can be visualized as the length of the straight line connecting them.
The distance formula is derived from the renowned Pythagorean theorem and is given by:
  • \(d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)
This allows you to calculate the distance by first finding the differences in the x and y coordinates, squaring them, adding those squares, and finally taking the square root of the sum. Applying it to the exercise, the calculation for the coordinates \((-3, -1)\) and \((-7, 2)\) resulted in:
  • \((x_2 - x_1) = -4\)
  • \((y_2 - y_1) = 3\)
  • Thus, \(d = \sqrt{(-4)^2 + (3)^2} = \sqrt{25} = 5\) units.
This is a foundational skill in math that helps understand spatial relationships, important in fields like physics, engineering, and architecture.

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