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Find an equation of a line that passes through the point \((B, A-1)\) and is parallel to the line \(A x+B y=C\). Assume that \(B\) is not equal to zero.

Short Answer

Expert verified
The equation of the line is \(Ax + By = 2AB - B\).

Step by step solution

01

Identify the Slope of the Given Line

The equation of the line given is \(Ax + By = C\). To find the slope \(m\) of this line, we rearrange the equation into the slope-intercept form \(y = mx + b\). First, solve for \(y\): \(By = -Ax + C\). Divide by \(B\) to get \(y = -\frac{A}{B}x + \frac{C}{B}\). Thus, the slope of the line is \(-\frac{A}{B}\).
02

Write the Equation of the Parallel Line

Lines that are parallel have the same slope. Therefore, the line we are looking for has the same slope of \(-\frac{A}{B}\). We'll use the point-slope form of a line equation: \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is the point through which the line passes, \((B, A-1)\), and \(m\) is the slope, \(-\frac{A}{B}\).
03

Substitute Point and Slope into the Equation

Substitute the point \((B, A-1)\) and the slope \(-\frac{A}{B}\) into the point-slope form: \(y - (A-1) = -\frac{A}{B}(x - B)\).
04

Simplify the Equation

Distribute the slope on the right side: \(y - A + 1 = -\frac{A}{B}x + \frac{A}{B}B\). Simplifying, \(y - A + 1 = -\frac{A}{B}x + A\).
05

Rearrange to Standard Form

Combine like terms and rearrange the equation to get it in standard form: \(\frac{A}{B}x + y = 2A - 1\). Multiply all terms by \(B\) to clear the fraction: \(Ax + By = B(2A - 1)\). Thus, the equation of the line is \(Ax + By = 2AB - B\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope-Intercept Form
The slope-intercept form of a linear equation is one of the most popular ways to express equations of lines. It is given by the formula \(y = mx + b\), where \(m\) represents the slope of the line and \(b\) represents the y-intercept, the point where the line crosses the y-axis. This form is exceptionally useful because it provides immediate insight into the steepness (slope) and starting point (y-intercept) of a line.

To convert an equation to the slope-intercept form, you need to solve for \(y\). This often involves rearranging the terms. For example, given the equation \(Ax + By = C\), we solve for \(y\) by isolating it on one side:
  • First, move \(Ax\) to the other side: \(By = -Ax + C\)
  • Then, divide every term by \(B\): \(y = -\frac{A}{B}x + \frac{C}{B}\)
Here, \(-\frac{A}{B}\) is the slope, and \(\frac{C}{B}\) is the y-intercept.
Point-Slope Form
The point-slope form of a line equation is quite convenient when you know one point on the line and its slope. It is expressed as \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) are the coordinates of the given point, and \(m\) is the slope.

This form makes it easy to write the equation of a line when you have a point and a slope, as you directly plug these values into the formula. For example, to write the equation of a line parallel to another line with known slope, you:
  • Identify the slope \(m\)
  • Insert the point values \((x_1, y_1)\) into the formula
This process gives you the precise equation of your desired line, without the need for additional rearranging or calculations.
Standard Form
The standard form of a line is expressed as \(Ax + By = C\), where \(A\), \(B\), and \(C\) are integers, and \(A\) and \(B\) are not both zero. This form is often preferred when you need an integer-based format for equations, such as in systems of equations.

To convert another form into standard form, you'll want to eliminate any fractions and ensure that the coefficients are integers:
  • First, move all terms involving variables to one side of the equation
  • Combine like terms, if necessary
  • Adjust coefficients to be integer values by multiplying through, if needed
For example, from a point-slope form like \(y - (A-1) = -\frac{A}{B}(x - B)\), you rearrange terms and multiply by \(B\) to clear the fraction, resulting in \(Ax + By = 2AB - B\). This process highlights the flexibility and straightforward nature of the standard form when applied correctly.

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