Chapter 0: Problem 109
Solve the inequality \(\left|\frac{x}{x+1}\right|<1\) by graphing both sides of the inequality, and identify which \(x\) -values make this statement true.
Short Answer
Expert verified
The solution is \( -\frac{1}{2} < x < \infty \), excluding \( x = -1 \).
Step by step solution
01
Express the Inequality
Start by rewriting the inequality \( \left|\frac{x}{x+1}\right| < 1 \). The absolute value inequality can be split into two inequalities: \( -1 < \frac{x}{x+1} < 1 \). This gives us two separate inequalities to solve: \( \frac{x}{x+1} > -1 \) and \( \frac{x}{x+1} < 1 \).
02
Solve the First Inequality
Solve \( \frac{x}{x+1} > -1 \). Cross multiply to get \( x > -x - 1 \). Combine like terms to obtain \( 2x > -1 \). Dividing both sides by 2, we have \( x > -\frac{1}{2} \).
03
Solve the Second Inequality
Solve \( \frac{x}{x+1} < 1 \). Cross multiply to get \( x < x + 1 \). Simplifying gives the inequality \( 0 < 1 \), which is trivially true for all values within the domain where the inequality is valid.
04
Determine the Domain
The expression \( \frac{x}{x+1} \) is undefined at \( x = -1 \) because the denominator becomes zero. This means our solution must exclude \( x = -1 \).
05
Combine Conditions
From the previous steps, we've got the inequality \( x > -\frac{1}{2} \) except for \( x = -1 \). Combine these, and the solution to the inequality is \( -\frac{1}{2} < x < \infty \), excluding \( x = -1 \).
06
Graph the Expression
For graphing, plot the graph of \( y = \left|\frac{x}{x+1}\right| \) and a horizontal line \( y = 1 \). The solution region is where the graph of the function is below the line \( y = 1 \). This will be between \( x = -\frac{1}{2} \) and infinity, without \( x = -1 \). After identifying the graph's intersections and regions, label these appropriately.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Absolute Value
The concept of absolute value relates to the distance of a number from zero on the number line, without considering direction. This means it is always non-negative.
In mathematical terms, the absolute value of a number \( x \) is denoted as \( |x| \) and can be defined as:
Consider the inequality \( \left| \frac{x}{x+1} \right| < 1 \). Solving it involves understanding that the expression inside the absolute value must stay within the range of -1 and 1. This gives us two simultaneous inequalities:
In mathematical terms, the absolute value of a number \( x \) is denoted as \( |x| \) and can be defined as:
- \( |x| = x \) if \( x \geq 0 \)
- \( |x| = -x \) if \( x < 0 \)
Consider the inequality \( \left| \frac{x}{x+1} \right| < 1 \). Solving it involves understanding that the expression inside the absolute value must stay within the range of -1 and 1. This gives us two simultaneous inequalities:
- \( -1 < \frac{x}{x+1} < 1 \)
Graphing Inequalities
Graphing inequalities involves representing the solution set of an inequality on a number line or a coordinate plane. It helps visualize which part of the number line or plane satisfies the inequality. For inequalities involving absolute values, such as \( \left| \frac{x}{x+1} \right| < 1 \), the process includes plotting the expressions on a graph and looking for regions.
Here’s a simple way to graph:
Graphing thus aids in confirming algebraic solutions and understanding where inequalities hold true.
Here’s a simple way to graph:
- Identify the function and the constant on the other side of the inequality. Here, we graph \( y = \left| \frac{x}{x+1} \right| \) and the line \( y = 1 \).
- The inequality shows we want the function's value to remain below 1, so we find where the graph dips below the line \( y = 1 \).
- Mark the points where the graph intersects \( y = 1 \). These are critical as they can signal where the inequality changes.
- Shade the region satisfying the inequality, considering the domain restrictions.
Graphing thus aids in confirming algebraic solutions and understanding where inequalities hold true.
Domain in Mathematics
The domain of a function is the set of all possible input values (\( x \)-values) for which the function is defined. It's crucial to determine the domain because it tells us where the function can actually operate.
For the expression \( \frac{x}{x+1} \), the key issue is the denominator:\
It can't be zero because division by zero is undefined. This gives the constraint \( x eq -1 \) because when \( x = -1 \), the denominator \( x+1 \) becomes zero.
Here's how to determine the domain for these functions:
Understanding the domain simplifies the solution process and prevents errors related to undefined values during the solution of an inequality.
For the expression \( \frac{x}{x+1} \), the key issue is the denominator:\
It can't be zero because division by zero is undefined. This gives the constraint \( x eq -1 \) because when \( x = -1 \), the denominator \( x+1 \) becomes zero.
Here's how to determine the domain for these functions:
- Look for values where the denominator or any square root becomes zero or negative.
- Exclude these critical values from the domain.
Understanding the domain simplifies the solution process and prevents errors related to undefined values during the solution of an inequality.