Chapter 12: Problem 14
Find \((2 y-7)^{2}\) A. \(4 y^{2}+49\) B. \(4 y^{2}+28 y+49\) C. \(4 y^{2}-28 x+49\) D. \(4 y^{2}-49\)
Short Answer
Expert verified
The answer is B: \(4y^2 + 28y + 49\).
Step by step solution
01
Identify the Expression
We need to simplify the expression \((2y-7)^2\). This expression is a binomial squared, which can be expanded using the binomial theorem.
02
Apply the Binomial Expansion Formula
Recall that \((a-b)^2 = a^2 - 2ab + b^2\). Here, the expression is \((2y-7)^2\), so \(a = 2y\) and \(b = 7\).
03
Calculate Each Term
First, find \(a^2\), which is \((2y)^2 = 4y^2\). Next, find the term \(-2ab\), which is \(-2(2y)(7) = -28y\). Finally, find \(b^2\), which is \(7^2 = 49\).
04
Combine the Terms
Combine the calculated terms: \(4y^2 - 28y + 49\).
05
Verify the Answer
Compare the combined terms with the given options. The correct simplified form from our calculation is \(4y^2 - 28y + 49\), which matches option B.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Binomial Theorem
The binomial theorem is a powerful tool in algebra that helps in expanding algebraic expressions raised to a power. Specifically, it provides a formula for expanding expressions like \((x + y)^n\), where these expressions are referred to as binomials because they contain two terms. The theorem states: \[(x + y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k} y^k\] Here, \(\binom{n}{k}\) are the binomial coefficients, and they can be found using Pascal's Triangle or by using the formula \(\binom{n}{k} = \frac{n!}{k!(n-k)!} \).
The beauty of the binomial theorem is that it simplifies calculations:
The beauty of the binomial theorem is that it simplifies calculations:
- It allows us to expand expressions without multiplying every term by every other term repeatedly.
- It provides a systematic approach to expanding binomials to any power, making it easier to handle complex algebraic problems.
Demystifying Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operators (like + or −). They form the building blocks of algebra. In the expression \((2y-7)^2\), we have a binomial—meaning two different terms are combined using operations.
When dealing with algebraic expressions:
When dealing with algebraic expressions:
- It is important to identify terms and coefficients. For example, in \(2y\), "2" is the coefficient of \(y\).
- Understanding the operations like addition, subtraction (in this case, the subtraction in \(2y - 7\)), multiplication, and division is crucial. Each operation dictates how terms interact in the expression.
Exploring Polynomial Expansion
Polynomial expansion is a technique used to express a polynomial, such as a binomial, to a power in its fully expanded form. The initial binomial \((2y-7)^2\) becomes a polynomial after expansion. Expanding this expression involves finding and combining several terms.
- The first step involves identifying each term to be expanded: \( (2y)^2 \) gives \( 4y^2 \), \( -2(2y)(7) \) results in \(-28y\), and \( 7^2 \) equals \( 49 \).
- Once these terms are calculated, they are combined to form a polynomial: \( 4y^2 - 28y + 49 \).