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Multiply. $$\left(5 y^{2}+8 y-2\right)(3 y-8)$$

Short Answer

Expert verified
The result of the multiplication is \(15y^3 - 16y^2 - 70y + 16\).

Step by step solution

01

- Apply Distributive Law to the First Term

Apply the distributive law of multiplication over addition to the first term of the first binomial. This means multiplying the first term, \(5y^2\) of \((5y^2 + 8y - 2)\) with each term in the second binomial \((3y - 8)\). This gives us \((15y^3 - 40y^2)\).
02

- Apply Distributive Law to the Second Term

Repeat the process for the second term of the first binomial, \(8y\). Multiply it with each term in the second binomial, giving \((24y^2 - 64y)\).
03

- Apply Distributive Law to the Third Term

Finally, repeat this process with the last term in the first binomial, \(-2\), resulting in \(-6y + 16\).
04

- Combine Like Terms

Combine all the obtained expressions from the previous steps. This leaves us with the polynomial \(15y^3 - 40y^2 + 24y^2 - 64y - 6y + 16\). Combine like terms to simplify this expression to \(15y^3 - 16y^2 - 70y + 16\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distributive Law
The Distributive Law is a foundational principle in algebra that allows us to multiply a single term across a bracketed expression. When faced with a polynomial multiplication task like

\((5y^2 + 8y - 2)(3y - 8)\),

we apply the distributive law to break down the process step by step.For each term in the first polynomial, multiply it by every term in the second polynomial.
  • For \(5y^2\), multiply it with \(3y\) and \(-8\) to get \(15y^3\) and \(-40y^2\).
  • Next, multiply \(8y\) by each term in \(3y - 8\), obtaining \(24y^2\) and \(-64y\).
  • For the final term, \(-2\), multiply it across \(3y - 8\) to get \(-6y\) and \(+16\).
The distributive law turns a complex equation into smaller, manageable pieces.
Combining Like Terms
Once you have applied the distributive law, you'll end up with a list of terms:

\(15y^3 - 40y^2 + 24y^2 - 64y - 6y + 16\).

Each of these terms might have the same variable part, known as "like terms."The goal in this step is to add or subtract the coefficients of the like terms.
  • Identify terms with the same variable degree, like \(y^2\) or \(y\).
  • Combine \(-40y^2\) and \(24y^2\) to get \(-16y^2\).
  • For the \(y\) terms, combine \(-64y\) and \(-6y\) to obtain \(-70y\).
This process reduces redundancy and makes the polynomial easier to interpret.
Expression Simplification
Expression Simplification is the final step that consolidates all previous work into a neat, concise format. After combining like terms, you get:

\(15y^3 - 16y^2 - 70y + 16\).

Simplifying means writing the polynomial in its most straightforward form possible, arranged by degree of terms, usually starting with the highest.
  • Notice how this expression now has fewer terms than what we started with.
  • The expression is ordered from the highest degree \(y^3\) to the constant.
Simplification ensures clarity, allowing you to easily see the behavior and characteristics of the polynomial.

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