/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 If a 56 -gram serving of pasta c... [FREE SOLUTION] | 91Ó°ÊÓ

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If a 56 -gram serving of pasta contains 7 g of protein, how many grams of protein are contained in a 454 -gram box of the pasta?

Short Answer

Expert verified
The amount of protein in a 454-gram box of pasta is approximated to 56.7 grams (rounded to the nearest tenth).

Step by step solution

01

Identify the known ratio

The known ratio here is that 56 grams of pasta contains 7 grams of protein. We can set '56 grams of pasta' to '7 grams of protein' with the goal to convert this ratio to a 454-gram box of the pasta.
02

Set a proportion

To find out the grams of protein in a 454-gram box of pasta, a proportion can be set up. Using cross-multiplication, this gives \( \frac{56}{7} = \frac{454}{x} \), where \( x \) denotes the unknown quantity of protein in grams.
03

Solve for the unknown

Now it's a straightforward calculation to solve for \( x \). This follows the rule of cross-multiplication: \( 56 * x = 454 * 7 \), which simplifies to \( x = \frac{454 * 7}{56} \). Calculate this to find the value of \( x \) - the number of protein grams in a 454-gram box of pasta.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cross-Multiplication
Cross-multiplication is an essential technique in solving proportion problems in algebra. It simplifies the comparison between two ratios by multiplying the numerator of one ratio with the denominator of the other, and vice versa. This method is particularly useful when one of the four values in two sets of ratios is unknown.

Let's apply this to the given problem. We have a known ratio of 56 grams of pasta to 7 grams of protein, and we want to find out how much protein is in a 454-gram box of pasta. Setting up the ratios, we get \( \frac{56}{7} = \frac{454}{x} \) and apply cross-multiplication to solve for \( x \), our unknown. By multiplying across the equal sign - 56 times \( x \) on one side and 454 times 7 on the other - we can effectively find the amount of protein in the larger box of pasta. This method bypasses more complex algebraic manipulations and offers a straightforward path to the solution.
Ratio and Proportion
Ratio and proportion are foundational concepts in mathematics that describe the relationship between quantities. A ratio compares two numbers, showing how much of one thing there is compared to another. Proportion, on the other hand, is an equation that indicates that two ratios are equivalent.

In the context of our problem, the ratio of pasta to protein is established, and we use proportion to scale that ratio up to the new quantity of pasta. By setting the two ratios equal—\( \frac{56}{7} \) for the initial amount and \( \frac{454}{x} \) for the new amount—we are creating a proportion. This proportion allows us to calculate the unknown quantity by showing that the ratio of grams of pasta to grams of protein remains constant, despite the different amounts involved.
Algebraic Problem-Solving Methods
Algebraic problem-solving methods are systematic approaches used to find the solution to equations involving unknown variables. It is vital to take a step-by-step approach to break down complex problems into manageable parts. For proportion problems, identifying the known ratio and setting up the proportion correctly are critical first steps.

Once we have our proportion—like the \( \frac{56}{7} = \frac{454}{x} \) from the pasta problem—we switch to the computation phase. We apply algebraic techniques, such as cross-multiplication, to isolate the variable and solve for it. In our case, the algebraic manipulation leads to \( x = \frac{454 * 7}{56} \) that upon simplification gives us the answer. Effective problem-solving in algebra often involves understanding how to leverage different methods, such as these, to move from known information to unknown quantities, thus unveiling the solution.

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