Chapter 16: Problem 59
Explain why the equation \((x-2)^{2}=-4\) does not have a real number solution.
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Chapter 16: Problem 59
Explain why the equation \((x-2)^{2}=-4\) does not have a real number solution.
These are the key concepts you need to understand to accurately answer the question.
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What number is equal to three less than its square?
The length of a rectangle is \(4 \mathrm{ft}\) more than twice the width. The area of the rectangle is \(160 \mathrm{ft}^{2}\). Find the length and width of the rectangle.
Find the radius of a right circular cone that has a volume of \(800 \mathrm{cm}^{3}\) and a height of \(12 \mathrm{cm} .\) Round to the nearest hundredth. (figure not copy)
For a quadratic equation of the form \(x^{2}+b x+c=0,\) the sum of the solutions is equal to the opposite of \(b\), and the product of the solutions is equal to \(c .\) For example, the solutions of the equation \(x^{2}+5 x+6=0\) are \(-2\) and \(-3 .\) The sum of the solutions is \(-5,\) the opposite of the coefficient of \(x\). The product of the solutions is \(6,\) the constant term. This is one way to check the solutions of a quadratic equation. Use this method to determine whether the given numbers are solutions of the equation. If they are not solutions of the equation, find the solutions. $$x^{2}-4 x-21=0 ;-3 \text { and } 7$$
For Exercises 50 to \(53,\) solve by completing the square. Approximate the solutions to the nearest thousandth. $$2 x^{2}+3 x=11$$
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