/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 For Exercises 7 to \(47,\) solve... [FREE SOLUTION] | 91Ó°ÊÓ

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For Exercises 7 to \(47,\) solve by completing the square. $$6 z^{2}=z+2$$

Short Answer

Expert verified
The solutions of the given equation are \(z = \frac{1}{6} ± \sqrt{\frac{7}{12}}\).

Step by step solution

01

Identify a, b and c

In the equation '6z\(^{2}\') = z + 2', 'a' is the coefficient of z\(^{2}\'), which is 6. 'b' is the coefficient of z, which is -1 (when moved to the left side), and 'c' is the constant, which is -2 (when shifted to the left).
02

Re-arrange the Equation into quadratic form

By shifting 'z' and '2' to the left side of the equation, we get the quadratic form of the equations: \[6z^{2} -z - 2=0\] This equation represents the form 'az\(^{2}\')+bz+c=0'.
03

Solve by Completing the Square

We can divide the equation by the coefficient of z\(^{2}\'), which is 6, to make the coefficient of z\(^{2}\') 1: \[(z - \frac{1}{6})^{2} - \frac{1}{4} - \frac{2}{6}=0.\] This equation can be simplified further to: \[(z- \frac{1}{6})^{2} = \frac{1}{4} + \frac{1}{3},\] This simplifies to \[(z- \frac{1}{6})^{2} = \frac{7}{12}.\] Taking square root on both sides, we get: \[z- \frac{1}{6} = ± \sqrt{\frac{7}{12}}.\] Solving for z gives the roots of the quadratic equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equations
Quadratic equations are fundamental in algebra and appear in various forms, typically as \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants, and \(a \eq 0\). These equations are called 'quadratic' because the term 'quad' suggests squaring, and the highest power of the variable \(x\) is 2. They can be solved using several methods, including factoring, using the quadratic formula, or completing the square.

Completing the square is an algebraic technique that transforms a quadratic equation into a perfect square trinomial, which is easier to solve. For the equation given in the exercise, \(6z^2 = z + 2\), completing the square involves moving all terms except the \(z^2\) term to the opposite side of the equation, factoring out the coefficient of the \(z^2\) term to set the stage for creating a perfect square. By doing so, solutions for \(z\) can be found more straightforwardly, as demonstrated in the exercise solution.
Algebraic Methods
Algebra is filled with various methods to solve equations, and among the most important are those used to solve quadratic equations. Algebraic methods rely on manipulating equations in systematic ways to find their solutions. Completing the square is one such method that may initially seem less intuitive than others, but it becomes very useful, especially when equations do not factor easily or when applying the quadratic formula is not practical.

The process requires several steps, including rearranging terms, creating a perfect square on one side, and taking the square root of both sides. These steps help isolate the variable, leading to a solution. Understanding each step conceptually is crucial, as missteps can lead to incorrect solutions. When solving by completing the square, it is also essential to maintain balance in the equation by performing operations equally on both sides.
Prealgebra Concepts
Prealgebra lays the groundwork for understanding algebraic concepts, such as the notion of variables, constants, and the idea of an equation representing a balance between two expressions. It teaches the properties of arithmetic operations and their role in transforming equations and introduces the concept of solving for an unknown. In the context of solving quadratic equations, prealgebraic concepts remind us to combine like terms, move terms across the equals sign by using inverse operations, and closely observe signs and coefficients as they shift sides.

With a firm grasp of prealgebra, students can navigate the steps required to complete the square with greater ease. Recognizing that \(ax^2 + bx + c = 0\) is an equation that can be balanced and manipulated paves the way for algebraic methods that lead to the finding of \(x\). Completing the square serves as an excellent bridge between prealgebra understating and more complex algebraic problem-solving.

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Most popular questions from this chapter

For a quadratic equation of the form \(x^{2}+b x+c=0,\) the sum of the solutions is equal to the opposite of \(b\), and the product of the solutions is equal to \(c .\) For example, the solutions of the equation \(x^{2}+5 x+6=0\) are \(-2\) and \(-3 .\) The sum of the solutions is \(-5,\) the opposite of the coefficient of \(x\). The product of the solutions is \(6,\) the constant term. This is one way to check the solutions of a quadratic equation. Use this method to determine whether the given numbers are solutions of the equation. If they are not solutions of the equation, find the solutions. $$x^{2}-4 x+1=0 ; 2+\sqrt{3} \text { and } 2-\sqrt{3}$$

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