Chapter 16: Problem 11
Solve by using the quadratic formula. $$w^{2}+3 w+5=0$$
Short Answer
Expert verified
The equation \(w^{2}+3w+5=0\) has no real solutions.
Step by step solution
01
Identify a, b, and c
From the equation \(w^2+3w+5=0\), we can identify that \(a=1\), \(b=3\), and \(c=5\). These are the coefficients of the square term, the linear term, and the constant term, respectively.
02
Substitute in the Quadratic Formula
Substitute \(a=1\), \(b=3\), and \(c=5\) into the quadratic formula:\[w = \frac{-b ± \sqrt{b^2-4ac}}{2a} = \frac{-3 ± \sqrt{3^2-4*1*5}}{2*1}\]
03
Simplify the Equation
Simplify the equation to get \(w = \frac{-3 ± \sqrt{9-20}}{2}\). However, we can't take the square root of a negative number (-11 in this case), which means the equation has no real solutions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coefficients
In a quadratic equation, the term 'coefficients' refers to the numbers that are multiplied by the variables. For example, in the equation \(w^2 + 3w + 5 = 0\), the coefficients are critical because they help in forming the quadratic equation. This equation is in the standard form \(ax^2 + bx + c = 0\) where:
Understanding coefficients will also help you manipulate and rearrange other polynomial equations. This forms the basis for solving various mathematical problems efficiently.
- \(a\) is the coefficient of the quadratic term \(w^2\) (here, \(a=1\))
- \(b\) is the coefficient of the linear term \(w\) (here, \(b=3\))
- \(c\) is the constant term (here, \(c=5\))
Understanding coefficients will also help you manipulate and rearrange other polynomial equations. This forms the basis for solving various mathematical problems efficiently.
Quadratic Equation
A quadratic equation is a polynomial equation of the second degree, typically in the form \(ax^2 + bx + c = 0\). The standard form ensures that you are always working with an equation where the highest power of the variable is squared (\(x^2\)).
To solve a quadratic equation like \(w^2 + 3w + 5 = 0\), one common method used is the quadratic formula:\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]This formula allows you to find the solutions of the quadratic equation: often referred to as the 'roots' of the equation.
In our example, substituting the values \(a=1\), \(b=3\), and \(c=5\) in the quadratic formula helps us derive the possible values of \(w\). It is a reliable technique especially when factoring isn't feasible or straightforward.
To solve a quadratic equation like \(w^2 + 3w + 5 = 0\), one common method used is the quadratic formula:\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]This formula allows you to find the solutions of the quadratic equation: often referred to as the 'roots' of the equation.
In our example, substituting the values \(a=1\), \(b=3\), and \(c=5\) in the quadratic formula helps us derive the possible values of \(w\). It is a reliable technique especially when factoring isn't feasible or straightforward.
- The \(\pm\) symbol indicates that you need to perform the calculation twice: once with a plus and once with a minus sign, which potentially gives two solutions.
- If the discriminant \((b^2 - 4ac)\) is negative, as it is in this case \( (9-20=-11)\), then the equation has complex roots rather than real ones.
- When the discriminant is zero, the quadratic equation has one real solution.
- If the discriminant is positive, the equation has two distinct real solutions.
Complex Numbers
Complex numbers extend the real number system. A complex number is typically expressed in the form \(a + bi\), where \(a\) and \(b\) are real numbers and \(i\) is the imaginary unit, satisfying \(i^2 = -1\).
In the process of solving the quadratic equation \(w^2 + 3w + 5 = 0\) using the quadratic formula, we encountered the issue of finding the square root of a negative number \((-11)\). This leads us to the use of complex numbers since real numbers cannot satisfy this need.
The imaginary unit \(i\) provides a way to work with such roots. In this example:
In the process of solving the quadratic equation \(w^2 + 3w + 5 = 0\) using the quadratic formula, we encountered the issue of finding the square root of a negative number \((-11)\). This leads us to the use of complex numbers since real numbers cannot satisfy this need.
The imaginary unit \(i\) provides a way to work with such roots. In this example:
- The discriminant \(b^2 - 4ac\) was \(-11\), indicating the lack of real solutions.
- This can be expressed as \( \sqrt{-11} = \sqrt{11}i\), introducing the imaginary component.
- Therefore, the solutions of the equation are complex and can be noted as \( -\frac{3}{2} \pm \frac{\sqrt{11}}{2}i \).