/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Simplify. $$\frac{x^{2}-3 x}{2... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Simplify. $$\frac{x^{2}-3 x}{2 x-6}$$

Short Answer

Expert verified
The simplified form of the given algebraic expression is \(x/2\).

Step by step solution

01

Factorize the Expressions

First, take a look at the numerator \(x^{2}-3 x\). Notice that there's a common factor, \(x\), that can be factored out: \(x * (x - 3)\) Next, look at the denominator, \(2x - 6\), we can also factor out the common factor, \(2\): \(2 * (x - 3)\)
02

Simplify by Cancelling Out

Now comes the simplification part. We can see that the factor \((x - 3)\) is common in both the numerator and the denominator. So we can cancel out this common factor: \(x * (x - 3) / 2 * (x - 3)\) After cancelling out \((x - 3)\), the simplified form of the given expression becomes: \(x / 2\)
03

Provide the Simplified Expression

Therefore, the simplified form of the given algebraic expression \(\frac{x^{2}-3x}{2x-6}\) is \(x/2\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Expressions
Factoring is an important foundational skill in algebra that helps in simplifying expressions by breaking them down into their basic building blocks or "factors." When you factor an expression, you look for terms that have something in common and pull them out. For example, in the expression \(x^2 - 3x\), notice that both terms contain the variable \(x\). By taking \(x\) out as a common factor, you rewrite it as \(x(x - 3)\). Similarly, for the expression \(2x - 6\), both terms are divisible by \(2\), so you can factor \(2\) out, resulting in \(2(x - 3)\).
Understanding factoring is essential as it can make complex algebraic expressions easier to handle, paving the way for further simplification.
Canceling Common Factors
Canceling common factors is a key step when simplifying rational expressions, as it helps condense the expression to its simplest form. After factoring both the numerator and denominator, identify any identical factors that appear above and below the fraction line. In our example, after factoring the expressions, both the numerator \(x(x - 3)\) and the denominator \(2(x - 3)\) contain the common factor \((x - 3)\).
By canceling or "crossing out" this common factor, we effectively simplify the fraction, making the expression less complex. In this particular exercise, canceling \((x - 3)\) leaves us with the simplified expression \(\frac{x}{2}\). Always remember that you can only cancel factors, not individual terms, ensuring that the value of the expression remains unchanged.
Rational Expressions
Rational expressions are fractions where both the numerator and the denominator are polynomials. Simplifying these expressions involves similar steps to simplifying regular fractions. The core idea is to reduce the expression to its lowest terms by factoring and canceling common factors.
Algebraically, rational expressions offer many interesting problems and solutions. However, they may sometimes look daunting. Breaking them down to recognize patterns and delve into step-by-step simplification, just like fractions, helps strongly in understanding. The exercise illustrates this process perfectly: it begins with \(\frac{x^2 - 3x}{2x - 6}\) and simplifies to \(\frac{x}{2}\) by highlighting common factors. This process not only simplifies the problem but also teaches important algebraic techniques useful in advanced mathematics.
Prealgebra Skills
While this exercise focuses on algebraic concepts, the skills you develop in prealgebra are just as vital. These foundational skills include basic arithmetic operations, understanding of factors and multiples, pre-algebraic manipulations, and recognizing patterns.
Prealgebra skills provide the toolkit for handling algebraic problems with ease. Recognizing common factors, understanding how to distribute and how to effectively cancel, all stem from solid prealgebra foundations. With these skills, you learn to break down complex instructions and see the logic behind each step. The entire process, from factoring \(x^2 - 3x\) and \(2x - 6\), to canceling \((x - 3)\), builds upon what you learn in prealgebra, preparing you for tackling more challenging algebraic expressions and equations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

After sailing \(15 \mathrm{mi}\), a sailor changed direction and increased the boat's speed by 2 mph. An additional 19 mi was sailed at the increased speed. The total sailing time was \(4 \mathrm{h}\). Find the rate of the boat for the first \(15 \mathrm{mi}\).

To assess the damage done by a fire, a forest ranger traveled 1080 mi by jet and then an additional 180 mi by helicopter. The rate of the jet was four times the rate of the helicopter. The entire trip took \(5 \mathrm{h}\). Find the rate of the jet.

A small motor on a fishing boat can move the boat at a rate of \(6 \mathrm{mph}\) in calm water. Traveling with the current, the boat can travel \(24 \mathrm{mi}\) in the same amount of time it takes to travel 12 mi against the current. Find the rate of the current.

A camper drove 80 mi to a recreational area and then hiked 4 mi into the woods. The rate of the camper while driving was ten times the rate while hiking. The total time spent hiking and driving was 3 h. Find the rate at which the camper hiked.

Suppose that you drive about \(12,000 \mathrm{mi}\) per year and that the cost of gasoline averages 3.70 dollar per gallon. a. Let \(x\) represent the number of miles per gallon your car gets. Write a variable expression for the amount you spend on gasoline in one year. b. Write and simplify a variable expression for the amount of money you will save each year if you increase your gas mileage by 5 miles per gallon. c. If you currently get 25 miles per gallon and you increase your gas mileage by 5 miles per gallon, how much will you save in one year?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.